机械原理答案修改版.docx
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机械原理答案修改版
之前的版本虽然写着正确的,但实际上还是有错的。
在本人亲自学习的过程中有些错误的地方我修改了;有些指出了错误,但希望学生自己去思考错在了哪里,然后作出正确的解答,不可轻信答案。
答案仅供参考!
NameClassStudentNo.Date
5-1Aplatecamwithpositive-offsettranslatingrollerfollowerhasthefollowingmotion:
arisethroughlifth=40mmwithasineaccelerationmotioncurveduring0=150,S=30,areturnwitha3-4-5polynomialmotioncurveduring0'=120,andS'=60.Thecamrotatesclockwise.AndrP=40mm.rR=12mm,e=12mmandrC=25mm.Constructthepitchcurveandthecamcontourgraphicallywithascaleof1:
1.Labelinredthecenterlineofthefollower,S,therollerandwhen=60and=0.
0
30
60
90
120
150
180
210
240
270
300
330
360
S(mm)
0
1.9
12.3
27.7
38.1
40
40
35.86
20
4.14
0
0
0
记住:
是沿着-w方向画
NameClassStudentNo.Date
5-2Aplatecamwithtranslatingoffsetrollerfollowerhasthesamemotioncurveanddimensionsasexercise5-1has.Writeaprogramtocalculatetheco-ordinatesofthepitchcurve,thecamcontourandthelocusofthecenterofthemillingcutter,andB.
SETWINDOW-100,120,-100,60
LETM=-1
LETN=+1
LETRP=40
LETE=12
LETRR=12
LETRC=25
LETH=40
LETDELTA0=150*PI/180
LETDELTAS=30*PI/180
LETDELTA01=120*PI/180
LETDELTAS1=60*PI/180
LETS0=SQR(RP^2-E^2)
BOXCIRCLE-RP,RP,-RP,RP
BOXCIRCLE-E,E,-E,E
FORI=0TO360STEP.005
LETDELTA=I*PI/180
IFDELTA<=DELTA0THEN
LETDD=DELTA/DELTA0
LETS=H*(DD-1/2/PI*SIN(2*PI*DD))
LETS1=H/DELTA0*(1-COS(2*PI*DD))
LETS11=2*PI*H/DELTA0^2*SIN(2*PI*DD)
ELSEIFDELTA<=(DELTA0+DELTAS)THEN
LETS=H
LETS1=0
LETS11=0
ELSEIFDELTA<=(DELTA0+DELTAS+DELTA01)THEN
LETD4=(DELTA-DELTA0-DELTAS)/DELTA01
LETS=H*(1-10*D4^3+15*D4^4-6*D4^5)
LETS1=-H/DELTA01*(30*D4^2-60*D4^3+30*D4^4)
LETS11=-H/DELTA01^2*(60*D4-180*D4^2+120*D4^3)
ELSE
LETS=0
LETS1=0
LETS11=0
ENDIF
LETXB=M*((S0+S)*SIN(DELTA)+N*E*COS(DELTA))
LETYB=(S0+S)*COS(DELTA)-N*E*SIN(DELTA)
LETXB1=M*(S1*SIN(DELTA)+(S0+S)*COS(DELTA)-N*E*SIN(DELTA))
LETYB1=S1*COS(DELTA)-(S0+S)*SIN(DELTA)-N*E*COS(DELTA)
LETKB=SQR(XB1^2+YB1^2)
LETXT=XB+M*RR*YB1/KB
LETYT=YB-M*RR*XB1/KB
LETXC=XT-M*RC*YB1/KB
LETYC=YT+M*RC*XB1/KB
LETALAFA=ARCTAN(ABS(S1-N*E)/(S0+S))
LETLOUB=((S0+S)^2+(S1-N*E)^2)^1.5/(-(S0+S)*(S11-S0-S)+(S1-N*E)*(2*S1-N*E))
PLOTXB,YB
PLOTXT,YT
PLOTXC,YC
NEXTI
END
NameClassStudentNo.Date
5-3IntheplatecamwithtranslatingoffsetrollerfollowerasshowninFig5-1,GHandIJaretwoarcswithcenteratO.IndicateradiusofprimecirclerP,offsete,camangleforrise0,camangleforouterdwellS,camangleforreturn0',camangleforinnerdwellS'andlifth.InthepositionshowninFig5-1,indicatepressureangle,displacementSandthecorrespondingcamangle.
Fig5-1
这题答案错了;注意几个关键点的位置。
NameClassStudentNo.Date
Fig5-2
5-4IntheplatecamwithtranslatingoffsetrollerfollowerasshowninFig5-2,EA,ABandBCDarethreearcswithcenteratO,NandP,respectively.IndicateradiusofprimecirclerP,offsete,camangleforrise0,camangleforouterdwellS,camangleforreturn0',camangleforinnerdwellS'andindicatelifth,pressureangle,displacementSandthecorrespondingcamangleinthepositionshowninFig5-2,.
