完整word版汇编第六章答案推荐文档Word下载.docx
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的功能,写出堆栈最满时各单元的地址及内容.
6.4题的程序
====================================
STACKSEGMENTAT500H
DW128DUP（?
STACKENDS
CODESEGMENT;
MAINPROCFAR;
MAINPARTOFPROGRAM
CODE,SS:
STACK
START:
;
STARTINGEXECUTIONADDRESS
MOVAX,STACK
SUBAX,AX
MAINPARTOFPROGRAMGOESHERE
MOVAX,4321H
CALLHTOA
RET
RETURNTODOS
MAINENDP;
ENDOFMAINPARTOFPROGRAM
HTOAPROCNEAR;
DEFINESUBPROCEDUREHTOA
CMPAX,15
JLEB1
PUSHBP
MOVBP,SP
MOVBX,[BP+2]
ANDBX,000FH
MOV[BP+2],BX
POPBP
MOVCL,4
SHRAX,CL
B1:
ADDAL,30H
CMPAL,3AH
JLPRINTIT
ADDAL,07H
PRINTIT:
MOVDL,AL
MOVAH,2
INT21H
HTOAENDP;
ENDOFSUBPROCEDURE
CODEENDS;
ENDSTART;
5.下面是6.5题的程序清单,请在清单中填入此程序执行过程中的堆栈变化.
0000
STACKSGSEGMENT
000020[.DW32DUP（?
?
0040
]
STACKSGENDS
CODESGSEGMENTPARA'
CODE'
BEGINPROCFAR
ASSUMECS:
CODESG,SS:
STACKSG
00001E
PUSHDS
00012BC0SUBAX,AX
000350
PUSHAX
0004E80008RCALLP10
0007CB
RET
0008
BEGINENDP
B10PROC
0008E8000CRCALLC10
000BC3
000C
B10ENDP
C10PROC
000CC3
000D
C10ENDP
CODESGENDS
ENDBEGIN
6.写一段子程序SKIPLINES,完成输出空行的功能.空行的行数在AX寄存器中.
SKIPLINESPROCNEAR
PUSHCX
PUSHDX
MOVCX，AX
NEXT：
MOVAH，2
MOVDL，0AH
INT21H
MOVAH，2
MOVDL，0DH
LOOPNEXT
POPDX
POPCX
RET
SKIPLINESENDP
7.设有10个学生的成绩分别是76,69,81,90,73,88,99,63,100和80分.试编制一个子程序统计60-69,70-79,80-89,90-99和100分的人数并分别存放到S6,S7,S8,S9和S10单元中.
DSEGSEGMENT
NUMDW76,69,84,90,73,88,99,63,100,80
NDW10
S6DW0
S7DW0
S8DW0
S9DW0
S10DW0
DSEGENDS
CODESEGMENT
MAINPROCFAR
CODE,DS:
DSEG
PUSHDS
SUBAX,AX
PUSHAX
MOVAX,DSEG
MOVDS,AX
CALLSUB1
MAINENDP
SUB1PROCNEAR
PUSHBX
PUSHSI
MOVSI,0
MOVCX,N
NEXT:
MOVAX,NUM[SI]
MOVBX,10
DIVBL
MOVBL,AL
CBW
SUBBX,6
SALBX,1
INCS6[BX]
ADDSI,2
POPSI
POPBX
POPAX
SUB1ENDP
CODEENDS
ENDSTART
（解法二）
datasgsegment
grade
db76,69,84,90,73,88,99,63,100,80
s6
db0
s7
s8
s9
s10
mess6db'
60~69:
$'
mess7db'
70~79:
mess8db'
80~89:
mess9db'
90~99:
mess10db'
100:
datasgends
codesgsegment
main
procfar
assumecs:
codesg,ds:
datasg
start:
pushds
subax,ax
pushax
movax,datasg
movds,ax
callsub1
leadx,mess6
calldispstr
movdl,s6
calldispscore
callcrlf
leadx,mess7
movdl,s7
calldispscore
leadx,mess8
movdl,s8
leadx,mess9
movdl,s9
calldispscore
leadx,mess10
movdl,s10
ret
endp
sub1
procnear
movcx,10
movsi,0
loop1:
moval,grade[si]
cmpal,60
jl
next5
cmpal,70
jgenext1
incs6
jmpshortnext5
next1:
cmpal,80
jgenext2
incs7
next2:
cmpal,90
jgenext3
incs8
next3:
cmpal,100
jgnext5
jenext4
incs9
next4:
incs10
next5:
incsi
looploop1
dispstrprocnear
movah,9
int21h
dispstrendp
dispscoreprocnear
adddl,30h
movah,2
dispscoreendp
crlfprocnear
movdl,0dh
movdl,0ah
crlfendp
codesgends
endstart
8.编写一个有主程序和子程序结构的程序模块.子程序的参数是一个N字节数组的首地址TABLE,数N及字符CHAR.要求在N字节数组中查找字符CHAR,并记录该字符的出现次数.;
主程序则要求从键盘接收一串字符以建立字节数组TABLE,并逐个显示从键盘输入的每个字符CHAR以及它在TABLE数组中出现的次数.（为简化起见,假设出现次数<
=15,可以用十六进制形式显示出来）
DATASEGMENT
MAXLENDB40
NDB?
