高二学生下学期学习计划化学Sophomore students study plan chemistry next semester 02 23.docx

1、高二学生下学期学习计划化学Sophomore students study plan chemistry next semester 02 23高二学生下学期学习计划化学02月23日（Sophomore students study plan chemistry next semester, 02, 23）The Zhang Bei study program is shared every dayCase (1), 500 (2), C (3), 10, CD, C (4), small, no influence11., in the office or in the living roo

2、m, in a beautiful vase with a bunch of beautiful flowers, will give the nervous and busy work, life brings relaxed and cheerful mood. If you add a fresh flower preservative to the vase, it will extend the life of the flower. The following is the ingredients for 1 L flower preservative. After reading

3、, answer the following questions:componentMass /gThe molar mass (g / Mol1)sucroseFiftyThree hundred and twelvePotassium sulphateZero point five zeroOne hundred and seventy-fourAspirinZero point three fiveOne hundred and eightypotassium permanganateZero point five zeroOne hundred and fifty-eightsilve

4、r nitrateZero point zero fourOne hundred and seventy(1) flower antistaling agent in the amount of substance concentration of the largest component is _ (name).(2) the content of K + in flower preservative is (aspirin contains no K +)_mol. L - 1 (just write an expression and dont need to compute it).

5、(3) during the preparation process, the following is the _ does not affect the result of preparation (fill).The A. volumetric flask is not dried before use and contains a small amount of distilled waterLook up the liquid level when the B. is fixedC. capacity bottle, before use, just finished the con

6、centration of a certain amount of substance NaCl solution, but not washedWhen the D. is fixed and shaken, the liquid level is lower than the calibration line of the capacity bottle, but no treatment is done(4) to determine the concentration of fresh flower antistaling agent silver nitrate, should co

7、ntain _ reagent added in (filling chemical symbol).Analysis (1) calculated according to the formula: C = n/V. (2) to calculate the concentration of potassium sulfate and Potassium Permanganate, you can find the C (K). (3) A did not affect B; constant volume up to level solution volume, the concentra

8、tion of NaCl solution is small; the C can react with silver nitrate; the D level is lower than the scale line capacity of bottle that part of residual liquid in the bottle mouth and the wall, then do not handle.Answer (1) sucrose (2) + 2 * (3) AD (4) ClOneFourth unit oxidation-reduction reactionFirs

9、t, the multiple-choice question1. oxidation reduction reactions are widely used in production and life. The following examples of production and life do not contain redox reactions.A. metal smelting, B. setting off firecrackers, C. food spoilage, D. point tofuAnalysis of tofu point system belongs to

10、 the accumulation of colloid, is a physical change.Answer D2. known: KMnO4 crystal to add concentrated hydrochloric acid to produce yellow green gas; gas to the FeCl2 solution into a large number of experiments of the solution takes yellow; experiment II generation solution drops in KI containing st

11、arch, litmus blue. The following is true ().The experiment proved that A. oxidation: MnO + I2 Cl2 B. in the above experiments, there are two redox reactionsThe gas produced by C. experiment can not make the moist starch KI test paper blueD. experiment proved that both oxidation and Reduction Reducti

12、onAccording to the problem of analytic knowledge generated in chlorine, Cl is oxidized to Cl2, KMnO4 as oxidant, Cl2 as oxidation products. FeCl2 was oxidized to FeCl3 by Cl2, and I was oxidized by FeCl3 to form I2. According to the redox reaction rules: oxidation: MnO Cl2 Fe3 I2 + A, right; the thr

13、ee reaction is a redox reaction, the oxidation of KI and Cl2 can also generate I2, the experiment only shows that Fe2 + reduction.Answer AThe 3. known Co2O3 in acidic solution is easily reduced to cobalt ions, oxidative Co2O3, Cl2, FeCl3 and I2 decreased in turn. The following reactions that are unl

14、ikely to occur in aqueous solutions are ()A.3Cl26FeI2=2FeCl34FeI3B.Cl2FeI2=FeCl2I2C.Co2O36HCl=2CoCl2Cl2 = 3H2OD.2Fe32I=2Fe2I2Analysis of the test to determine the strength of using oxidative reaction, oxidation of Co2O3, Cl2, the FeCl3, I2 isattenuated, so Cl2 Fe2 can be oxidized to Fe3 + and I - +

15、and I2, and I Co2O3 can be oxidized, Cl oxidation of Cl2, Fe3 + I can be oxidation generate I2, so A is not correct.Answer A4., I known SO2, Cl -, Fe2 +, H2O2 were reduced in acidic solution, reducing the strength of the order of ClFe2H2O2I Fe2 +, to do; if B can occur, while reducing SO2 I, to do;

16、if C can occur, while reducing H2O2, SO2, and the title to restore the sequence of number does not match, so the C reaction can occur if D can occur; then, reducing I, Fe2 +, with their.Answer C5.LiAlH4 is a kind of metal hydrogen storage material and a common reagent in organic synthesis. When hydr

