IBMPC汇编语言作业答案文档格式.docx

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IBMPC汇编语言作业答案文档格式.docx

1D000H

1D001H

1D002H

1D003H

AX

8FF10H

8FF11H

8FF12H

8FF13H

3.7

(1)0626H+27H=064DH

(2)0626H+6BH=0691H

(3)0626H+0FFC6H=05ECH(注意符号扩展)

3.8

寻址方式物理地址

(1)立即数寻址无

(2)寄存器寻址无

(3)直接寻址20100H

(4)直接寻址20050H

(5)寄存器间接寻址20100H

(6)寄存器间接寻址21100H

(7)寄存器间接寻址15010H

(8)寄存器间接寻址200A0H

(9)寄存器相对寻址20000H+0100H+0AH=2010AH

(10)寄存器相对寻址20150H

(11)基址变址寻址201A0H

(12)相对基址变址寻址201F0H

3.9

(1)MOVAX,[BX+12]

MOVZERO,AX

(2)MOVAX,ARRAY[BX]

3.10

(1)1234H

(2)0032H

3.11

1E00H

3.13

SP57H0FFAAEH

80H0FFAAFH

SP0FFAB0H

(1)初始

(2)8057H入栈

SP

79H0FFACH79H0FFACH

0FH0FFADH0FH0FFADH

57H0FFAEHSP57H0FFAEH

80H0FFAFH80H0FFAFH

(3)0F79H入栈(4)0F79H出栈

3.15

62A0H62A0H62A0H62A0H

+1234H+4321H+CFA0H+9D60H

74D4HA5C1H3240H

(1)0000H

SF0100

ZF0001

CF0011

OF0100

3.17

(1)MOVAX,Z

SUBAX,X

ADDAX,W

MOVZ,AX

(2)ADDX,6

ADDR,9

MOVAX,W

SUBAX,R

(3)MOVAX,W

IMULX

ADDY,6

MOVBX,Y

IDIVBX

MOVR,DX

(4)MOVBX,W

SUBBX,X;

(BX)=W-X

MOVAX,Y

MOVCX,5

IMULCX;

(DX,AX)=Y×

5

MOVCXAX

MOVAX,BX;

BX扩展到EAX(32位)

CWD;

被除数扩展到64位

IDIVCX;

除数Y限制为字(16位)

SALAX,1

MOVZ,AX;

可以认为AX能存储下结果

3.19

程序

CF

SF

ZF

0F

MOVAX,0

0000H

----

DECAX

FFFFH

1

0

1

ADDAX,7FFFH

7FFFH

ADDAX,2

8000H

NOTAX

SUBAX,0FFFFH

ADDAX,8000H

SUBAX,1

ANDAX,58D1H

58D1H

SACAX,1

B1A2H

SARAX,1

D8D1H

NEGAX

272FH

RORAX,1

9397H

3.21

NOTAX

NOTDX

ADDAX,1

ADCDX,0

3.23

(1)BX=009AH

(2)BX=0061H(3)BX=00FBH(4)BX=001CH(5)BX=0000H(6)BX=0001H

3.25

(1)+53×

2MOVAL,35H

(2)-49×

2MOVAL,CFH

SALAL,1SALAL,1

结果为6AH=106D结果为9EH=-98D

(3)+53÷

2MOVAL,35H(4)-49÷

2MOVAL,CFH

SARAL,1SARAL,1

结果为1AH=26D结果为E7H=-24D

3.27

(1)DX=0000000001011100B

(2)DX=0000000000010111B

(3)DX=0000010111001000B

(4)DX=0000000001110010B

(5)DX=0001000000010111B

(6)DX=0000000011001101B

(7)DX=0000000010111001B

(8)DX=0000010111001100B

(9)DX=0000000011011100B

3.29

(1)LEASI,CONAME

(2)LEASI,CONAME(3)LEASI,CONAME

LEADI,PRLINEADDSI,19ADDSI,2

MOVCX,20LEADI,PRLINELODSW

CLDADDDI,19

REPMOVSBSTD

REPMOVSB

(4)LEADI,PRLINE(5)LEADI,CONAME

ADDDI,5MOVAL,20H

STOSWMOVCX,20

CLD

REPNESCASB

JNZNO-FOUND

MOVBH,AL

…….

NO-FOUND:

3.31

(1)CLD

(2)LEADI,STUDENT_ADDR

MOVCX,132MOVAL,‘-’

MOVAL,20HMOVCX,9

LEADI,PRINT_LINECLD

REPSTOSBREPNESCASB

第一个‘—’在DI-1中

(3)LEADI,STUDENT_ADDR+8STD

MOVAL,‘-’REPNESCASB

MOVCX,9最后一个‘-’在DI-1中

(4)LEADI,STUDENT_NAME(5)CLD

MOVAL,20HMOVCX,30

MOVCX,30LEASI,STUDENT_NAME

CLDLEADI,PRINT_LINE

REPESCASBREPMOVSB

JNENO-MATCHSTD

MOVCX,30MOVCX,9

LEADI,STUDENT_NAMELEASI,STUDENT_ADDR+8

MOVAL,‘﹡’LEADI,PRINT_LINE+131

REPSTOSBREPMOVSB

NO-MATCH:

