高级财管考点总结.docx

上传人:b****8 文档编号:9890037 上传时间:2023-02-07 格式:DOCX 页数:12 大小:87.69KB
下载 相关 举报
高级财管考点总结.docx_第1页
第1页 / 共12页
高级财管考点总结.docx_第2页
第2页 / 共12页
高级财管考点总结.docx_第3页
第3页 / 共12页
高级财管考点总结.docx_第4页
第4页 / 共12页
高级财管考点总结.docx_第5页
第5页 / 共12页
点击查看更多>>
下载资源
资源描述

高级财管考点总结.docx

《高级财管考点总结.docx》由会员分享,可在线阅读,更多相关《高级财管考点总结.docx(12页珍藏版)》请在冰豆网上搜索。

高级财管考点总结.docx

高级财管考点总结

高级财管考点总结

计算题(50分)

10.1a.ExpectedReturn=(0.1)(-0.045)+(.2)(0.044)+(0.5)(0.12)+(0.2)(0.207)

=0.1057

=10.57%

TheexpectedreturnonQ-mart’sstockis10.57%.

b.Variance(σ2)=(0.1)(-0.045–0.1057)2+(0.2)(0.044–0.1057)2+(0.5)(0.12–0.1057)2+

(0.2)(0.207–0.1057)2

=0.005187

StandardDeviation(σ)=(0.005187)1/2

=0.0720

=7.20%

ThestandarddeviationofQ-mart’sreturnsis7.20%.

10.2a.ExpectedReturnA=(1/3)(0.063)+(1/3)(0.105)+(1/3)(0.156)

=0.1080

=10.80%

TheexpectedreturnonStockAis10.80%.

ExpectedReturnB=(1/3)(-0.037)+(1/3)(0.064)+(1/3)(0.253)

=0.933

=9.33%

TheexpectedreturnonStockBis9.33%.

b.VarianceA(σA2)=(1/3)(0.063–0.108)2+(1/3)(0.105–0.108)2+(1/3)(0.156–0.108)2

=0.001446

StandardDeviationA(σA)=(0.001446)1/2

=0.0380

=3.80%

ThestandarddeviationofStockA’sreturnsis3.80%.

VarianceB(σB2)=(1/3)(-0.037–0.0933)2+(1/3)(0.064–0.0933)2+(1/3)(0.253–0.0933)2

=0.014447

StandardDeviationB(σB)=(0.014447)1/2

=0.1202

=12.02%

ThestandarddeviationofStockB’sreturnsis12.02%.

C.Covariance(RA,RB)=(1/3)(0.063–0.108)(-0.037–0.0933)+(1/3)(0.105–0.108)(0.064–0.933)+(1/3)(0.156–0.108)(0.253–0.0933)

=0.004539

ThecovariancebetweenthereturnsofStockAandStockBis0.004539.

Correlation(RA,RB)=Covariance(RA,RB)/(σA*σB)

=0.004539/(0.0380*0.1202)

=0.9937

ThecorrelationbetweenthereturnsonStockAandStockBis0.9937.

10.3a.ExpectedReturnHB=(0.25)(-0.02)+(0.60)(0.092)+(0.15)(0.154)

=0.0733

=7.33%

TheexpectedreturnonHighbull’sstockis7.33%.

ExpectedReturnSB=(0.25)(0.05)+(0.60)(0.062)+(0.15)(0.074)=0.0608

=6.08%

TheexpectedreturnonSlowbear’sstockis6.08%.

b.VarianceA(σHB2)=(0.25)(-0.02–0.0733)2+(0.60)(0.092–0.0733)2+(0.15)(0.154–0.0733)2

=0.003363

StandardDeviationA(σHB)=(0.003363)1/2

=0.0580

=5.80%

ThestandarddeviationofHighbear’sstockreturnsis5.80%.

VarianceB(σSB2)=(0.25)(0.05–0.0608)2+(0.60)(0.062–0.0608)2+(0.15)(0.074–0.0608)2

=0.000056

StandardDeviationB(σB)=(0.000056)1/2

=0.0075

=0.75%

ThestandarddeviationofSlowbear’sstockreturnsis0.75%.

c.Covariance(RHB,RSB)=(0.25)(-0.02–0.0733)(0.05–0.0608)+(0.60)(0.092–0.0733)(0.062–(0.0608)+(0.15)(0.154–0.0733)(0.074–0.0608)

=0.000425

ThecovariancebetweenthereturnsonHighbull’sstockandSlowbear’sstockis

0.000425.

