点阵式LED09数字显示技术.docx
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点阵式LED09数字显示技术
1．实验任务
利用8X8点阵显示数字0到9的数字。
2．电路原理图
图4.25.1
3．硬件系统连线
（1）．把“单片机系统”区域中的P1端口用8芯排芯连接到“点阵模块”区域中的“DR1－DR8”端口上；
（2）．把“单片机系统”区域中的P3端口用8芯排芯连接到“点阵模块”区域中的“DC1－DC8”端口上；
4．程序设计内容
（1）．数字0－9点阵显示代码的形成
如下图所示，假设显示数字“0”
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00003E4141413E00
因此，形成的列代码为 00H，00H，3EH，41H，41H，3EH，00H，00H；只要把这些代码分别送到相应的列线上面，即可实现“0”的数字显示。
送显示代码过程如下所示
送第一列线代码到P3端口，同时置第一行线为“0”，其它行线为“1”，延时2ms左右，送第二列线代码到P3端口，同时置第二行线为“0”，其它行线为“1”，延时2ms左右，如此下去，直到送完最后一列代码，又从头开始送。
数字“1”代码建立如下图所示
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其显示代码为 00H，00H，00H，00H，21H，7FH，01H，00H
数字“2”代码建立如下图所示
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00H，00H，27H，45H，45H，45H，39H，00H
数字“3”代码建立如下图所示
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00H，00H，22H，49H，49H，49H，36H，00H
数字“4”代码建立如下图所示
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00H，00H，0CH，14H，24H，7FH，04H，00H
数字“5”代码建立如下图所示
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00H，00H，72H，51H，51H，51H，4EH，00H
数字“6”代码建立如下图所示
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00H，00H，3EH，49H，49H，49H，26H，00H
数字“7”代码建立如下图所示
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00H，00H，40H，40H，40H，4FH，70H，00H
数字“8”代码建立如下图所示
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00H，00H，36H，49H，49H，49H，36H，00H
数字“9”代码建立如下图所示
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00H，00H，32H，49H，49H，49H，3EH，00H
5．汇编源程序
TIMEQU30H
CNTAEQU31H
CNTBEQU32H
ORG00H
LJMPSTART
ORG0BH
LJMPT0X
ORG30H
START:
MOVTIM,#00H
MOVCNTA,#00H
MOVCNTB,#00H
MOVTMOD,#01H
MOVTH0,#（65536-4000）/256
MOVTL0,#（65536-4000）MOD256
SETBTR0
SETBET0
SETBEA
SJMP$
T0X:
MOVTH0,#（65536-4000）/256
MOVTL0,#（65536-4000）MOD256
MOVDPTR,#TAB
MOVA,CNTA
MOVCA,@A+DPTR
MOVP3,A
MOVDPTR,#DIGIT
MOVA,CNTB
MOVB,#8
MULAB
ADDA,CNTA
MOVCA,@A+DPTR
MOVP1,A
INCCNTA
MOVA,CNTA
CJNEA,#8,NEXT
MOVCNTA,#00H
NEXT:
INCTIM
MOVA,TIM
CJNEA,#250,NEX
MOVTIM,#00H
INCCNTB
MOVA,CNTB
CJNEA,#10,NEX
MOVCNTB,#00H
NEX:
RETI
TAB:
DB0FEH,0FDH,0FBH,0F7H,0EFH,0DFH,0BFH,07FH
DIGIT:
DB00H,00H,3EH,41H,41H,41H,3EH,00H
DB00H,00H,00H,00H,21H,7FH,01H,00H
DB00H,00H,27H,45H,45H,45H,39H,00H
DB00H,00H,22H,49H,49H,49H,36H,00H
DB00H,00H,0CH,14H,24H,7FH,04H,00H
DB00H,00H,72H,51H,51H,51H,4EH,00H
DB00H,00H,3EH,49H,49H,49H,26H,00H
DB00H,00H,40H,40H,40H,4FH,70H,00H
DB00H,00H,36H,49H,49H,49H,36H,00H
DB00H,00H,32H,49H,49H,49H,3EH,00H
END
6．C语言源程序
#include
unsignedcharcodetab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
unsignedcharcodedigittab[10][8]={ {0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00},//0
{0x00,0x00,0x00,0x00,0x21,0x7f,0x01,0x00},//1
{0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00},//2
{0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00},//3
{0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00},//4
{0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00},//5
{0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00},//6
{0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00},//7
{0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00},//8
{0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00}//9
};
unsignedinttimecount;
unsignedcharcnta;
unsignedcharcntb;
voidmain（void）
{
TMOD=0x01;
TH0=（65536-3000）/256;
TL0=（65536-3000）%6;
TR0=1;
ET0=1;
EA=1;
while
（1）
{;
}
}
voidt0（void）interrupt1using0
{
TH0=（65536-3000）/256;
TL0=（65536-3000）%6;
P3=tab[cnta];
P1=digittab[cntb][cnta];
cnta++;
if（cnta==8）
{
cnta=0;
}
timecount++;
if（timecount==333）
{
timecount=0;
cntb++;
if（cntb==10）
{
cntb=0;
}
}
}
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