计算机代码Word格式文档下载.docx
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Picture1.Print
Nexti
EndSub
PrivateSubCommand2_Click()
Dimsun1AsInteger
sum1=0
sum1=sum1+a(i,j)
Text1.Text=Text1.Text&
sum1&
vbCrLf
PrivateSubCommand3_Click()
Dimsum2AsInteger
sum2=0
sum2=sum2+a(i,j)
Text2.Text=Text2.Text&
sum2&
"
PrivateSubCommand4_Click()
Dimsum3AsInteger
Ifi+j=v1+1Ori=jThensum3=sum3+a(i,j)
Text3.Text=sum3
数组
(2)
Sort(i)=10+int(rnd*90)
i10
sort(i)>
sort(j)
数组(3)
第一种先输入n的值,然后点击按钮则同时在picture和text中出现两个矩阵
text2的multiline属性要改为ture
Optionbase1
PrivateSubCommand1_click()
Dima()asinteger
Dimnasinteger,iasinteger,jasinteger,tempasinteger
n=val(text2.text)
redima(n,n)
fori=1ton
forj=iton
a(i,j)=10+int(rnd*90)
picture1.printa(i,j);
nextj
picture1.print
nexti
fori=1ton
forj=1ton
temp=a(I,j)
a(I,j)=a(j,i)
a(j,i)=temp
text1.text1=text1.text&
a(I,j)&
“”
text1.text=text1.text&
vbcrlf
第二种输入n后picture生成矩阵,点下按钮则进行转置
注意同上
Dima()AsInteger
DimnAsInteger,iAsInteger,jAsInteger,tempAsInteger
PrivateSubText2_change()
n=Val(Text2.Text)
ReDima(n,n)
Fori=1Ton
Forj=1Ton
Forj=iTon
temp=a(i,j)
a(i,j)=a(j,i)
a(j,i)=temp
a(i,j)&
过程
(1)
sum=sum+score(i)
round(av,1)
a()assingle,maxvassingle,minvassingle
forI=2toubound(a,1)
过程
(2)
2n-1
Exitfunction
true
val(text1.text)
3
Judge(i)
i=i+2
过程(3)
DimiAsInteger
Fori=10To9999
Ifarm(i)ThenPrinti
PrivateFunctionarm(xAsInteger)AsBoolean
n=Len(CStr(x))
sum=sum+Mid(x,i,1)^n
Ifsum<
>
xThen
ExitFunction
Else
arm=True
EndIf
EndFunction
综合
(1)
DimiAsInteger,jAsInteger,maxAsInteger,minAsInteger,maxhgsAsInteger,maxlesAsInteger,minhgsAsInteger,minlesAsInteger
Dima(4,5)AsInteger
Fori=1To4
Forj=1To5
a(i,j)=10+Int(Rnd*31)
max=a(1,1):
min=a(1,1):
maxhgs=1:
maxles=1:
minhgs=1:
minles=1
Ifa(i,j)>
maxThenmax=a(i,j):
maxhgs=i:
maxles=j
Ifa(i,j)=maxThenPicture2.Printa(i,j);
i;
j
Ifa(i,j)<
minThenmin=a(i,j):
minghs=i:
minles=j
Ifa(i,j)=minThenPicture2.Printa(i,j);
Picture1.Cls
Picture2.Cls
End
综合
(2)
text3的multiline属性要改为ture
DimaAsInteger,bAsInteger,iAsInteger,xAsInteger
a=Val(Text1.Text)
b=Val(Text2.Text)
Text3.Text="
幻影素数对:
"
Fori=aTob
x=0
Forj=len(cstr(i))to1step-1
x=Mid(i,j,1)&
x
Ifpu(i)Andpu(x)ThenText3.Text=Text3.Text&
vbCrLf&
i&
和"
&
PrivateFunctionpu(xAsInteger)AsBoolean
Fori=2Tox-1
IfxModi=0ThenExitFunction
pu=True
Text1.Text="
Text2.Text="
Text1.SetFocus