这题也错了,自己思考下,类似的错误。
NameClassStudentNo.Date
5-5AplatecamwithanoscillatingrollerfollowersimilartothatinFig.5-36oftextbookistohavethefollowingmotion:
anangularliftMAX=20withasineaccelerationmotioncurveduring0=150,S=30,areturnwitha3-4-5polynomialmotioncurveduring0'=120andS'=60.Thegivendimensionsare:
rP=40mm,LOA=80mm,LAB=76mm,rR=12mmandrC=16mm.Constructthepitchcurveandthecamcontourgraphicallywithascaleof1:
1.LabelinredinktheframeOA,,centrelineABofthefollower,therollerandcorrespondingto=60and=0.
0
30
60
90
120
150
180
210
240
270
300
330
360
0
0.97
6.12
13.9
19.0
20
20
17.93
10
2.07
0
0
0
NameClassStudentNo.Date
5-6Aplatecamwithanoscillatingrollerfollowerhasthesamemotioncurveanddimensionsasexercise5-5has.Writeaprogramtocalculatetheco-ordinatesofthepitchcurve,thecamcontourandthelocusofthecenterofthemillingcutter,thepressureangleandtheradiusofcurvatureBofthepitchcurve.
SETWINDOW-100,120,-100,60
LETM=+1
LETN=+1
LETRP=40
LETRR=12
LETRC=16
LETH=20
LETLOA=80
LETLAB=76
LETDELTA0=150*PI/180
LETDELTAS=30*PI/180
LETDELTA01=120*PI/180
LETDELTAS1=60*PI/180
LETS0=ARCTAN(SQR((2*LOA*LAB)^2-(LOA^2+LAB^2-RP^2)^2)/(LOA^2+LAB^2-RP^2))
BOXCIRCLE-RP,RP,-RP,RP
FORI=0TO360STEP.005
LETDELTA=I*PI/180
IFDELTA<=DELTA0THEN
LETDD=DELTA/DELTA0
LETS=H*(DD-1/2/PI*SIN(2*PI*DD))
LETS1=H/DELTA0*(1-COS(2*PI*DD))
LETS11=2*PI*H/DELTA0^2*SIN(2*PI*DD)
ELSEIFDELTA<=(DELTA0+DELTAS)THEN
LETS=H
LETS1=0
LETS11=0
ELSEIFDELTA<=(DELTA0+DELTAS+DELTA01)THEN
LETD4=(DELTA-DELTA0-DELTAS)/DELTA01
LETS=H*(1-10*D4^3+15*D4^4-6*D4^5)
LETS1=-H/DELTA01*(30*D4^2-60*D4^3+30*D4^4)
LETS11=-H/DELTA01^2*(60*D4-180*D4^2+120*D4^3)
ELSE
LETS=0
LETS1=0
LETS11=0
ENDIF
LETXB=M*(LOA*SIN(DELTA)+N*LAB*SIN(S0+S-N*DELTA))
LETYB=LOA*COS(DELTA)-LAB*COS(S0+S-N*DELTA)
LETXB1=M*(LOA*COS(DELTA)+N*LAB*COS(S0+S-N*DELTA)*(S1-N))
LETYB1=-LOA*SIN(DELTA)+LAB*SIN(S0+S-N*DELTA)*(S1-N)
LETKB=SQR(XB1^2+YB1^2)
LETXT=XB+M*RR*YB1/KB
LETYT=YB-M*RR*XB1/KB
LETXC=XT-M*RC*YB1/KB
LETYC=YT+M*RC*XB1/KB
LETALAFA=ARCTAN(ABS(LAB*(1-N*S)-LOA*COS(S0+S))/(LOA*SIN(S0+S)))
LETK=(1-N*S)*(2-N*S)*COS(S0+S)+S11*SIN(S0+S)
LETLOUB=(LOA^2+LAB^2*(1-N*S1)^2-2*LOA*LAB*(1-N*S1)*COS(S0+S))^1.5/(LOA^2+LAB^2*(1-N*S1)^3-LOA*LAB*K)
PLOTXB,YB
PLOTXT,YT
PLOTXC,YC
NEXTI
END
NameClassStudentNo.Date
5-7Intheplatecammechanismwithoscillatingrollerfollower,thecamisacirclewithcenteratC.IndicateradiusofprimecirclerP,camangleforrise0,camangleforouterdwellS,camangleforreturn0',camangleforinnerdwellS'andangularliftmax.InthepositionshowninFig5-4,indicatepressureangle,angulardisplacementoffollowerandthecorrespondingcamangle.
Fig5-4
NameClassStudentNo.Date
5-8Aplatecamwithatranslatingflat-facedfollowerhasthefollowingmotion:
arisethroughlifth=50mmwithasineaccelerationmotioncurveduring0=150,S=30,areturnwitha3-4-5polynomialmotioncurveduring0'=120andS'=60.Thecamrotatesclockwise.AndrP=50mm.rC=20mm.Constructthepitchcurveandthecamcontourgraphicallywithascaleof1:
1.Labelinredthefollowercenterline,S,theflatface,thetangentpointTbetweenthecamcontourandwhen=60and=0.
