Steam properties.docx
《Steam properties.docx》由会员分享,可在线阅读,更多相关《Steam properties.docx(13页珍藏版)》请在冰豆网上搜索。
Steamproperties
30/10/2014
Steamandsilencers
Summary
2methodscanbeusedtodeterminetheparametersofthesonicneck :
∙AgraphicalmethodwithEXCELfromthesteamtables(saturatedsteam)byusingtheratioxwhichistheratioofthemassofthegaseousphasedividedbythemassofthemixture.
∙Amethodusingrelationshipssimilartothoseofperfectgases,withanisentropiccoefficientkinsteadof
.
TheygivethesameresultsastheBertincalculationofatypicalcase.
Then,concerningthevelocityofthejetdownstreaminfinite(wherethepressureistheatmosphericpressure):
Wehavetoconsiderthatitisanadiabaticexpansion.
Onecanfindverydetailedsteamtablesonthefollowingsite:
sitehttp:
//webbook.nist.gov/chemistry/fluid.
Tabledesmatières
1Goal3
2Steamtable3
3Caseofstudy4
3.1Personalinterpretation5
4Steam5
4.1Enthalpydiagrams5
4.2Isentropiccurves6
4.3Relationshipbetweenpressureanddensity7
4.4Isentropicexpansionrelationships8
4.4.1Zeunerrelationship8
4.4.2Eulerequation8
4.4.3Soundspeeddefinition8
4.4.4Continuity9
4.4.5Additionallaws9
5Backtothecasestudy10
5.1Usingisentropicrelationships10
5.2CurrentBertincalculation11
5.3Downstream12
1Goal
ExplainthethermodynamicalbehaviourusedtocomputeanddesigntheBertinsilencers.
2Steamtable
Websitewhereonecandownloadveryaccuratedata:
http:
//webbook.nist.gov/chemistry/fluid/
http:
//webbook.nist.gov/cgi/fluid.cgi?
TLow=100&THigh=300&TInc=1&Applet=on&Digits=5&ID=C7732185&Action=Load&Type=SatP&TUnit=C&PUnit=MPa&DUnit=kg%2Fm3&HUnit=kcal%2Fmol&WUnit=m%2Fs&VisUnit=uPa*s&STUnit=N%2Fm&RefState=DEF
3Caseofstudy
Theimportantparametersforthesilencerdesignare :
∙Thetotalsectionnecessaryfortheflowrateattherequiredpressure(sonicneck)
∙Thejetspeedatthedownstreaminfiniteconditionwhichisusedtocalculatetheacousticpowerforafreejet.
Wechooseanumericalapplicationforwhichwehavetheresultsofcalculation:
∙NISteamDumpSilencers-DumpingModuleandAcousticsDimensioning-Réf.:
05483-005-DC002-A
∙Pages5et6,itiswritten:
∙
∙
∙
3.1Personalinterpretation
Asthevalvebehaviourisunknown,wejustconsidertheupstreamconditions(3)ofthevalve
Thenweadmitthattheexpansionisadiabatic(isentropic)for2reasons:
ØAsthesteamvelocityattheneckwillbehigh(soundspeed)weadmitthatthereisnoheatexchangewithenvironment;
ØWehavesimplerelationshipsinthiscase.
Thenwemanagetohaveasonicflowattheneck.
Then,weadmitthatattheoutlet,thepressuredecreasestoreachtheatmosphericpressureinthefarfield.Wehavestillanadiabaticexpansionandwecancalculatethesteamvelocityattheatmosphericpressure.
4Steam
Thesteamisnotaperfectgas.
4.1Enthalpydiagrams
Weusetheenthalpydiagramsversusentropyforsaturatedsteambecausethetransformationisassumedtobeisentropic(adiabatic).
Above:
Enthalpyforvariousxcoefficients.
Thecurvex=1isthesaturatedsteamcurve.