Correlation(RA,RB)=Covariance(RA,RB)/(σA*σB)

=0.000425/(0.0580*0.0075)

=0.9770

ThecorrelationbetweenthereturnsonHighbull’sstockandSlowbear’sstockis

0.9770.

10.4ValueofAtlasstockintheportfolio=(120shares)($50pershare)

=$6,000

ValueofBabcockstockintheportfolio=(150shares)($20pershare)

=$3,000

TotalValueintheportfolio=$6,000+$3000

=$9,000

WeightofAtlasstock=$6,000/$9,000

=2/3

TheweightofAtlasstockintheportfoliois2/3.

WeightofBabcockstock=$3,000/$9,000

=1/3

TheweightofBabcockstockintheportfoliois1/3.

11.1RealGNPwashigherthananticipated.SincereturnsarepositivelyrelatedtothelevelofGNP,returnsshouldrisebasedonthisfactor.

Inflationwasexactlytheamountanticipated.Sincetherewasnosurpriseinthis

announcement,itwillnotaffectLewis-Stridenreturns.

InterestRatesarelowerthananticipated.Sincereturnsarenegativelyrelatedto

interestrates,thelowerthanexpectedrateisgoodnews.Returns

shouldriseduetointerestrates.

ThePresident’sdeathisbadnews.Althoughthepresidentwasexpectedtoretire,his

retirementwouldnotbeeffectiveforsixmonths.Duringthatperiodhewouldstillcontributetothefirm.Hisuntimelydeathmeanthatthosecontributionswouldnotbemade.Sincehewasgenerallyconsideredanassettothefirm,hisdeathwillcausereturnstofall.

Thepoorresearchresultsarealsobadnews.SinceLewis-Stridenmustcontinueto

testthedrug,itwillnotgointoproductionasearlyasexpected.Thedelaywillaffectexpectedfutureearnings,andthusitwilldampenreturnsnow.

TheresearchbreakthroughispositivenewsforLewisStriden.Sinceitwas

unexpected,itwillcausereturnstorise.

Thecompetitor’sannouncementisalsounexpected,butitisnotawelcomesurprise.ThisannouncementwilllowerthereturnsonLewis-Striden.

Systematicriskisriskthatcannotbediversifiedawaythroughformationofaportfolio.Generally,systematicriskfactorsarethosefactorsthataffectalargenumberoffirmsinthemarket,however,thosefactorswillnotnecessarilyaffectallfirmsequally.ThesystematicfactorsinthelistarerealGNP,inflationandinterestrates.

Unsystematicriskisthetypeofriskthatcanbediversifiedawaythroughportfolioformation.Unsystematicriskfactorsarespecifictothefirmorindustry.Surprisesinthesefactorswillaffectthereturnsofthefirminwhichyouareinterested,buttheywillhavenoeffectonthereturnsoffirmsinadifferentindustryandperhapslittleeffectonotherfirmsinthesameindustry.ForLewis-Striden,theunsystematicriskfactorsarethepresident’sabilitytocontributetothefirm,theresearchresultsandthecompetitor.

11.2a.Letm=systematicriskportionofreturn:

b.Let

=theunsystematicportionofrisk,sincethenewswasonlyaboutthisfirm:

c.TotalReturn=Expectedreturn,plus2thecomponentsofunexpectedreturn:

thesystematicriskportionofreturnandtheunsystematicportion:

11.3a.Letm=systematicriskportionofreturn:

b.Let

=theunsystematicportionofrisk:

c.TotalReturn:

11.4a.Themarketmodelisspecifiedby:

soapplyingthattoeachStock:

StockA:

StockB:

StockC:

b.Sincewedon'thavetheactualmarketreturnorunsystematicrisk,wewillgetaformulawiththosevaluesasunknowns:

c.Now,continuingwiththeMarketModel(asinparta),when

=15%,andall

=0:

i.returnsofindividualstocks:

ii.returnoftheportfolio:

AlternateSolutionforreturnonportfolio,where

istheweightintheportfolioofstocki:

12.1Thediscountratefortheprojectisequaltotheexpectedreturnforthesecurity,RS,sincetheprojecthasthesameriskasthefirmasawhole.ApplytheCAPMtoexpressthefirm’srequiredreturn,RS,intermsofthefirm’sbeta,,therisk-freerate,RF,andtheexpectedmarketreturn,

M.

