ANSYS热应力分析经典例题Word文件下载.docx
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allsel
$outpr,basic,all
solve
$finish
/post1
$Set,last
/plopts,info,on
Plnsol,temp
$Etchg,tts
$Keyopt,1,6,1
Mp,ex,1,220e9
$Mp,alpx,,1,3e-6
$Mp,prxy,1,0.28
$Cp,8,ux,all
Lsel,s,,,2
$Cp,9,ux,all
Allsel
$Antype,static
D,all,uy,0
$Ldread,temp,,,,,,rth
$Solve
/post1
/title,radialstresscontours
Plnsol,s,x
/title,axialstresscontours
Plnsol,s,y
/title,circularstresscontours
Plnsol,s,z
/title,equvialentstresscontours
Plnsol,s,eqv
$finish
/filname,exercise1-zhijie
$Et,1,plane13
Keyopt,1,1,4
$Keyopt,1,3,1
$Mp,alpx,,1,3e-6
MP,KXX,1,70
$Nsll,s,1
ALLSEL
$Finish
318页实例2——冷却栅管的热应力分析
图中为一冷却栅管的轴对称结构示意图，其中管内为热流体，温度为200℃，压力为10Mp,对流系数为110W／（m2•℃）；
管外为空气，温度为25℃，对流系数为30w／（mz．℃）。
栅管材料参数如表13—2所示，求栅管内的温度场和应力场分布。
根据对称性，并在图示边界线段上施加对称边界约束，进行热应力分析求解。
FINISH
$/CLEA
/filname,exercise2
/title,thermalstressesinanaxisymmetricalpipe
$et,1,plane13
$Keyopt,1,1,4
mp,ex,1,200e9
$Mp,alpx,1,1.5e-5
mp,prxy,1,0.3
$mp,kxx,1,30
rectang,0.12,0.16,0,0.07
$rectang,0.16,0.4,0.025,0.045$rectang,0.38,0.4,0.015,0.055
k,100,0.15,0.055
$k,101,0.15,0.015
aadd,all
$numcmp,line
lfillt,8,12,0.01
$lfillt,7,9,0.01
ldiv,9,0.8
$ldiv,12,0.8
L2tan,12,-6
$L2tan,9,5
al,15,16,17
$al,18,19,20
al,14,22,23
$al,13,21,24
aadd,1,2,4
$aadd,5,6
aadd,1,3
$numcmp,line
esize,0.0025
$wpstyle,,,,,,,,1
csys,4
$kwpave,100
wprot,0,0,90
$asbw,2
wprot,0,90
$asbw,3
kwpave,101
$asbw,4
kwpave,16
$wprot,0,-90
$asbw,5
kwpave,19
$asbw,6
kwpave,12
$asbw,7
amesh,1,3
$amesh,5,8,3
amap,4,15,16,18,17
$amap,6,19,20,9,12
$wpstyle,,,,,,,,0
csys,0
$nsel,s,loc,y,0
cp,1,uy,all
$allsel
$antype,static
Sfl,3,pres,10e6
$Sfl,3,conv,110,,200
Lsel,s,,,4,18
$Lsel,a,,,20,21
Sfl,all,conv,30,,25
$Lsel,s,,,17,20,3
Dl,all,,symm
$lsel,s,,,18,21,3
$allsel
Outpr,basic,all
$Solve
$Set,last
/title,temperaturecontours
Plnsol,temp
/title,sumdisplamentlcontours
Plnsol,u,sum
/expand,9,axis,,,10
/view,1,1,1,1
/title,temperaturecontours
332页实例3——两无限长平扳热膨胀分析：
有两块厚度均为0.02mm的无限长平板1和2，受如图13—52所示约束。
平板初始温度为20℃，求将其加热到800℃时平板内部的应力场分布（平板材料参数见表）。
根据题意，忽略平板沿长度方向的端面效应，将问题简化为平面应变问题。
在分析过程中取两平板的横截面建立几何模型，并选取plane13热一结构锅台单元进行求解。
/filname,exercise3
/title,thermalexpansionbetweentwoinfiniteflat
$et,1,plane13
$Keyopt,1,1,4
mp,alpx,1,1.5e-5
$mp,ex,1,1.0e11
mp,prxy,1,0.25
$mp,kxx,1,65
mp,prxy,2,0.3
$mp,ex,2,2.0e11
mp,kxx,2,30
$mp,alpx,2,2.5e-5
rectng,0,0.1,0,0.02
$rectng,0.1,0.3,0,0.02
esize,0.02
$mat,1
$amesh,1
$mat,2
$amesh,2
nummrg,all
$numcmp,all
Autots,on
$lsel,s,,,4,6,2
Nsll,s,1
$d,all,ux
Tref,20
$bfunif,temp,800
$solve
/title,xdirectiondisplamentcontours
Plnsol,u,x
/title,ydirectiondisplamentcontours
Plnsol,u,y
/title,sumdirectiondisplamentcontours
/title,xdirectionstresscontours
/title,ydirectionstresscontours
340页实例4——包含焊缝的金属板热膨胀分析
某一平板由钢板和铁板焊接而成，焊接材料为铜，平板尺寸为1×
1×
0.2，横截面结构如图13—68所示。
平板初始温度为800℃，将平板放置于空气中进行冷却，周围空气温度为30℃，对流系数为110W／（m2．℃）。
求10分钟后平板内部的温度场及应力场分布（材料参数见表134）。
属于瞬态热应力问题，选择整体平板建立几何模型，选取solid5热一结构耦合单元进行求解。
/filname,exercise4
/title,thermalstressesinsecti*****includingweldingseam
$et,1,plane13
$et,2,solid5
Mp,alpx,1,1.06e-5
$mp,kxx,1,66.6
Mp,dens,1,7800
$mp,c,1,460
Mptemp,,30,200,400,600,800
Mpdata,ex,1,,2.06e11,1.92e11,1.75e11,1.53e11,1.25e11
Mpdata,prxy,1,,0.3,0.3,0.3,0.3,0.3
Tb,bkin,1,5
!