Onthisgraph:
Theinitialenthalpyis2765kJ/kg.Thenwehaveanisentropicexpansionuptoh1.Thetitrexis0,9.Itmeansthatthecorrespondingsteammixturecontains90%ofgas(inmass).
4.2Isentropiccurves
Theyareeasytobuildwhentheenthalpydecreasesbecausewecanusethetitrex.
Fortheentropy,wehave:
Where
istheentropyoftheliquidphaseand
theentropyofthegaseousphase.
Itisthesamewithenthalpyandvolume(inm^3/kg).
Wecaneasilycomputethexcoefficientcorrespondingtotheentropywherex=1whichistheentropyforsaturatedsteam.Forx=1wehave:
Thereforeforeachlineofthetablewecancompute:
Thenwecomputeforeachline:
Thepressureandtemperaturedonotchangewhenxchanges.
NotaBene:
xcannotexceed1.
4.3Relationshipbetweenpressureanddensity
Thankstothesteamtable,wehavenowonanisentropiccurvethevaluesofthedensityandpressureofthemixture.Wecanseethat:
Hereafteraresomeisentropiccoefficientsforsomevaluesoftheentropy:
S(kJ/kg/°K)
k
6,9894
1,1376
6,014
1,1213
5,7739
1,1093
5,5026
1,0909
5,2915
1,0733
4.4Isentropicexpansionrelationships
Inthefollowingequationsweneverassumethatsteamisaperfectgas.
4.4.1Zeunerrelationship
ONLYifthetransformationisadiabatic(isentropic):
Theenthalpyishanduisthefluidvelocity.
Betweentheinitialstateandanycurrentpoint:
Wederivethisrelationship:
Infact,itisthethermodynamicalequationintheparticularcaseofanadiabatictransformation.
4.4.2Eulerequation
Withoutexternalforceswork :
UsingZeunerequation,wehavealso:
4.4.3Soundspeeddefinition
Thesoundspeedisgivenbythepartialderivativeofpressureversusdensityinisentropicconditions :
4.4.4Continuity
Itistheconservationofthemass,andthusofthemassflowrate:
WhereAisthesection.
Therefore:
4.4.5Additionallaws
Wecanobtainadditionallawswhichareverysimilartothoseforperfectgases.
Using :
Wherekdependsupontheentropy(butisconstantforagivenentropy)weobtainafterboringcalculationsthefollowingrelationships :
ØWhenthedownstreamvelocityisneglected:
Massflowrateforasubsonicflow:
Criticalpressureforasonicflowrate:
Velocityattheneck(soundvelocity) :
Massflowrateforasonicflow:
5Backtothecasestudy
Inlet(i)
DumpingModule(3)
Sonicneck(c)
Outlet(o)
Pi=7.6MPaabs
Ti=292°C
Hi=2765kJ/kg
P3=4.56MPaabs
T3=258°C
Tc
Po=0.1MPaabs
To=145°C
Ho=Hi=2765kJ/kg
Nota:
V3isabout80m/s.Thecondition(V3)²/2<Upstreamwehave:
Pi=7.6MPaabs
Ti=292°C
Hi=2765kJ/kg
5.1Usingisentropicrelationships
∙Necksection :
Theequation
Gives:
With:
k=
1,1213
cte1=
0,61543621
cte2=
1,05718192
P0=
4,56
Mpa
P0=
4560000
Pa
rho_0=
23,013
kg/m^3
For:
Qm=
90
kg/s
Wefind:
A=
1,3884E-02
m^2
∙Criticalpressure(atthesonicneck):
Pc/P0=
0,580
P0/Pc=
1,723
Pc=
2,646
Mpa
∙Soundspeed:
Wefind:
c^2=
2,095E+05
c=
457,69
m/s
5.2CurrentBertincalculation
Itgivesthesameresult.
5.3Downstream
Weusetherelationship:
Attheatmosphericpressure:
k=
1,1213
P0=
4,56
Mpa
P0=
4560000
Pa
rho_0=
23,013
kg/m^3
Uj=
1113,56138
m/s