经典c程序100例91100.docx

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经典c程序100例91100.docx

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经典c程序100例91100.docx

经典c程序100例91100

经典c程序100例==91--100

【程序91】

题目:

时间函数举例1

1.程序分析:

2.程序源代码:

#include"stdio.h"

#include"time.h"

voidmain()

{time_tlt;/*definealonginttimevarible*/

lt=time(NULL);/*systemtimeanddate*/

printf(ctime(<));/*englishformatoutput*/

printf(asctime(localtime(<)));/*tranfertotm*/

printf(asctime(gmtime(<)));/*tranfertoGreenwichtime*/

}

==============================================================

【程序92】

题目:

时间函数举例2

1.程序分析:

           

2.程序源代码:

/*calculatetime*/

#include"time.h"

#include"stdio.h"

main()

{time_tstart,end;

inti;

start=time(NULL);

for(i=0;i<3000;i++)

{printf("\1\1\1\1\1\1\1\1\1\1\n");}

end=time(NULL);

printf("\1:

Thedifferentis%6.3f\n",difftime(end,start));

}

==============================================================

【程序93】

题目:

时间函数举例3

1.程序分析:

2.程序源代码:

/*calculatetime*/

#include"time.h"

#include"stdio.h"

main()

{clock_tstart,end;

inti;

doublevar;

start=clock();

for(i=0;i<10000;i++)

{printf("\1\1\1\1\1\1\1\1\1\1\n");}

end=clock();

printf("\1:

Thedifferentis%6.3f\n",(double)(end-start));

}

==============================================================

【程序94】

题目:

时间函数举例4,一个猜数游戏,判断一个人反应快慢。

(版主初学时编的)

1.程序分析:

2.程序源代码:

#include"time.h"

#include"stdlib.h"

#include"stdio.h"

main()

{charc;

clock_tstart,end;

time_ta,b;

doublevar;

inti,guess;

srand(time(NULL));

printf("doyouwanttoplayit.('y'or'n')\n");

loop:

while((c=getchar())=='y')

{

i=rand()%100;

printf("\npleaseinputnumberyouguess:

\n");

start=clock();

a=time(NULL);

scanf("%d",&guess);

while(guess!

=i)

{if(guess>i)

{printf("pleaseinputalittlesmaller.\n");

scanf("%d",&guess);}

else

{printf("pleaseinputalittlebigger.\n");

scanf("%d",&guess);}

}

end=clock();

b=time(NULL);

printf("\1:

Ittookyou%6.3fseconds\n",var=(double)(end-start)/18.2);

printf("\1:

ittookyou%6.3fseconds\n\n",difftime(b,a));

if(var<15)

printf("\1\1Youareveryclever!

\1\1\n\n");

elseif(var<25)

printf("\1\1youarenormal!

\1\1\n\n");

else

printf("\1\1youarestupid!

\1\1\n\n");

printf("\1\1Congradulations\1\1\n\n");

printf("Thenumberyouguessis%d",i);

}

printf("\ndoyouwanttotryitagain?

(\"yy\".or.\"n\")\n");

if((c=getch())=='y')

gotoloop;

}

==============================================================

【程序95】

题目:

家庭财务管理小程序

1.程序分析:

2.程序源代码:

/*moneymanagementsystem*/

#include"stdio.h"

#include"dos.h"

main()

{

FILE*fp;

structdated;

floatsum,chm=0.0;

intlen,i,j=0;

intc;

charch[4]="",ch1[16]="",chtime[12]="",chshop[16],chmoney[8];

pp:

clrscr();

sum=0.0;

gotoxy(1,1);printf("|---------------------------------------------------------------------------|");

gotoxy(1,2);printf("|moneymanagementsystem(C1.0)2000.03|");

gotoxy(1,3);printf("|---------------------------------------------------------------------------|");

gotoxy(1,4);printf("|--moneyrecords--|--todaycostlist--|");

gotoxy(1,5);printf("|------------------------|-------------------------------------|");

gotoxy(1,6);printf("|date:

--------------||");

gotoxy(1,7);printf("|||||");

gotoxy(1,8);printf("|--------------||");

gotoxy(1,9);printf("|thgs:

------------------||");

gotoxy(1,10);printf("|||||");

gotoxy(1,11);printf("|------------------||");

gotoxy(1,12);printf("|cost:

