自动化专业英语Chapter41b.docx

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自动化专业英语Chapter41b.docx

自动化专业英语Chapter41b

Chapter4Response—ClassicalMethod

4-1INRODUCTION

Havingrepresentedcontrolsystemsusingblockdiagramsaswellasstatevariables,weturnourattentiontosystemresponse,i.e.howdoesasystemrespondasafunctionoftimewhensubjectedtovarioustypesofstimuli?

Hereweareinterestedinthesystemoutputwithoutregardtothebehaviorofvariablesinsidethecontrolsystem.Whenthisisthecase,wecanworkwiththesystemtransferfunction.IfwedesireC(s)wecanworkwithC(s)/R(s)andspecifyR(s)andobtaintheoutput.Ontheotherhand,ifweneedE(s)weshouldworkwithE(s)/R(s)andspecifyR(s).Inanyeventitisimportanttorecognizethatwhentheresponsetoasingleinputisrequiredwithoutregardtothebehaviorofvariablesinsideacontrolsystem,wespeakofapplyingtheclassicalapproach.Thiscanbemostreadilyachievedbyemployingtechniques.Thistechniqueinvolvesrepresentingtheoutput(ordesiredvariable)astheratiooftwopolynomialsandthenexpandingtheexpressioninpartialfractions.Theconstantsofthepartialfractionarecalculatedbytheresiduetheorem.TheoutputinthetimedomainistheobtainedbytakingtheinverseLaplacetransform.AdetaileddiscussionofLaplacetransformsisgiveninAppendixAandshouldbereviewedbythosethatdonothaveagoodworkingknowledgeintheuseofLaplacetransforms.

Ingeneral,theinputexcitationtoacontrolsystemisnotknownaheadoftime.However,forpurposesofanalysisitisnecessarythatweassumesomesimpletypesofexcitationandobtainsystemresponsetoatleastthesetypesofsignals.Ingeneral,therearethreetypes*ofexcitationsusedinobtainingtheresponseoflinearfeedbackcontrolsystems.Theyarethestepinput,rampinput,andtheparabolicinput.Thesearetypicaltestorreferenceinputs.Inpractice,theinputisgenerallyneverexactlyspecifiable.

Stepinput

Astepinputconsistsofasuddenchangeofreferenceinputatt=0.Mathematicallyitis

ThefunctionshowninFig.4-1aisnotdefinedfort=0.TheLaplacetransformofthestepinputisA/s.

RampInput(StepVelocity)

Arampinputisaconstantvelocityandisrepresentedas

ThefunctionisshowninFig.4-1bandhasaLaplacetransformofA/s2.

ParabolicInput(StepAcceleration)

Inthiscasetheinputisaconstantacceleration,

*Inmanycontrolsystemstheinputmaybeasinusoidallyvaryingsignal.Whenthisisso,andweknowthesystemislinear,thentheoutputalsoconsistsofasinusoidallyvaryingsignalbuthavingadifferentmagnitudeandaphaseshiftwhichmaybefunctionsoftheinputfrequency.Weshallconsiderthisinmoredetailinalaterchapter.

ThefunctionisshowninFig.4-1candhasaLaplacetransformof2A/s3.

Fig.4-1Threetestsignalsforlinearfeedbackcontrolsystems

 

Instudyingthesystemresponseofafeedbackcontrolsystemtherearethreethingswewishtoknow,viz.thetransientresponse,thesteadystateorforcedresponse,andthestabilityofthesystem.Thetransientsolutionyieldsinformationonhowmuchthesystemdeviatesfromtheinputandthetimenecessaryforthesystemresponsetosettletowithincertainlimits.Thesteadystateorforcedresponsegivesanindicationoftheaccuracyofthesystem.Wheneverthesteadystateoutputdoesnotagreewiththeinput,thesystemissaidtohaveasteadystateerror.Bystabilitywemeanthattheoutputdoesnotgetuncontrollablylarge.

4-2TRANSIENTRESPONSE

ConsideraclosedloopsystemshowninFig.4-2.Theoutputandtheerrortransferfunctionsare

(4-1a)

(4-1b)

 

 

Thetransientresponseofthesystem,beittheerrorEortheoutputC,dependsupontheroots(alsocalledzeros)ofthecharacteristicequation

(4-2)

ThezerosofthecharacteristicequationarealsothepolesofthetransferfunctionsgivenbyEqs.(4-1a)and(4-1b).Thesepolesareknownastheclosedlooppoles.Itisinterestingtonotethatthetransientresponsedoesnotdependuponthekindofinputbutdependsonlyonthezerosofthecharacteristicequation.Nowiftheforwardandfeedbacktransferfunctionsaredefinedas

;

thenthecharacteristicequationbecomes

andthezerosareobtainedfrom

whichcorrespondtothepolesof

Theright-handsideoftheaboveequationisaratiooftwopolynomialswherethedegreeofthedenominatorisequaltoorhigherthantheorderofthenumerator.Letusassumethatthedegreeofthedenominatorisnandofthenumeratorisv,thenifwefactorizeEq.(4-1a)itcanbewrittenas

(4-3)

Notethatwebeganwiththesystemtransferfunctiontoobtainthisexpression.Itisperhapsinterestingtoobservethathadwebegunwithastaterepresentation,then

whichwouldhavebeenfactoredtoobtaintheright-handsideofEq.(4-3).Whenweareinterestedonlyinthesystemtransientsweneednotbeconcernedwiththeformoftheinputsincethetransientsareafunctionofonlythecharacteristicroots.ItisthereforeconvenienttosetR(s)=1.(SinceR(s)=1whenr(t)isanimpulse,itfollowsthatthetransientsmaybeobtainedbyapplyinganimpulsetotheinputofasystem.)Whentheinputisincluded,thetransientswillnotonlyincludetheresponseduetothecharacteristicroots,buttermsintheimageoftheinputanditsderivatives.Onlythesetermswillsurviveast→∞andyieldthesteadystateperformance.Forobtainingthetotaltransientresponsewewillincludetheinputterm.

