C语言程序设计现代方法第二版习题答案Word文档格式.docx

C语言程序设计现代方法第二版习题答案Word文档格式.docx

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Dimensions:

%dx%dx%d\n"

length,width,height）;

printf（"

Volume（cubicinches）:

%d\n"

volume）;

Dimensionalweight（pounds）:

（volume+165）/166）;

return0;

}

4.[was#6]Here'

sonepossibleprogram:

inti,j,k;

floatx,y,z;

Valueofi:

i）;

Valueofj:

j）;

Valueofk:

k）;

Valueofx:

%g\n"

x）;

Valueofy:

y）;

Valueofz:

z）;

WhencompiledusingGCCandthenexecuted,thisprogramproducedthe

followingoutput:

5618848

0

6844404

3.98979e-34

9.59105e-39

Thevaluesprinteddependonmanyfactors,sothechaneethatyou'

llgetexactlythesenumbersissmall.

5.[was#10]（a）isnotlegalbecause100_bottlesbeginswithadigit.

8.[was#12]Thereare14tokens:

a,=,（,3,*,q,-,p,*,p,）,/,3,

and;

.

AnswerstoSelectedProgrammingProjects

4.[was#8;

modified]

floatoriginal_amount,amount_with_tax;

Enteranamount:

"

）;

scanf（"

%f"

&

original_amount）;

amount_with_tax=original_amount*1.05f;

Withtaxadded:

$%.2f\n"

amount_with_tax）;

Theamount_with_taxvariableisunnecessary.Ifweremoveit,theprogram

isslightlyshorter:

#include<

floatoriginal_amount;

seanf（"

original_amount*1.05f）;

Chapter3

2.[was#2]

（a）printf（%8.1e"

（b）printf（"

%10.6e"

（e）printf（"

%-8.3f"

（d）printf（"

%6.0f"

5.

respectively.

[was#8]Thevaluesofx,i,andywillbe12.3,45,and.6,

1.[was#4;

intmonth,day,year;

Enteradate（mm/dd/yyyy）:

%d/%d/%d"

month,&

day,&

year）;

Youenteredthedate%d%.2d%.2d\n"

year,month,day）;

3.[was#6;

intmain（void）

intprefix,group,publisher,item,check_digit;

EnterISBN:

%d-%d-%d-%d-%d"

prefix,&

group,&

publisher,&

tem,&

check_digit）;

GS1prefix:

prefix）;

Groupidentifier:

group）;

Publishercode:

publisher）;

Itemnumber:

item）;

Checkdigit:

check_digit）;

/*Thefiveprintfcallscanbecombinedasfollows:

%d\nGroupidentifier:

%d\nPublisher

code:

%d\nItemnumber:

%d\nCheckdigit:

prefix,group,publisher,item,check_digit）;

*/

Chapter4

2.[was#2]NotinC89.Supposethatiis9andjis7.Thevalueof（-i）/jcouldbeeither—1or—2,dependingontheimplementation.Ontheotherhand,thevalueof-（i/j）isalways—1,regardlessoftheimplementation.

InC99,ontheotherhand,thevalueof（-i）/jmustbeequaltothevalueof-（i/j）.

9.[was#6]

（a）638

（b）321

（c）2-13

（d）000

13.[was#8]Theexpression++iisequivalentto（i+=1）.Thevalueofbothexpressionsisiaftertheincrementhasbeenperformed.

2.[was#4]

intn;

Enterathree-digitnumber:

%d"

n）;

Thereversalis:

%d%d%d\n"

n%10,（n/10）%10,n/100）;

Chapter5

2.[was#2]

（a）1

（b）1

（c）1

（d）1

4.[was#4]（i>

j）-（i<

j）

6.[was#12]Yes,thestatementislegal.Whennisequalto5,itdoesnothing,since5isnotequalto-9.

10.[was#16]Theoutputis

onetwo

sincetherearenobreakstatementsafterthecases.

AnswerstoSelectedProgrammingProjects2.[was#6]

inthours,minutes;

Entera24-hourtime:

scanf（"

%d:

hours,&

minutes）;

Equivalent12-hourtime:

if（hours==0）

12:

%.2dAM\n"

minutes）;

elseif（hours<

12）

hours,minutes）;

elseif（hours==12）

%.2dPM\n"

else

hours-12,minutes）;

4.[was#8;

intspeed;

Enterawindspeedinknots:

scanf（"

spee