自动化专业英语Chapter41b.docx
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自动化专业英语Chapter41b
Chapter4Response—ClassicalMethod
4-1INRODUCTION
Havingrepresentedcontrolsystemsusingblockdiagramsaswellasstatevariables,weturnourattentiontosystemresponse,i.e.howdoesasystemrespondasafunctionoftimewhensubjectedtovarioustypesofstimuli?
Hereweareinterestedinthesystemoutputwithoutregardtothebehaviorofvariablesinsidethecontrolsystem.Whenthisisthecase,wecanworkwiththesystemtransferfunction.IfwedesireC(s)wecanworkwithC(s)/R(s)andspecifyR(s)andobtaintheoutput.Ontheotherhand,ifweneedE(s)weshouldworkwithE(s)/R(s)andspecifyR(s).Inanyeventitisimportanttorecognizethatwhentheresponsetoasingleinputisrequiredwithoutregardtothebehaviorofvariablesinsideacontrolsystem,wespeakofapplyingtheclassicalapproach.Thiscanbemostreadilyachievedbyemployingtechniques.Thistechniqueinvolvesrepresentingtheoutput(ordesiredvariable)astheratiooftwopolynomialsandthenexpandingtheexpressioninpartialfractions.Theconstantsofthepartialfractionarecalculatedbytheresiduetheorem.TheoutputinthetimedomainistheobtainedbytakingtheinverseLaplacetransform.AdetaileddiscussionofLaplacetransformsisgiveninAppendixAandshouldbereviewedbythosethatdonothaveagoodworkingknowledgeintheuseofLaplacetransforms.
Ingeneral,theinputexcitationtoacontrolsystemisnotknownaheadoftime.However,forpurposesofanalysisitisnecessarythatweassumesomesimpletypesofexcitationandobtainsystemresponsetoatleastthesetypesofsignals.Ingeneral,therearethreetypes*ofexcitationsusedinobtainingtheresponseoflinearfeedbackcontrolsystems.Theyarethestepinput,rampinput,andtheparabolicinput.Thesearetypicaltestorreferenceinputs.Inpractice,theinputisgenerallyneverexactlyspecifiable.
Stepinput
Astepinputconsistsofasuddenchangeofreferenceinputatt=0.Mathematicallyitis
ThefunctionshowninFig.4-1aisnotdefinedfort=0.TheLaplacetransformofthestepinputisA/s.
RampInput(StepVelocity)
Arampinputisaconstantvelocityandisrepresentedas
ThefunctionisshowninFig.4-1bandhasaLaplacetransformofA/s2.
ParabolicInput(StepAcceleration)
Inthiscasetheinputisaconstantacceleration,
*Inmanycontrolsystemstheinputmaybeasinusoidallyvaryingsignal.Whenthisisso,andweknowthesystemislinear,thentheoutputalsoconsistsofasinusoidallyvaryingsignalbuthavingadifferentmagnitudeandaphaseshiftwhichmaybefunctionsoftheinputfrequency.Weshallconsiderthisinmoredetailinalaterchapter.
ThefunctionisshowninFig.4-1candhasaLaplacetransformof2A/s3.
Fig.4-1Threetestsignalsforlinearfeedbackcontrolsystems
Instudyingthesystemresponseofafeedbackcontrolsystemtherearethreethingswewishtoknow,viz.thetransientresponse,thesteadystateorforcedresponse,andthestabilityofthesystem.Thetransientsolutionyieldsinformationonhowmuchthesystemdeviatesfromtheinputandthetimenecessaryforthesystemresponsetosettletowithincertainlimits.Thesteadystateorforcedresponsegivesanindicationoftheaccuracyofthesystem.Wheneverthesteadystateoutputdoesnotagreewiththeinput,thesystemissaidtohaveasteadystateerror.Bystabilitywemeanthattheoutputdoesnotgetuncontrollablylarge.
4-2TRANSIENTRESPONSE
ConsideraclosedloopsystemshowninFig.4-2.Theoutputandtheerrortransferfunctionsare
(4-1a)
(4-1b)
Thetransientresponseofthesystem,beittheerrorEortheoutputC,dependsupontheroots(alsocalledzeros)ofthecharacteristicequation
(4-2)
ThezerosofthecharacteristicequationarealsothepolesofthetransferfunctionsgivenbyEqs.(4-1a)and(4-1b).Thesepolesareknownastheclosedlooppoles.Itisinterestingtonotethatthetransientresponsedoesnotdependuponthekindofinputbutdependsonlyonthezerosofthecharacteristicequation.Nowiftheforwardandfeedbacktransferfunctionsaredefinedas
;
thenthecharacteristicequationbecomes
andthezerosareobtainedfrom
whichcorrespondtothepolesof
Theright-handsideoftheaboveequationisaratiooftwopolynomialswherethedegreeofthedenominatorisequaltoorhigherthantheorderofthenumerator.Letusassumethatthedegreeofthedenominatorisnandofthenumeratorisv,thenifwefactorizeEq.(4-1a)itcanbewrittenas
(4-3)
Notethatwebeganwiththesystemtransferfunctiontoobtainthisexpression.Itisperhapsinterestingtoobservethathadwebegunwithastaterepresentation,then
whichwouldhavebeenfactoredtoobtaintheright-handsideofEq.(4-3).Whenweareinterestedonlyinthesystemtransientsweneednotbeconcernedwiththeformoftheinputsincethetransientsareafunctionofonlythecharacteristicroots.ItisthereforeconvenienttosetR(s)=1.(SinceR(s)=1whenr(t)isanimpulse,itfollowsthatthetransientsmaybeobtainedbyapplyinganimpulsetotheinputofasystem.)Whentheinputisincluded,thetransientswillnotonlyincludetheresponseduetothecharacteristicroots,buttermsintheimageoftheinputanditsderivatives.Onlythesetermswillsurviveast→∞andyieldthesteadystateperformance.Forobtainingthetotaltransientresponsewewillincludetheinputterm.
