有用的小学到初中所有数学公式大全Word文件下载.docx

有用的小学到初中所有数学公式大全Word文件下载.docx

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Volume=edgelengthxxlong*xV=axa*a

3,rectangle:

Cperimeter,Sarea,a,sidelength,perimeter=（length+width）*2C=2（a+b）area=**widthS=ab

4,cuboid

V:

volumes:

areaa:

long,b:

width,h:

height

（1）surfacearea（length*width+length*height+width*height）*2S=2（ab+ah+bh）

（2）volume=long*width*highV=abh

5,triangle

Sahhighendareabottomarea=xheight/2s=ah/2

Triangleareahigh=x2/bottom

Trianglearea=x2/high

6,parallelogram:

sareaa,bottomh,higharea=bottom*highs=ah

7,ladder:

sareaabhhighbottombottomarea=（+downonthebottomend）*/2s=（a+b）*H/2

8round:

SCd=r=diameterradiuscircumferencepi

（1）==2***perimeterdiameterradiusC=d=2pipipi*r

（2）***area=radiusradius

9,cylinder:

V,volumeh:

highS:

bottomareaR:

bottomradiusC:

bottomperimeter

（1）thesidearea=thecircumferenceofthebottom*high

（2）surfacearea=sidearea+basearea*2

（3）volume=basearea*height

（4）=2/Xvolumesidearearadius

10,V:

hshighvolumeconebottomareaRbottomradiussize=baseareaxheight/3

Thetotal,thetotalnumberofcopies=averagenumber

Equationofsumanddifference

（+anddifference）830192=number

（andpoor）830192=decimal

Doublingproblem

And（1=decimalmultiples）.

Decimal=multiple=largenumber

（orsum=decimal=largenumber）

Differenceproblem

（1/differencemultiples）=decimal

（ordecimal+difference=largenumber）

Treeplantingproblem

1,theproblemoftreeplantingonnonclosedlinescanbedividedintothefollowingthreecases:

Ifanonclosedlineatbothendsareplantingtrees,so:

Number=numberof+1/1=lengthspacing

*（1=lengthspacingnumber）

Fulllength（1/spacing=number）

Ifyouwanttoplanttreesintheendofnonclosedline,theotherendisnotplanting,so:

Number=number=length/spacing

Length=xnumberofrows

=length/numberofrows

Ifbothendsinnonclosedlinearenotplantingtrees,so:

Numbersectionnumber=-1/1=lengthspacing

*（number=lengthspacing+1）

=length/spacing（number1）

2,thenumberoftreesonclosedlinesisasfollows

Profitandloss

（profit+loss）,thetwodistributionofthedifferencebetweenthenumberofcopiesinthedistributionof=

（largesurplus-smallsurplus）/twodistributionofthedifferencebetweenthenumberofcopiesinthedistributionof=

（burned-asmalllossoftwotimes）,thedifferencebetweenthenumberofcopiesisassignedtoparticipateinthedistributionofthe

Encounterproblem

Encounterdistance=speedandXmeetingtime

Meettime=distance/speedandmeet

Thespeedanddistance,theencountertime=meet

Catchupwithproblems

Trackingdistance=speeddifference*trackingtime

Chaseandchaseanddistance/time=speeddifference

Thespeeddifferenceanddistance=chasechaseandtime.

Flowproblem

Downstreamvelocity=hydrostaticvelocity+flowvelocity

Countercurrentvelocity=hydrostaticvelocity-flowvelocity

Hydrostaticspeed=（downstreamvelocityandvelocity）,2

Flowrate=（downstreamspeedvelocity）,2

Concentrationproblem

Theweightofthesolute+theweightofthesolvent=theweightofthesolution

Theweight,theweightofthesolutesolutionx100%=concentration

Weightofsolution=concentration=soluteweight

Theweight,concentrationofsolutesolution=weight

Profitanddiscountproblems

Profit=sellingprice-cost

Therateofprofit,profit=costX100%=（sold/cost1）*100%

Amountoffluctuation=principal*ChangePercentage

Theactualpricediscount,theoriginalpricex=100%（<

1discount）

Interest=principal*interestrate*time

Aftertaxinterestrates***=principaltime（120%）

LengthConversion

1kilometers1meters=1000meters=10.

1cm=100cm=101meterdecimeter

1cm=10mm

AreaConversion

1sqkm=100hectares

1hectares=10000squaremeters

1squaremeters=100squaredecimeter

1square=100squarecentimeterdecimeter

1mm2=100mm2

Volume（volume）productunitconversion

1cubicmeters=1000cubicdecimeter

1cubicmeter=1000cubiccentimeter

1DM3=1L

1cubiccentimeter=1ml.