TABLEDB40DUP（?
）
CHARDB'
A'
查找字符'
EVEN
_ADDRDW3DUP（?
DATAENDS
DATA
MOVAX,0
MOVAX,DATA
LEADX,MAXLEN
MOVAH,0AH
INT21H
从键盘接收字符串
MOV_ADDR,OFFSETTABLE
MOV_ADDR+2,OFFSETN
MOV_ADDR+4,OFFSETCHAR
MOVBX,OFFSET_ADDR;
通过地址表传送变量地址
CALLCOUNT
计算CHAR的出现次数
CALLDISPLAY;
显示
MAINENDP
COUNTPROCNEAR;
COUNT子程序
PUSHDI
MOVDI,[BX]
MOVSI,[BX+2]
MOVCL,BYTEPTR[SI]
MOVCH,0
MOVSI,[BX+4]
MOVAL,BYTEPTR[SI]
MOVBX,0
AGAIN:
CMPAL,BYTEPTR[DI]
JNEL1
INCBX
L1:
INCDI
LOOPAGAIN
POPDI
COUNTENDP
DISPLAYPROCNEAR;
DISPLAY子程序
CALLCRLF
显示回车和换行
MOVDL,CHAR
MOVAH,2
MOVDL,20H
MOVAL,BL
ANDAL,0FH
ADDAL,30H
CMPAL,3AH
JLPRINT
ADDAL,7
PRINT:
MOVDL,AL
CALLCRLF
DISPLAYENDP
CRLFPROCNEAR;
CRLF子程序
MOVDL,0DH
MOVDL,0AH
CRLFENDP
ENDSTART
9.编写一个子程序嵌套结构的程序模块,分别从键盘输入姓名及8个字符的电话号码,并以一定的格式显示出来.
主程序TELIST:
（1）显示提示符INPUTNAME:
（2）调用子程序INPUT_NAME输入姓名:
（3）显示提示符INPUTATELEPHONENUMBER:
（4）调用子程序INPHONE输入电话号码;
（5）调用子程序PRINTLINE显示姓名及电话号码;
子程序INPUT_NAME:
（1）调用键盘输入子程序GETCHAR,把输入的姓名存放在INBUF缓冲区中;
（2）把INBUF中的姓名移入输出行OUTNAME;
子程序INPHONE:
（1）调用键盘输入子程序GETCHAR,把输入的8位电话号码存放在INBUF缓冲区中;
（2）把INBUF中的号码移入输出行OUTPHONE.
子程序PRINTLINE:
显示姓名及电话号码,格式为:
NAME
TEL
****
********
==========================================
编写一个子程序嵌套结构的程序模块，分别从键盘输入姓名及8个字符的电话号码，并以一定的格式显示出来
（解法一）
datasegment
No_of_namedb20
No_of_phonedb8
inbufdb20dup（?
outnamedb20dup（?
）,'
outphonedb8dup（?
message1db'
pleaseinputname:
'
'
message2db'
pleaseinputatelephonenumber:
message3db'
NAME'
16dup（20h）,'
TEL.'
13,10,'
errormessage1db'
youshouldinput8numbers!
errormessage2db'
youinputawrongnumber!
flagdb?
dataends
progsegment
mainprocfar
prog,ds:
data
movax,data
movflag,0
leadx,message1
movah,09
callinput_name
leadx,message2
callinphone
cmpflag,1
je
exit
callprintline
exit:
mainendp
input_nameprocnear
pushdx
pushcx
movcx,0
movcl,No_of_name
callgetchar
movax,0
moval,No_of_name
subax,cx
movcx,ax
moval,inbuf[si]
movoutname[si],al
loopnext1
popcx
popdx
popax
input_nameendp
inphoneprocnear
movcl,No_of_phone
cmpcx,0
jnzerror1
movcl,No_of_phone
cmpal,30h
error2
cmpal,39h
ja
movoutphone[si],al
loopnext2
jmpexit2
error1:
leadx,errormessage1
movflag,1
error2:
leadx,errormessage2
exit2:
inphoneendp
getcharprocnear
movdi,0
rotate:
movah,01
cmpal,0dh
exit1
movinbuf[di],al
incdi
looprotate
exit1:
getcharendp
printlineprocnear
leadx,message3
leadx,outname
movah,09
int21h
leadx,outphone
printlineendp
progends
endmain
从键盘输入姓名及8个字符的电话号码，并以一定的格式显示出来
datareasegment
inbuf
label
byte
nameparameterlist:
maxn
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