sql习题及答案.docx
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sql习题及答案
题
1、查询Student表中的所有记录的Sname、Ssex和Class列。
2、查询教师所有的单位即不重复的Depart列。
3、查询Student表的所有记录。
4、查询Score表中成绩在60到80之间的所有记录。
5、查询Score表中成绩为85,86或88的记录。
6、查询Student表中“95031”班或性别为“女”的同学记录。
7、以Class降序查询Student表的所有记录。
8、以Cno升序、Degree降序查询Score表的所有记录。
9、查询“95031”班的学生人数。
10、查询Score表中的最高分的学生学号和课程号。
11、查询‘3-105’号课程的平均分。
12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。
13、查询最低分大于70,最高分小于90的Sno列。
14、查询所有学生的Sname、Cno和Degree列。
15、查询所有学生的Sno、Cname和Degree列。
16、查询所有学生的Sname、Cname和Degree列。
17、查询“95033”班所选课程的平均分。
18、假设使用如下命令建立了一个grade表:
createtablegrade(lownumeric(3,0),uppnumeric(3),rankchar
(1));
insertintogradevalues(90,100,'A');
insertintogradevalues(80,89,'B');
insertintogradevalues(70,79,'C');
insertintogradevalues(60,69,'D');
insertintogradevalues(0,59,'E');
现查询所有同学的Sno、Cno和rank列。
19、查询选修“3-105”课程的成绩高于“109”号同学成绩的所有同学的记录。
20、查询score中选学一门以上课程的同学中分数为非最高分成绩的记录。
21、查询成绩高于学号为“109”、课程号为“3-105”的成绩的所有记录。
22、查询和学号为108的同学同年出生的所有学生的Sno、Sname和Sbirthday列。
23、查询“张旭“教师任课的学生成绩。
24、查询选修某课程的同学人数多于5人的教师姓名。
25、查询95033班和95031班全体学生的记录。
26、查询存在有85分以上成绩的课程Cno.
27、查询出“计算机系“教师所教课程的成绩表。
28、查询“计算机系”与“电子工程系“不同职称的教师的Tname和Prof。
29、查询选修编号为“3-105“课程且成绩至少高于选修编号为“3-245”的同学的Cno、Sno和Degree,并按Degree从高到低次序排序。
30、查询选修编号为“3-105”且成绩高于选修编号为“3-245”课程的同学的Cno、Sno和Degree.
31、查询所有教师和同学的name、sex和birthday.
32、查询所有“女”教师和“女”同学的name、sex和birthday.
33、查询成绩比该课程平均成绩低的同学的成绩表。
34、查询所有任课教师的Tname和Depart.
35查询所有未讲课的教师的Tname和Depart.
36、查询至少有2名男生的班号。
37、查询Student表中不姓“王”的同学记录。
38、查询Student表中每个学生的姓名和年龄。
39、查询Student表中最大和最小的Sbirthday日期值。
40、以班号和年龄从大到小的顺序查询Student表中的全部记录。
41、查询“男”教师及其所上的课程。
42、查询最高分同学的Sno、Cno和Degree列。
43、查询和“李军”同性别的所有同学的Sname.
44、查询和“李军”同性别并同班的同学Sname.
45、查询所有选修“计算机导论”课程的“男”同学的成绩表
下面是参考答案:
SQL语句练习题参考答案
1.selectsname,ssex,classfromstudent;
2.
selectdistinct(depart)fromteacher;
or
selectdistinctdepartfromteacher;
3.select*fromstudent;
4.
select*fromscorewheredegreebetween60and80;
or
select*fromscorewheredegree>=60anddegree<=80;
5.
select*fromscorewheredegreein(85,86,88);
or
select*fromscorewheredegree=85ordegree=86ordegree=88;
6.select*fromstudentwhereclass=95031orssex='女';
7.select*fromstudentorderbyclassdesc;
8.
select*fromscoreorderbycnoasc,degreedesc;
or
select*fromscoreorderbycno,degreedesc;
9.
selectcount(*)fromstudentwhereclass=95031;
or
selectcount(sno)fromstudentwhereclass=95031;
10.selectSnoas'学号',cnoas'课程号',degreeas'最高分'fromscorewheredegree=(selectmax(degree)fromscore);
11.selectavg(degree)fromscorewherecno='3-105';
12.
selectcno,avg(degree)fromscorewherecnolike'3%'groupbycnohavingcount(sno)>5;
or
selectcno,avg(degree)fromscorewherecnolike'3%'groupbycnohavingcount(*)>5;
13.selectsnofromscoregroupbysnohavingmin(degree)>70andmax(degree)<90;
14.
selectstudent.sname,o,score.degreefromstudent,scorewherestudent.sno=score.sno;
or
selectsname,cno,degreefromstudent,scorewherestudent.sno=score.sno;
or
selectx.sname,o,y.degreefromstudentx,scoreywherex.sno=y.sno;
15.
Selectscore.sno,ame,score.degreefromscore,coursewhereo=o;
or
selectsno,cname,degreefromscore,coursewhereo=o;
or
selectx.sno,ame,x.degreefromscorex,courseywhereo=o;
16.
selectstudent.sname,ame,score.degreefromstudent,course,scorewherestudent.sno=score.snoando=o;
or
selectsname,cname,degreefromstudent,course,scorewherestudent.sno=score.snoando=o;
or
selectx.sname,ame,z.degreefromstudentx,coursey,scorezwherex.sno=z.snoando=o;
17.
selectcno,avg(degree)fromscore,studentwherestudent.sno=score.snoandclass=95033groupbycno;
or
selecto,avg(y.degree)fromstudentx,scoreywherex.sno=y.snoandx.class=95033groupbyo;
18.selectsno,cno,rankfromscore,gradewheredegreebetweenlowandupp[orderbyrank];[]表示可有可无
19.
select*fromscorewherecno='3-105'anddegree>(selectdegreefromscorewheresno='109'andcno='3-105');
or
selectx.*fromscorex,scoreywhereo='3-105'andx.degree>y.degreeandy.sno='109'ando='3-105';
20.
