1、3.P=1,2,3,4;3,0,1,2;max(P)=4.y=0; i=1;while i5 f=2*i;y=y+f;i=i+1;A=1,2,3,4;4,3,2,1;1, -2 ,1, -2;B=3,1,-1;0,4,2;A1=A(:,1 3);M=size(A1)+ len gth(B(:,2)将下列命令的运行结果填在横线上M= ;A1+B = 2.A=1,2,3,4;2,3,4,5;3,4,5,6;A1=sum(A4,2);A(2,3,:)=,A2=A院学A1 = ; A2= ;mean(P,2)= 5.a=;for i=1:3; for j=i: a(i,j)=i*(a(i)1OO cj
2、(i,j)=1OO;elseif cj(i,j)0 cj(i,j)=0;endkmea n=roun d(mea n(cj)disp(课程1 课程2 课程3 课程4disp(sprintf( %4d%8d%8d%8d ,kmean(1),kmean(2),kmean(3),kmean(4)stude ntmea n=roun d(mea n( cj,2);stude ntnu mber=1:80;stude ntnu mber, stude ntmea nc=sum(sum(cj60)d=sum(sum(cj=3)七、(10分)(1).fu nction y=fourier(x ,n) ny=y+si n( (2*i-1)*x)/(2*i-1);y(2).x=0:pi/20:4*pi;y1=fourier(x,10);y2= fourier(x,20);subplot(211),plot(x,y1)subplot(212),plot(x,y2)1 2 3 2 0 0设 A 3 2 1 ,B 7 5 0 ,5 1 2 1 2 6(1).D |(At B)(A 2B) 1 |; (2) .A 的秩 R R(B(A B)AT);(3).解矩 阵方程BX 2BtA 1B 5E; (4).求A 2B的特征值U与特征向量V;