17、ogen reacts with water, it releases hydrogen gas, and LiAlH4 decomposes into LiH, H2 and Al at 125 DEG C. The following statement is wrong ()A.LiAlH4 and acetaldehyde act as ethanol and LiAlH4 as reducing agentB.LiAlH4 and D2O reaction, molar mass of hydrogen from the 4 g - Mol1C.1 mol LiAlH4 comple

18、tely decomposes at 125 DEG C and transfers 3 mol electronsThe reaction of D.LiAlH4 with water to generate three kinds of substances, the chemical equation can be expressed as: LiAlH44H2O=Al (OH) 3LiOH4H2 haveExplicit analytical LiAlH4 1 price of hydrogen, with strong reducibility; A, acetaldehyde, e

19、thanol, reducing reaction, correct; B, essence of the hydrogen is LiAlH4 1 H and D2O price + 1 valence D to generate HD gas, the molar mass is 3 G - mol 1, C, Al3 + error; generate Al, transfer 3E, D, right; the reaction is equivalent to the hydrolysis of Al (OH) 3 soluble in acid and alkali insolub

20、le in water, LiOH is alkali, insoluble, right.Answer B6. the efficient water treatment agent ClO2 was prepared in the laboratory by the following reaction: 2KClO3 + H2C2O4 +H2SO4=2ClO2 = K2SO42CO2 = 2H2O, which of the following statements is not true ()A.CO2 is the product of oxidationThe B.1 mol KC

21、lO3 participated in the reaction with an electron transfer of 1 molC.KClO3 is oxidized in the reactionThe reducibility of D.H2C2O4 is stronger than that of ClO2In the analytic reaction, the Cl element is changed from + 5 (KClO3) to + 4 (ClO2), and the C element is changed from + 3 (H2C2O4) to + 4 (C

22、O2), so CO2 is the product of oxidation, and ClO2 is the product of reduction. KClO3 is used as an oxidant and is reduced in the reaction.Answer CThe reaction occurred in 7. Na2S solution was added dropwise to the amount of substance concentration of FeCl3 solution, Na2S solution: 2Fe3S2=2Fe2S down;

23、 concentration of FeCl3 solution was added dropwise and other substances in the reaction: 2Fe33S2=Fe2S3 down. The following statement is wrong ().A.Fe3 in the acidic environment of strong oxidation resistanceB.S2 strong reduction in alkaline environmentThe solubility of Fe (OH) 3 is larger than that

24、 of C. at the same temperature of Fe2S3D. into FeCl3 solution into H2S, there is sulfur precipitationThe analytical solution of FeCl3 Na2S is acidic, alkaline solution, reaction of the former in the question in the acid solution reaction, which showed that A and D correctly; the latter reaction in a

25、lkaline solution, generating more insoluble Fe2S3, B error, C.Answer BTwo. Non choice questions8. under the condition of high temperature, chalcocite (the main component of Cu2S) through the amount of air can be smelt metal copper, through a series of reactions can be B and D, E. G is a brick red pr

26、ecipitate.Please answer the following questions:(1) chalcocite (Cu2S) through the amount of copper smelting metal air chemical equation _, the oxidant is _.(2) chemical formula E concentrated solution reacts with Cu II is _.(3) the use of electrolytic copper refining, in the electrolytic reaction in

27、 the anode material is _, electrolyte solution is _.(4) when the iron ore and pyrite in the nature of bile (main ingredient FeS2) meet the slow reaction of chalcocite, the reaction is: 14CuSO4 + 5FeS2 + 12H2O=7Cu2S + 5FeSO4 + 12H2SO4, is the quality of the oxidized sulfur and sulfur reduction ratio

28、of _.The analysis first finds out the substances participating in the reaction and judges the products, and then analyzes the characteristics of the redox reaction. (1) according to the Cu2S icon, and O2 reaction for the redox reaction with B can react with O2 to generate D and D react with water to

29、 produce E, E and Cu can generate reaction B, B SO2, D SO3, E H2SO4, the reaction is: Cu2SO2 (moderate) high temperature (high temperature should 2CuSO2). The reaction of Cu, the valence of O is reduced, so the oxidation agent is O2 and Cu2S. (2) E is sulfuric acid, and can react with Cu, but concen

30、trated sulfuric acid. (3) when the copper is refined by electrolysis, the coarse copper is used as anode, and the salt solution containing Cu2 + is used as electrolyte solution. (4) according to the mass ratio of the oxidized sulfur and the reduced sulfur is 3: 7.Answer (1) Cu2SO2 (moderate) high te

31、mperature (high C) and Cu2S O2 2CuSO2(2) Cu2H2SO4 (concentrated) Delta (delta) = 2H2O CuSO4SO2)(3) crude copper sulfate or salt solution containing Cu2 + (4) 3: 7;9. miniature chemical experiments can effectively reduce pollution and realize green chemistry experiment, some students do a test according to the following: different positions of glass lining paper respectively adding concentration of 0.1 mo