ReturningnowtoEq.(4-3)wenowassumethattheinputr(t)isaunitstep,thenR(s)=1/sandtheoutputbecomes

(4-4)

Letusnowassumethatofthendistinctpoles,2kpolesarecomplex*andtheremainingpolesarereal.IfwedenotetheconjugateofsmandKmby

and

thenEq.(4-4)maybeexpandedinpartialfractionsandwrittenas

(4-5)

*Complexpolesappearasconjugates.

where

Ifwedenotesm=-

thentheoutputinthetimedomainisobtainedbytakingtheinverseLaplacetransformofEq.(4-5),

(4-6)

where

isthephasecontributionoftheconstantKm.NoticethesecondtermofEq.(4-6)isobtainedbycombiningtwoterms.

IfC(s)hasmpolesthatareequal(i.e.repeat),then

(4-7)

where

and

(4-8)

where

goesfrom1tom.Ingeneral,theresponseofasystemcontainstermsofthetypegiveninEq.(4-6)aswellasEq.(4-8).

Theimportantfacthereisthattheformofthetransientresponseisafunctionofthelocationoftheclosedlooppoles,whichareidenticaltothezerosofthecharacteristicequation,onthes-plane.

Forreal,simplepolesthetimeresponseissimplyanexponentialwhichdecaysifthepoleisinthelefthalfs-planeandincreaseswithtimeifthepoleisintherighthalfs-plane.Therateofthisdecayorincreaseisdependentuponthemagnitudeofpole.Polesclosertotheimaginaryaxisarereferredtoasdominantpolessincethedecayduetothemtakeslonger.

Forcomplexpolestheresponseisoscillatorywiththemagnitudevaryingexponentiallywithtime.Again,iftherealpartisinthelefthalfs-plane,themagnitudedecreaseswithtime.Iftherealpartispositive,thenthemagnitudeincreasesexponentiallywithtime.

Finally,ifthepolesarerealandofmultiplicitym,thenthetimeresponseisoftheform

.Wehavenotshowntheresponseifthepolesaremultipleandcomplex.Itisleftforyoutoshowthatforcomplexmultiplepolestheresponseisoftheform

OurideasofthissectionareconsolidatedandshowngraphicallyinFig.4-3.Wenotethatforwell-behavedsystems,i.e.systemsexhibitingastableresponse,itisreasonabletorequirethattheclosedlooppolesofthecontrolsystembelocatedinthelefthalfs-plane.Ifthepolesexistontheimaginaryaxistheymustbesimple.Otherwise,thecontrolsystemrespondsinsuchawaythatthemagnitudeoftheoutputbecomesuncontrollablylarge.

Fig.4-3Transientresponseasafunctionoftheclosedlooppolesonthes-plane.

 

EXAMPLE4-1

TheforwardloopofaunityfeedbackcontrolsystemisgivenbyG(s)=K/s(s2+19s+118).Obtaine(t)ifK=240andtheinputisr(t)=t.

ForK=240andr(t)=t

Expandingthisinpartialfractionsweobtain

wheres1=0,s2=-5,s3=-6ands4=-8.Nowweevaluatetheconstants,

TheinverseLaplacetransformyields

EXAMPLE4-2

TheforwardloopofaunityfeedbackcontrolsystemisgivenbyG(s)=K/s(s+6).ItisdesiredtovaryKfrom8to13forthecaseofaunitystepinput.ObtaintheoutputforK=8and13anddeterminethevalueofKabovewhichthesystemexhibitsoscillatorybehavior.

Theoveralltransferfunctionisgivenby

SubstitutingforG(s)andsimplifyingyields

Therootsofthedenominatorares1ands2where

ForK

9therootsarerealandforK>9therootsarecomplex.ThesystemthereforewillexhibitoscillationsforK>9.(Seenextexample.)WhenK=8therootsbecome

s1=-2,s2=-4

andforastepinput

Theconstantsare

TheoutputforK=8becomes

C(t)=1-2e-2t+e-4t

WhenK=13therootsbecome

s1=-3+j2,s2=-3–j2

andforastepinput

Theconstantsbecome

WenotethatK2isthecomplexconjugateofK3.Whenevertherootsarecomplexconjugateswewillfindthattheconstantsarealsocomplexconjugates.TheoutputforK=13becomes

Notingthat

Theoutputisseentohaveanexponentiallydampedoscillatorytermsuperimposedonaconstantterm.

EXAMPLE4-3

ObtaintheoutputforK=9forthesystemdescribedinExample4-2.Assumetheinputisaunitstep.

ForK=9,theoveralltransferfunctionbecomes

Sincewehaverepeatedrootsthepartialfractionexpansionbecomes

The

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