RS=RF+(

M–RF)

=0.05+0.95(0.09)

=0.1355

Subtracttheinitialinvestmentatyear0.TocalculatethePVofthecashinflows,applytheannuityformula,discountedat0.1355.

NPV=C0+C1ATr

=-$1,200,000+$340,000A50.1355

=-$20,016.52

DonotundertaketheprojectsincetheNPVisnegative.

12.2a.CalculatetheaveragereturnforDouglasstockandthemarket.

D=(SumofYearlyReturns)/(NumberofYears)

=(-0.05+0.05+0.08+0.15+0.10)/(5)

=0.066

M=(-0.12+0.01+0.06+0.10+0.05)/(5)

=0.020

TocalculatethebetaofDouglasstock,calculatethevarianceofthemarket,(RM-

M)2,andthecovarianceofDouglasstock’sreturnwiththemarket’sreturn,(RD-

D)(RM-

M).ThebetaofDouglasstockisequaltothecovarianceofDouglasstock’sreturnandthemarket’sreturndividedbythevarianceofthemarket.RemembertodivideboththecovarianceofDouglasstock’sreturnandthemarket’sreturnandthevarianceofthemarketby4.Becausethedataarehistorical,theappropriatedenominatorinthecalculationofthevarianceis4(=T–1).

RD-

D

RM-

M

(RM-

M)2

(RD-

D)(RM-

M)

-0.116

-0.14

0.0196

0.01624

-0.016

-0.01

0.0001

0.00016

0.014

0.04

0.0016

0.00056

0.084

0.08

0.0064

0.00672

0.034

0.03

0.0009

0.00102

0.0286

0.02470

D=[Cov(RD,RM)/(T-1)]/[Var(RM)/(T-1)]

=(0.02470/4)/(0.0286/4)

=0.864

ThebetaofDouglasstockis0.864.

 

12.3Calculatethesquarerootofthestock’svarianceandthemarket’svariancetofindthestandarddeviation,,ofeach.

C=(2C)1/2

=(0.004225)1/2

=0.065

M=(2M)1/2

=(0.001467)1/2

=0.0383

Usetheformulaforbeta:

C=[Corr(RC,RM)C]/M

=[(0.675)(0.065)]/(0.0383)

=1.146

ThebetaofCeramicsCraftsmanis1.146.

12.4a.TocomputethebetaofMercantile’sstock,dividethecovarianceofthestock’sreturn

withthemarket’sreturnbythemarketvariance.Sincethosetwovaluesareprovidedintheproblem,the13quarterlyreturnsofMercantile’sstockandthemarketarenotneededforthecalculation.

D=Cov(RD,RM)/2M

=(0.038711)/(0.038588)

=1.0032

ThebetaofMercantileBankingCorporationis1.0032.

b.Thebetaoftheaveragestockisone.SinceMercantile’sbetaisclosetoone,itsstockhasapproximatelythesameriskastheoverallmarket.

Correlation(RA,RB)=Covariance(RA,RB)/(σA*σB)

=0.004539/(0.0380*0.1202)

=0.9937

ThecorrelationbetweenthereturnsonStockAandStockBis0.9937.

10.3a.ExpectedReturnHB=(0.25)(-0.02)+(0.60)(0.092)+(0.15)(0.154)

=0.0733

=7.33%

TheexpectedreturnonHighbull’sstockis7.33%.

ExpectedReturnSB=(0.25)(0.05)+(0.60)(0.062)+(0.15)(0.074)=0.0608

=6.08%

TheexpectedreturnonSlowbear’sstockis6.08%.

b.VarianceA(σHB2)=(0.25)(-0.02–0.0733)2+(0.60)(0.092–0.0733)2+(0.15)(0.154–0.0733)2

=0.003363

StandardDeviationA(σHB)=(0.003363)1/2

=0.0580

=5.80%

ThestandarddeviationofHighbear’sstockreturnsis5.80%.

VarianceB(σSB2)=(0.25)(0.05–0.0608)2+(0.60)(0.062–0.0608)2+(0.15)(0.074–0.0608)2

=0.000056

StandardDe

展开阅读全文
相关资源
猜你喜欢
相关搜索

当前位置:首页 > 高等教育 > 医学

copyright@ 2008-2022 冰豆网网站版权所有

经营许可证编号:鄂ICP备2022015515号-1