分析:
1.成绩非本科最高select*fromscorewheredegreenotin(selectmax(degree)fromscoregroupbycno)
选学一门以上的学生成绩:
selectsnofromscoregroupbysnohavingcount(*)>1;
2.查询成绩非本科最高并且选1门以上的学生的成绩:
select*fromscorewheredegreenotin(selectmax(degree)fromscoregroupbycno)groupbysnohavingcount(*)>1;
or
select*from(select*fromscorewheredegreenotin(selectmax(degree)fromscoregroupbycno))asaagroupbysnohavingcount(*)>=2;
通用答案:
selectsnofrom
( select*fromscore
wheredegreenotin
(selectmax(degree)fromscoregroupbycno))asaa
groupbysnohavingcount(*)>=2;
21.
select*fromscorewheredegree>(selectdegreefromscorewheresno=109andcno='3-105');
or
selectx.*fromscorex,scoreywherex.degree>y.degreeandy.sno=109ando='3-105';
22.
selectsno,sname,sbirthdayfromstudentwhereyear(sbirthday)=(selectyear(sbirthday)fromstudentwheresno=108);
23.
select*fromscorewherecnoin(selectcnofromcoursewheretno=(selecttnofromteacherwheretname='张旭'));
or
selectcno,sno,degreefromscorewherecno=(selectofromcoursex,teacherywherex.tno=y.tnoandy.tname='张旭');
24.
selecttnamefromteacherwheretnoin(selectx.tnofromcoursex,scoreywhereo=oandoin(selectcnofromscoregroupbycnohavingcount(*)>5));
or
selecttnamefromteacherwheretnoin(selecttnofromcoursewherecnoin(selectcnofromscoregroupbycnohavingcount(*)>5));
or
selecttnamefromteacherwheretnoin(selectx.tnofromcoursex,scoreywhereo=ogroupbyx.tnohavingcount(x.tno)>5);
25.
select*fromstudentwhereclassin('95033','95031');
or
select*fromstudentwhereclass=95033orclass=95031;
26.selectdistinctcnofromscorewheredegreein(selectdegreefromscorewheredegree>85);
27.
select*fromscorewherecnoin(selectcnofromcoursewheretnoin(selecttnofromteacherwheredepart='计算机系'));
or
select*fromscorewherecnoin(selectofromcoursex,teacherywherey.tno=x.tnoandy.depart='计算机系');
28.selecttname,proffromteacherwheredepart='计算机系'andprofnotin(selectproffromteacherwheredepart='电子工程系');
29.
select*fromscorewherecno='3-105'anddegree>(selectmin(degree)fromscorewherecno='3-245')orderbydegreedesc;
or
select*fromscorewherecno='3-105'anddegree>any(selectdegreefromscorewherecno='3-245')orderbydegreedesc;
30.
select*fromscorewherecno='3-105'anddegree>(selectmax(degree)fromscorewherecno='3-245');
or
select*fromscorewherecno='3-105'anddegree>all(selectdegreefromscorewherecno='3-245');
31.
selectsnameasname,ssexassex,sbirthdayasbirthdayfromstudent
union
selecttname,tsex,tbirthdayfromteacher;
32.
selectsnameasname,ssexassex,sbirthdayasbirthdayfromstudentwheressex='女'
union
selecttname,tsex,tbirthdayfromteacherwheretsex='女';
33.select*fromscoreawheredegree<(selectavg(degree)fromscorebwhereo=o);
34.selecttname,departfromteacherwheretnoin(selecttnofromcourse);
35.selecttname,departfromteacherwheretnonotin(selecttnofromcourse);
36.selectclassfromstudentwheressex='男'groupbyclasshavingcount(sno)>=2;
37.select*fromstudentwheresnamenotlike'王%';
38.selectsnameas'姓名',2010-year(sbirthday)as'年龄'fromstudent;
39.
selectsbirthdayfromstudentwheresbirthdayin(selectmin(sbirthday)fromstudent)
union
selectsbirthdayfromstudentwheresbirthdayin(selectmax(sbirthday)fromstudent);
or
selectsbirthdayfromstudentwheresbirthday=(selectmin(sbirthday)fromstudent)orsbirthday=(selectmax(sbirthday)fromstudent);
40.select*fromstudentorderbyclassdesc,sbirthday;
41.
selectcname,tnamefromcourse,teacherwherecourse.tno=teacher.tnoandtsex='男';
or
selectame,teacher.tnamefromcourse,teacherwherecourse.tno=teacher.tnoandtsex='男';
or
selectcname,tnamefromcoursex,teacherywherex.tno=y.tnoandy.tsex='男';
or
selectx.tname,amefromteacherx,courseywherex.tno=y.tnoandx.tsex='男';
42.select*fromscorewheredegreein(selectmax(degree)fromscore);
43.selectsnamefromstudentwheressex=(selectssexfromstudentwheresname='李军');
44.selectsnamefromstudentwheressex=(selectssexfromstudentwheresname='李军')andclass=(selectclassfromstudentwheresname='李军');
45.select*fromscorewheresnoin(selectsnofromstudentwheressex='男')andcnoin(selectcnofromcoursewherecname='计算机导论');
注意:
20题的前两个答案在sqlserver中不支持,在mysql中支持
如果题答案中有错误,请记得及时通知我让我纠正错误!
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