指定材料模型
Tbtemp,30
$Tbdata,1,1.40e9,2.06e10
Tbtemp,200
$Tbdata,1,1.330e9,1.98e10
Tbtemp,400
$Tbdata,1,1.15e9,1.83e10
Tbtemp,600
$Tbdata,1,0.92e9,1.56e10
Tbtemp,800
$Tbdata,1,0.68e9,1.12e10
MP,ALPX,2,1.75E-5
$MP,KXX,2,383
MP,DENS,2,8900
$MP,C,2,390
MPDATA,EX,2,,1.03E11,0.99E11,0.90E11,0.79E11,0.58E11
MPDATA,PRXY,2,,0.3,0.3,0.3,0.3,0.3
TB,BKIN,2,5
TBTEMP,30
$TBDATA,1,0.9E9,1.03E10
TBTEMP,200
$TBDATA,1,0.85E9,0.98E10
TBTEMP,400
$TBDATA,1,0.75E9,0.89E10
TBTEMP,600
$TBDATA,1,0.62E9,0.75E10
TBTEMP,800
$TBDATA,1,0.45E9,0.52E10
MP,ALPX,3,5.87E-6
$MP,KXX,3,46.5
MP,DENS,3,7000
$MP,C,3,450
MPDATA,EX,3,,1.18E11,1.09E11,0.93E11,0.75E11,0.52e11
MPDATA,PRXY,3,,0.3,0.3,0.3,0.3,0.3
TB,BKIN,3,5
$TBDATA,1,1.04E9,1.18E10
$TBDATA,1,1.01E9,1.02E10
$TBDATA,1,0.91E9,0.86E10
$TBDATA,1,0.76E9,0.69E10
$TBDATA,1,0.56E9,0.51E10
K,1
$K,2,0.5
K,3,1
$K,4,0,0.2
K,5,0.4,0.2
$K,6,0.6,0.2
$K,7,1,0.2
A,1,2,5,4
$A,2,3,7,6
CSYS,1
$L,6,5
$AL,2,8,9
MSHKEY,1
$ESIZE,0.05
AMESH,1,3,1
$ESIZE,,10
TYPE,2
$MAT,1
$VOFFST,1,1
MAT,3
$VOFFST,2,1
MAT,2
$VOFFST,3,-1
$ACLEAR,1,3,1
NUMMRG,ALL
$NUMCMP,ALL
$ALLSEL
/SOLU
$ANTYPE,4
TRNOPT,FULL
$TIMINT,1,STRUCT
TIMINT,1,THERM
$TIMINT,0,MAG
TIMINT,0,ELECT
$TINTP,0.005,,,-1,0.5,0.2
TIME,600
$DELTIM,30,10,100
AUTOTS,ON
$KBC,1
OUTRES,,ALL
$BFUNIF,TEMP,800
ASEL,U,,,6,13,7
$NSLA,S,1
SF,ALL,CONV,110,30
$ALLSEL
SOLVE
$FINISH
/POST1
SET,LAST
/TITLE,TEMPERATURECONTOURS
PLNSOL,TEMP
/TITLE,XDIRECTIONDISPLAMENTCONTOURS
PLNSOL,U,X
/TITLE,YDIRECTIONDISPLAMENTCONTOURS
PLNSOL,U,Y
/TITLE,ZDIRECTIONDISPLAMENTCONTOURS
PLNSOL,U,Z
/TITLE,SUM
DIRECTIONDISPLAMENTCONTOURS
PLNSOL,U,SUM
/TITLE,XDIRECTIONSTRESSCONTOURS
PLNSOL,S,X
/TITLE,YDIRECTIONSTRESSCONTOURS
PLNSOL,S,Y
/TITLE,ZDIRECTIONSTRESSCONTOURS
PLNSOL,S,Z
/TITLE,EQUVIALENTDIRECTIONSTRESSCONTOURS
PLNSOL,S,EQV
353页:
实例5——连杆热应力分析
图示为一连杆，其初始温度为100℃，现将连杆放置于空气中进行冷却，周围空气温度为20℃，对流系数为95W／（m2•℃）。
求：
1）5分钟后平板内部的温度场及应力场分布；
2）A、B两点温度随时间的变化关系曲线（材料参数见表13—5）。
该问题属于瞬态热应力问题，选取连杆建立几何模型，并选强solid98十节点四面体热结构耦合单元进行求解。
/filname,exercise5
/title,thermalstressanalysistoaconnectingrod
$Et,1,solid98
Mp,alpx,1,2.05e-5
$Mp,prxy,1,0.3
Mp,kxx,1,16.3
$Mp,ex,1,220e9
Mp,c,1,300
$Mp,dens,1,7800
K,1,-0.18,0,0
$K,2,-0.18,0.035,0
K,3,-0.14,0.035,0
$L,1,2
L,2,3
$Csys,1
K,4,0.14,135,0
$K,5,0.1,180,0
K,6,0.1,135,0
$L,3,4
L,5,6
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