1cubicmeters=1000liters

Weightunitconversion

1tons=1000kg

1kilograms=1000grams

1kg=1kg

UnitconversionofRenminbi

1yuan=10Jiao

1jiao=10minutes

1yuan=100cents

timeconversion

FirstCentury=100,1years=12months

Month（31days）:

1\3\5\7\8\10\12month

Xiaoyue（30days）are:

4\6\9\11month

Thereare28daysinFebruary,aleapyear29daysinFebruary

Thereare365daysayear,aleapyear366daysayear

1days=24hours,1hours=60minutes

1minutes,=60seconds,1hours,=3600seconds

Mathematicalformulasofgeometry,perimeter,areaandvolumeofPrimaryMathematics

1,theperimeteroftherectangle=（long+width）*2C=（a+b）*2

2,squareperimeter=sidelength*4C=4a

3,rectangulararea=long*widthS=ab

4,squarearea=lengthside*sidelengthS=a.a=a

5,thebottomofthetrianglearea=xheight/2S=ah/2

6.Theareaoftheparallelogram=bottom*highS=ah

Area=7,trapezoidal（bottom+bottom）xheight/2S=（a+b）H/2

8x2d=2rdiameter=radiusradius=2D/2r=diameter.

9,thecircumferenceofacirclediameterx=pi=pi**2c=D=2radiusPiPiR

10,theareaofacircleradiusradius=pi**

Commonformulasforjuniorhighschoolmathematics

1thereisonlyonelineaftertwo

2thelinebetweentwopointsistheshortest

3thesameangleorisometricequalmargin

4withtheangleofthecomplementofequalorconstant

5havingonlyonelineandperpendiculartotheknownline

6,thelineoutsideapointandthelineonallpointsconnectedbytheline,theverticallinesegmentistheshortest

7parallelaxiomsfollowapointoutsidethestraightlineandhaveonlyonelineinparallelwiththeline

8ifthetwolinesareparalleltothethirdlines,thetwolinesareparalleltoeachother

9correspondinganglesareequal,thetwoparallellines

10alternateanglesareequal,thetwoparallellines

11complementaryinterioranglesonthesameside,twoparallellines

12thetwoparallellines,correspondinganglesareequal

13twolineparallel,alternateanglesareequal

14thetwoparallellines,complementaryinterioranglesonthesameside

Thesumof15sidesofatriangleisgreaterthanthird

16inferthatthedifferencebetweenthesidesofatriangleislessthanthird

17triangletrianglesumtheoremthreeanglesandequalto180degrees

18inference1thetwoacuteanglesofrighttriangleoverlapeachother

19acorollaryofatriangleisequaltothe2cornersandtwoanglesitisadjacentand

20acorollaryofatrianglewith3cornersthananyoneanditisnotadjacent.

Thecorrespondingsidesof21congruenttrianglesandequalangles

22edgeaxioms（SAS）arecongruentwithtwotrianglesofequalanglesonbothsidesandtheirangles

23cornercorneraxiom（ASA）hastwotrianglescongruenthornsandtheiredgescorrespondingtotheequal

24inference（AAS）hadtwohornsandoneoftheangleonthesidecorrespondingtotheequaltwocongruenttriangles

25sideaxioms（SSS）havingtwoequaltrianglesequaltothreesides

26bevelandrightsideaxioms（HL）havetwoequalanglesofrighttriangleandonerightangle

Congruent

27theorem1thedistancebetweenpointsonthebisectorofanangletothesidesofthisangleisequal

Thepointatwhichthedistancebetween2and28anglesisthesameasinthebisectorofthisangle

Thebisectorof29anglesisthesetofallpointsequaltothetwosidesoftheangle

Twoand30areequalisoscelestriangletheoremofanisoscelestriangle（i.e.equalequilateralangle）

31inferthatthebisectorofthe1isoscelestrianglevertexisequaltothebaseandperpendiculartothebase

32thetopanglesoftheisoscelestriangle,thebisector,themiddlelineonthebottomedgeandtheheightonthebottomedgecoincidewitheachother

33corollary3equilateraltriangleswhoseanglesareequal,andeachangleequalto60degrees

34thedecisiontheoremofisoscelestriangle,ifatrianglehastwoanglesequal,thenthesetwoangles

Theoppositesidesareequal（equalangles,equalsides）

35corollary1threeanglesareequaltriangleisanequilateraltriangle

36corollary2anisoscelestrianglewithanangleequalto60degreesisanequilateraltriangle

37inarighttriangl