----------||");

gotoxy(1,13);printf("|||||");

gotoxy(1,14);printf("|----------||");

gotoxy(1,15);printf("|||");

gotoxy(1,16);printf("|||");

gotoxy(1,17);printf("|||");

gotoxy(1,18);printf("|||");

gotoxy(1,19);printf("|||");

gotoxy(1,20);printf("|||");

gotoxy(1,21);printf("|||");

gotoxy(1,22);printf("|||");

gotoxy(1,23);printf("|---------------------------------------------------------------------------|");

i=0;

getdate(&d);

sprintf(chtime,"%4d.%02d.%02d",d.da_year,d.da_mon,d.da_day);

for(;;)

{

gotoxy(3,24);printf("Tab__browsecostlistEsc__quit");

gotoxy(13,10);printf("");

gotoxy(13,13);printf("");

gotoxy(13,7);printf("%s",chtime);

j=18;

ch[0]=getch();

if(ch[0]==27)

break;

strcpy(chshop,"");

strcpy(chmoney,"");

if(ch[0]==9)

{

mm:

i=0;

fp=fopen("home.dat","r+");

gotoxy(3,24);printf("");

gotoxy(6,4);printf("listrecords");

gotoxy(1,5);printf("|-------------------------------------|");

gotoxy(41,4);printf("");

gotoxy(41,5);printf("|");

while(fscanf(fp,"%10s%14s%f\n",chtime,chshop,&chm)!

=EOF)

{if(i==36)

{getch();

i=0;}

if((i%36)<17)

{gotoxy(4,6+i);

printf("");

gotoxy(4,6+i);}

else

if((i%36)>16)

{gotoxy(41,4+i-17);

printf("");

gotoxy(42,4+i-17);}

i++;

sum=sum+chm;

printf("%10s%-14s%6.1f\n",chtime,chshop,chm);}

gotoxy(1,23);printf("|---------------------------------------------------------------------------|");

gotoxy(1,24);printf("||");

gotoxy(1,25);printf("|---------------------------------------------------------------------------|");

gotoxy(10,24);printf("totalis%8.1f$",sum);

fclose(fp);

gotoxy(49,24);printf("pressanykeyto.....");getch();gotopp;

}

else

{

while(ch[0]!

='\r')

{if(j<10)

{strncat(chtime,ch,1);

j++;}

if(ch[0]==8)

{

len=strlen(chtime)-1;

if(j>15)

{len=len+1;j=11;}

strcpy(ch1,"");

j=j-2;

strncat(ch1,chtime,len);

strcpy(chtime,"");

strncat(chtime,ch1,len-1);

gotoxy(13,7);printf("");}

gotoxy(13,7);printf("%s",chtime);ch[0]=getch();

if(ch[0]==9)

gotomm;

if(ch[0]==27)

exit

(1);

}

gotoxy(3,24);printf("");

gotoxy(13,10);

j=0;

ch[0]=getch();

while(ch[0]!

='\r')

{if(j<14)

{strncat(chshop,ch,1);

j++;}

if(ch[0]==8)

{len=strlen(chshop)-1;

strcpy(ch1,"");

j=j-2;

strncat(ch1,chshop,len);

strcpy(chshop,"");

strncat(chshop,ch1,len-1);

gotoxy(13,10);printf("");}

gotoxy(13,10);printf("%s",chshop);ch[0]=getch();}

gotoxy(13,13);

j=0;

ch[0]=getch();

while(ch[0]!

='\r')

{if(j<6)

{strncat(chmoney,ch,1);

j++;}

if(ch[0]==8)

{len=strlen(chmoney)-1;

strcpy(ch1,"");

j=j-2;

strncat(ch1,chmoney,len);

strcpy(chmoney,"");

strncat(chmoney,ch1,len-1);

gotoxy(13,13);printf("");}

gotoxy(13,13);printf("%s",chmoney);ch[0]=getch();}

if((strlen(chshop)==0)||(strlen(chmoney)==0))

continue;

if((fp=fopen("home.dat","a+"))!

=NULL);

fprintf(fp,"%10s%14s%6s",chtime,chshop,chmoney);

fputc('\n',fp);

fclose(fp);

i++;

gotoxy(41,5+i);

printf("%10s%-14s%-6s",chtime,chshop,chmoney);

}}}

==============================================================

【程序96】

题目:

计算字符串中子串出现的次数

1.程序分析:

2.程序源代码:

#include"string.h"

#include"stdio.h"

main()

{charstr1[20],str2[20],*p1,*p2;

intsum=0;

printf("pleaseinputtwostrings\n");

scanf("%s%s",str1,str2);

p1=str1;p2=str2;

while(*p1!