HLT

3.35

AX

BX

JB

JNB

JBE

JNBE

JL

JNL

JLE

JNLE

1F52H

×

88C9H

FF82H

007EH

58BAH

020EH

FFC5H

FF8BH

09A0H

1E97H

8AEAH

FC29H

D367H

32A6H

3.37

MOVAL,STATUS

TESTAL,00101010B

JZROUTINE-4;

当全为0时

JPROUTINE-2;

偶转移,当有2个1时(0的情况前一条已经跳转)

CMPAL,00101010B

JZROUTINE-1;

当为3个1时

JMPROUTINE-3;

剩余情况,1个1时。

3.39

(1)

(2)

0400H

0A00H

(3)(4)

0100H

B200H

0A00H

0400H

0100H

B200H

(5)(6)

0C00H

(7)(8)

(9)

0600H

1000H

(1)LEASI,CONAME

LEADI,PRLINE

MOVCX,20

CLD

(2)LEASI,CONAME+19

LEADI,PRLINE+19

STD

(3)LEASI,CONAME+3

LODSB

MOVAH,AL

(4)LEADI,PRLINE+5

STOSB

MOVAL,AH

(5)LEADI,CONAME

MOVAL,20H

REPNZSCASB

JNZNOFOUND

MOVBH,20H

************************************

3.30P112

LEADI,STRING

MOVCX,18

MOVAL,'

&

'

DECDI

MOV[DI],20H

(1)LEASI,PRINT_LINE

MOVCX,132

REPLODSB

(2)LEADI,STUDENT_ADDR

MOVCX,9

_'

(3)LEADI,STUDENT_ADDR+8

(4)LEASI,STUDENT_NAME

MOVCX,30

AGA:

CMPAL,20H

JZNEXT

JMPSHORTNEXT1

NEXT:

LOOPAGA

NEXT1:

JNZEXIT

LEADI,STUDENT_NAME

*'

REPSTOSB

EXIT:

(5)LEASI,STUDENT_NAME

LEADI,PRINT_LINE

LEASI,STUDENT_ADDR+8

LEADI,PRINT_LINE+131

3.32

LEASI,OLDS

LEADI,NEWS

MOVCX,5

REPZCMPSB

JNZNEW_LESS

3.33

(1)CMPDX,CX

JAEXCEED

(2)CMPBX,AX

JGEXCEED

(3)CMPCX,0

JZZERO

(4)CMPBX,AX

JOOVERFLOW

(5)CMPBX,AX

JLEEQ_SMA

(6)CMPDX,CX

JBEEQ_SMA

3.34

(1)L1

(2)L1

(3)L2

(4)L5

(5)L5

(1)JNBJBEJNLJLE

(2)JNBJBEJNLJLE

(3)JNBJNBEJLJLE

(4)JNBJNBEJNLJNLE

(5)JNBJNBEJNLJNLE

(6)JBJBEJLJLE

(7)JBJBEJLJLE

(8)JNBJNBEJLJLE

3.36

2P>

=qAX=1

2p<

qAX=2

MOVAL,STATUS

NOTAL

TESTAL,2AH

JZROUTINE_1

TESTAL,0AH

JZROUTINE_2

TESTAL,22H

TESTAL,28H

TESTAL,02H

JZROUTINE_3

TESTAL,08H

TESTAL,20H

JMPROUTINE_4

3.38

(1)LOOPL20

AX=5BX=10HDX=0CX=0

(2)LOOPEL20

AX=2BX=4DX=1CX=3

(3)LOOPNEL20

AX=3BX=7DX=0CX=2

第5章作业答案

5.1

datareasegment

mess1db'

Pleaseinputletter:

13,10,'

$'

mess2db'

Pleaseinputagain:

datareaends

programsegment

mainprocfar

assumecs:

program,ds:

datarea

start:

pushds

subax,ax

pushax

movax,datarea

movds,ax

leadx,mess1

movah,09

int21h

input:

movah,07

cmpal,61h

jbagain

cmpal,7Ah

jaagain

subal,20h

movdl,al

movah,02

jmpshortexit

again:

leadx,mess2

jmpshortinput

exit:

ret

mainendp

programends

endstart

5.2

stringdb'

chinasdujlp'

prognamsegment

prognam,ds:

datarea,es:

movax,datarea

moves,ax

leadi,string

movah,01

movcx,11

cld

repnzscasb

jzfind

jmpinput

find:

subdi,2

movcx,3

lop:

movdl,[di]

incdi

deccx

jzexit

jmpshortlop

prognamends

5.3

movax,1234h

movcl,4

rolax,cl

anddl,0fh

adddl,30h

rolax,cl

movch,al

andch,0fh

movbl,al

andbl,0fh

addbl,30h

andal,0fh

addal,30h

movdh,al

movcl,ch

addcl,30h

movdl,cl

movdl,bl

movdl,dh

moval,dh

5.5

5.6

Mdb-3,-2,-1,-8,-5,0,-9,-23,-100,-52,-1,-19,-18,-3,32,-4,-6,-17,11,24

Pdb20dup(?

Ndb20dup(?

movdh,0

movdl,0

movdi,20

movbx,0

cmpM[bx],0

jlless

incdh

movch,M[bx]

movP,ch

incP

jmpnext

less:

inc

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