ReturningnowtoEq.(4-3)wenowassumethattheinputr(t)isaunitstep,thenR(s)=1/sandtheoutputbecomes
(4-4)
Letusnowassumethatofthendistinctpoles,2kpolesarecomplex*andtheremainingpolesarereal.IfwedenotetheconjugateofsmandKmby
and
thenEq.(4-4)maybeexpandedinpartialfractionsandwrittenas
(4-5)
*Complexpolesappearasconjugates.
where
Ifwedenotesm=-
thentheoutputinthetimedomainisobtainedbytakingtheinverseLaplacetransformofEq.(4-5),
(4-6)
where
isthephasecontributionoftheconstantKm.NoticethesecondtermofEq.(4-6)isobtainedbycombiningtwoterms.
IfC(s)hasmpolesthatareequal(i.e.repeat),then
(4-7)
where
and
(4-8)
where
goesfrom1tom.Ingeneral,theresponseofasystemcontainstermsofthetypegiveninEq.(4-6)aswellasEq.(4-8).
Theimportantfacthereisthattheformofthetransientresponseisafunctionofthelocationoftheclosedlooppoles,whichareidenticaltothezerosofthecharacteristicequation,onthes-plane.
Forreal,simplepolesthetimeresponseissimplyanexponentialwhichdecaysifthepoleisinthelefthalfs-planeandincreaseswithtimeifthepoleisintherighthalfs-plane.Therateofthisdecayorincreaseisdependentuponthemagnitudeofpole.Polesclosertotheimaginaryaxisarereferredtoasdominantpolessincethedecayduetothemtakeslonger.
Forcomplexpolestheresponseisoscillatorywiththemagnitudevaryingexponentiallywithtime.Again,iftherealpartisinthelefthalfs-plane,themagnitudedecreaseswithtime.Iftherealpartispositive,thenthemagnitudeincreasesexponentiallywithtime.
Finally,ifthepolesarerealandofmultiplicitym,thenthetimeresponseisoftheform
.Wehavenotshowntheresponseifthepolesaremultipleandcomplex.Itisleftforyoutoshowthatforcomplexmultiplepolestheresponseisoftheform
OurideasofthissectionareconsolidatedandshowngraphicallyinFig.4-3.Wenotethatforwell-behavedsystems,i.e.systemsexhibitingastableresponse,itisreasonabletorequirethattheclosedlooppolesofthecontrolsystembelocatedinthelefthalfs-plane.Ifthepolesexistontheimaginaryaxistheymustbesimple.Otherwise,thecontrolsystemrespondsinsuchawaythatthemagnitudeoftheoutputbecomesuncontrollablylarge.
Fig.4-3Transientresponseasafunctionoftheclosedlooppolesonthes-plane.
EXAMPLE4-1
TheforwardloopofaunityfeedbackcontrolsystemisgivenbyG(s)=K/s(s2+19s+118).Obtaine(t)ifK=240andtheinputisr(t)=t.
ForK=240andr(t)=t
Expandingthisinpartialfractionsweobtain
wheres1=0,s2=-5,s3=-6ands4=-8.Nowweevaluatetheconstants,
TheinverseLaplacetransformyields
EXAMPLE4-2
TheforwardloopofaunityfeedbackcontrolsystemisgivenbyG(s)=K/s(s+6).ItisdesiredtovaryKfrom8to13forthecaseofaunitystepinput.ObtaintheoutputforK=8and13anddeterminethevalueofKabovewhichthesystemexhibitsoscillatorybehavior.
Theoveralltransferfunctionisgivenby
SubstitutingforG(s)andsimplifyingyields
Therootsofthedenominatorares1ands2where
ForK
9therootsarerealandforK>9therootsarecomplex.ThesystemthereforewillexhibitoscillationsforK>9.(Seenextexample.)WhenK=8therootsbecome
s1=-2,s2=-4
andforastepinput
Theconstantsare
TheoutputforK=8becomes
C(t)=1-2e-2t+e-4t
WhenK=13therootsbecome
s1=-3+j2,s2=-3–j2
andforastepinput
Theconstantsbecome
WenotethatK2isthecomplexconjugateofK3.Whenevertherootsarecomplexconjugateswewillfindthattheconstantsarealsocomplexconjugates.TheoutputforK=13becomes
Notingthat
Theoutputisseentohaveanexponentiallydampedoscillatorytermsuperimposedonaconstantterm.
EXAMPLE4-3
ObtaintheoutputforK=9forthesystemdescribedinExample4-2.Assumetheinputisaunitstep.
ForK=9,theoveralltransferfunctionbecomes
Sincewehaverepeatedrootsthepartialfractionexpansionbecomes
The