0
30
60
90
120
150
180
210
240
270
300
330
360
S(mm)
0
2.43
15.3
34.7
47.57
50
50
44.82
25
5.18
0
0
0
NameClassStudentNo.Date
5-9Aplatecamwithatranslatingflat-facedfollowerhasthesamemotioncurveanddimensionsasexercise5-8has.Writeaprogramtocalculatetheco-ordinatesofthepitchcurve?
?
thecamcontourandthelocusofthecenterofthemillingcutterandT.
LETM=-1
LETRP=40
LETH=40
LETRC=20
LETDELTA0=150*PI/180
LETDELTAS=30*PI/180
LETDELTA01=120*PI/180
SETWINDOW-90,90,-90,40
BOXCIRCLE-RP,RP,-RP,RP
FORI=0TO360STEP0.5
LETDELTA=I*PI/180
IFDELTA<=DELTA0THEN
LETD2=DELTA/DELTA0
LETS=H*(D2-1/2/PI*SIN(2*PI*D2))
LETS1=H/DELTA0*(1-COS(2*PI*D2))
LETS11=2*PI*H/DELTA0^2*SIN(2*PI*D2)
ELSEIFDELTA<=(DELTA0+DELTAS)THEN
LETS=H
LETS1=0
LETS11=0
ELSEIFDELTA<=(DELTA0+DELTAS+DELTA01)THEN
LETD4=(DELTA-DELTA0-DELTAS)/DELTA01
LETS=H*(1-10*D4^3+15*D4^4-6*D4^5)
LETS1=-H/DELTA01*(30*D4^2-60*D4^3+30*D4^4)
LETS11=-H/DELTA01^2*(60*D4-180*D4^2+120*D4^3)
ELSE
LETS=0
LETS1=0
LETS11=0
ENDIF
LETXB=M*(RP+S)*SIN(DELTA)
LETYB=(RP+S)*COS(DELTA)
LETXT=M*((RP+S)*SIN(DELTA)+S1*COS(DELTA))
LETYT=(RP+S)*COS(DELTA)-S1*SIN(DELTA)
LETXB11=+LOA*SIN(DELTA)+LAB*SIN(Q0+Q-DELTA)*(Q1-1)^2
-LAB*COS(Q0+Q-DELTA)*Q11
LETYB11=-LOA*COS(DELTA)+LAB*COS(Q0+Q-DELTA)*(Q1-1)^2
+LAB*SIN(Q0+Q-DELTA)*Q11
LETXT1=M*(S1*SIN(DELTA)+(RP+S)*COS(DELTA)+S11*COS(DELTA)-S1*SIN(DELTA))
LETYT1=S1*COS(DELTA)-(RP+S)*SIN(DELTA)-(S11*SIN(DELTA)+S1*COS(DELTA))
LETXC=XT-M*RC*YT1/SQR(YT1^2+XT1^2)
LETYC=YT+M*RC*XT1/SQR(YT1^2+XT1^2)
LETLOUT=RP+S+S11
PLOTXB,YB
PLOTXT,YT
NEXTI
END
NameClassStudentNo.Date
6-1Apairofstandardinvolutespurgearshaveamoduleof5mm,pressureangle=20,centerdistancea=350mm,transmissionratioi12=9/5.Calculatethenumbersofteeth(Z1andZ2),referencediameters(d1andd2),addendumdiameters(da1andda2),basediameters(db1anddb2),tooththicknesss,spacewidthe,pressureanglesontheaddendumcircles(a1anda2),theradiiofcurvaturesoftoothprofileonthereferencecircles(1and2),andtheradiiofcurvaturesoftoothprofileontheaddendumcircles(a1anda2)..
解:
NameClassStudentNo.Date
6-2Howmanyteethwouldanexternalstandardinvolutespurgearhaswhenitsdedendumcircleanditsbasecirclecoincide?
Whichoneisbiggerasthenumberofteethincreases?
解:
NameClassStudentNo.Date
6-3InFig6-1thereareapairofinvoluteprofilesC1andC2withthecommonnormaln-npassingthroughthecontactpointK.
1)Drawthetwobasecirclesandtwopitchcircles.
2)LabelthetheoreticallineofactionN1N2andactuallineofactionB1B2.
3)Labeltheworkingpressureangle’andpressureangleKatthepointK.
4)LabeltheactualworkingsectionDGoftheprofileC2.
5)FindoutpointM2ontheprofileC2thatwillengagewithpointM1ontheprofile1.
Fig6-1
NameClassStudentNo.Date
6-4InFig6-2thereareapairofinvolutepinionandrackwiththeirpitchcircl