='\0')

{

if(*p1==*p2)

{while(*p1==*p2&&*p2!

='\0')

{p1++;

p2++;}

}

else

p1++;

if(*p2=='\0')

sum++;

p2=str2;

}

printf("%d",sum);

getch();}

==============================================================

【程序97】

题目:

从键盘输入一些字符,逐个把它们送到磁盘上去,直到输入一个#为止。

1.程序分析:

     

2.程序源代码:

#include"stdio.h"

main()

{FILE*fp;

charch,filename[10];

scanf("%s",filename);

if((fp=fopen(filename,"w"))==NULL)

{printf("cannotopenfile\n");

exit(0);}

ch=getchar();

ch=getchar();

while(ch!

='#')

{fputc(ch,fp);putchar(ch);

ch=getchar();

}

fclose(fp);

}

==============================================================

【程序98】

题目:

从键盘输入一个字符串,将小写字母全部转换成大写字母,然后输出到一个磁盘文件“test”中保存。

   输入的字符串以!

结束。

1.程序分析:

2.程序源代码:

#include"stdio.h"

main()

{FILE*fp;

charstr[100],filename[10];

inti=0;

if((fp=fopen("test","w"))==NULL)

{printf("cannotopenthefile\n");

exit(0);}

printf("pleaseinputastring:

\n");

gets(str);

while(str[i]!

='!

')

{if(str[i]>='a'&&str[i]<='z')

str[i]=str[i]-32;

fputc(str[i],fp);

i++;}

fclose(fp);

fp=fopen("test","r");

fgets(str,strlen(str)+1,fp);

printf("%s\n",str);

fclose(fp);

}

==============================================================

【程序99】

题目:

有两个磁盘文件A和B,各存放一行字母,要求把这两个文件中的信息合并(按字母顺序排列),

   输出到一个新文件C中。

1.程序分析:

2.程序源代码:

#include"stdio.h"

main()

{FILE*fp;

inti,j,n,ni;

charc[160],t,ch;

if((fp=fopen("A","r"))==NULL)

{printf("fileAcannotbeopened\n");

exit(0);}

printf("\nAcontentsare:

\n");

for(i=0;(ch=fgetc(fp))!

=EOF;i++)

{c[i]=ch;

putchar(c[i]);

}

fclose(fp);

ni=i;

if((fp=fopen("B","r"))==NULL)

{printf("fileBcannotbeopened\n");

exit(0);}

printf("\nBcontentsare:

\n");

for(i=0;(ch=fgetc(fp))!

=EOF;i++)

{c[i]=ch;

putchar(c[i]);

}

fclose(fp);

n=i;

for(i=0;i

for(j=i+1;j

if(c[i]>c[j])

{t=c[i];c[i]=c[j];c[j]=t;}

printf("\nCfileis:

\n");

fp=fopen("C","w");

for(i=0;i

{putc(c[i],fp);

putchar(c[i]);

}

fclose(fp);

}

==============================================================

【程序100】

题目:

有五个学生,每个学生有3门课的成绩,从键盘输入以上数据(包括学生号,姓名,三门课成绩),计算出

   平均成绩,况原有的数据和计算出的平均分数存放在磁盘文件"stud"中。

1.程序分析:

2.程序源代码:

#include"stdio.h"

structstudent

{charnum[6];

charname[8];

intscore[3];

floatavr;

}stu[5];

main()

{inti,j,sum;

FILE*fp;

/*input*/

for(i=0;i<5;i++)

{printf("\npleaseinputNo.%dscore:

\n",i);

printf("stuNo:

");

scanf("%s",stu[i].num);

printf("name:

");

scanf("%s",stu[i].name);

sum=0;

for(j=0;j<3;j++)

{printf("score%d.",j+1);

scanf("%d",&stu[i].score[j]);

sum+=stu[i].score[j];

}

stu[i].avr=sum/3.0;

}

fp=fopen("stud","w");

for(i=0;i<5;i++)

if(fwrite(&stu[i],sizeof(structstudent),1,fp)!

=1)

printf("filewriteerror\n");

fclose(fp);

}

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