机械专业毕业设计论文外文翻译连杆机构文档格式.docx

上传人:b****5 文档编号:20591458 上传时间:2023-01-24 格式:DOCX 页数:14 大小:79.21KB
下载 相关 举报
机械专业毕业设计论文外文翻译连杆机构文档格式.docx_第1页
第1页 / 共14页
机械专业毕业设计论文外文翻译连杆机构文档格式.docx_第2页
第2页 / 共14页
机械专业毕业设计论文外文翻译连杆机构文档格式.docx_第3页
第3页 / 共14页
机械专业毕业设计论文外文翻译连杆机构文档格式.docx_第4页
第4页 / 共14页
机械专业毕业设计论文外文翻译连杆机构文档格式.docx_第5页
第5页 / 共14页
点击查看更多>>
下载资源
资源描述

机械专业毕业设计论文外文翻译连杆机构文档格式.docx

《机械专业毕业设计论文外文翻译连杆机构文档格式.docx》由会员分享,可在线阅读,更多相关《机械专业毕业设计论文外文翻译连杆机构文档格式.docx(14页珍藏版)》请在冰豆网上搜索。

机械专业毕业设计论文外文翻译连杆机构文档格式.docx

Kinematicsynthesisistheprocessofdesigningamechanismtoaccomplishadesiredtask. 

Here,bothchoosingthetypesaswellasthedimensionsofthenewmechanismcanbepartofkinematicsynthesis.

Planar,SpatialandSphericalMechanisms

Aplanarmechanismisoneinwhichallparticlesdescribeplanecurvesisspaceandalloftheplanesareco-planar.. 

Themajorityoflinkagesandmechanismsaredesignedasplanersystems.Themainreasonforthisisthatplanarsystemsaremoreconvenienttoengineer. 

Spatialmechanismaarefarmorecomplicatedtoengineerrequiringcomputersynthesis. 

Planarmechanismsultilisingonlylowerpairsarecalledplanarlinkages.Planarlinkagesonlyinvolvetheuseofrevoluteandprismaticpairs

Aspatialmechanismhasnorestrictionsontherelativemovementoftheparticles.Planarandsphericalmechanismsaresub-setsofspatialmechanisms..Spatialmechanisms/linkagesarenotconsideredonthispage

Sphericalmechanismshasonepointoneachlinkagewhichisstationaryandthestationarypointofallthelinksisatthesamelocation. 

Themotionsofalloftheparticlesinthemechanismareconcentricandcanberepesentedbytheirshadowonasphericalsurfacewhichiscenteredonthecommonlocation..Sphericalmechanisms/linkagesarenotconsideredonthispage

Mobility

Animportantfactorisconsideringalinkageisthemobilityexpressedasthenumberofdegreesoffreedom. 

Themobilityofalinkageisthenumberofinputparameterswhichmustbecontrolledindependentlyinordertobringthedevicetoasetposition. 

Itispossibletodeterminethisfromthenumberoflinksandthenumberandtypesofjointswhichconnectthelinks...

Afreeplanarlinkgenerallyhas3degreesoffreedom(x,y,θ). 

Onelinkisalwaysfixedsobeforeanyjointsareattachedthenumberofdegreesoffreedomofalinkageassemblywithnlinks=DOF=3(n-1)

Connectingtwolinksusingajointwhichhasonlyondegreeoffreedomaddstwoconstraints.Connectingtwolinkswithajointwhichhastwodegreesoffreedominclude1restrainttothesystems.Thenumberof1DOFjoints=sayj1andthenumberofjointswithtwodegreesoffreedom=sayj2..TheMobilityofasystemisthereforeexpressedasmobility=m=3(n-1)-2j1-j2

Exampleslinkagesshowingthemobilityareshownbelow..

Asystemwithamobilityof0isastructure.Asystemwithamobilityof1canbefixedinpositionmypositioningonlyonelink.Asystemwithamobilityof2requirestwolinkstobepositionedtofixthelinkageposition..

Thisruleisgeneralinnatureandthereareexceptionsbutitcanprovideaveryusefulinitialguideasthethemobilityofanarrangementoflinks...

Grashof'

sLaw

Whendesigningalinkagewheretheinputlinkageiscontinuouslyrotatede.g.drivenbyamotoritisimportantthattheinputlinkcanfreelyrotatethroughcompleterevolutions. 

Thearrangementwouldnotworkifthelinkagelocksatanypoint. 

ForthefourbarlinkageGrashof'

slawprovidesasimpletestforthiscondition

slawisasfollows:

Foraplanarfourbarlinkage,thesumoftheshortestandlongestlinkscannotbegreaterthanthesumoftheremaininglinksifthereistobecontinuousrelativerotationbetweentwomembers.

Referringtothe4inversionsofafourbarlinkageshownbelow..Grashof'

slawstatesthatoneofthelinks(generallytheshortestlink)willbeabletorotatecontinuouslyifthefollowingconditionismet...

b(shortestlink)+c(longestlink)<

a+d

FourInversionsofatypicalFourBarLinkage

Note:

Iftheaboveconditionwasnotmetthenonlyrockingmotionwouldbepossibleforanylink..

MechanicalAdvantageof4barlinkage

Themechanicaladvantageofalinkageistheratiooftheoutputtorqueexertedbythedrivenlinktotherequiredinputtorqueatthedriverlink. 

ItcanbeprovedthatthemechanicaladvantageisdirectlyproportionaltoSin(β)theanglebetweenthecouplerlink(c)andthedrivenlink(d),andisinverselyproportionaltosin(α)theanglebetweenthedriverlink(b)andthecoupler(c). 

Theseanglesarenotconstantsoitisclearthatthemechanicaladvantageisconstantlychanging.

Thelinkagepositionsshownbelowwithanangleα=0oand180ohasanearinfinitemechanicaladvantage. 

Thesepositionsarereferredtoastogglepositions. 

Thesepositionsallowthe4barlinkagetobeusedaclampingtools.

Theangleβiscalledthe"

transmissionangle"

Asthevaluesin(transmissionangle)becomessmallthemechanicaladvantageofthelinkageapproacheszero. 

Intheseregionthelinkageisveryliabletolockupwithverysmallamountsoffriction. 

Whenusingfourbarlinkagestotransfertorqueitisgenerallyconsideredprudenttoavoidtransmissionanglesbelow450and500.

Inthefigureaboveiflink(d)ismadethedriverthesystemshownisinalockedposition. 

Thesystemhasnotogglepositionsandthelinkageisapoordesign

Freudenstein'

sEquation

Thisequationprovidesasimplealgebraicmethodofdeterminingthepositionofanoutputleverknowingthefourlinklengthsandthepositionoftheinputlever. 

Considerthe4-barlinkagechainasshownbelow..

Thepositionvectorofthelinksarerelatedasfollows

l1+l2+l3+l4=0

Equatinghorizontaldistances

l1cosθ1+l2cosθ2+l3cosθ3+l4cosθ4=0

EquatingVerticaldistances

l1sinθ1+l2sinθ2+l3sinθ3+l4sinθ4=0

Assumingθ1=1800thensinθ1=0andcosθ1=-1Therefore

-l1+l2cosθ2+l3cosθ3+l4cosθ4=0

and..l2sinθ2+l3sinθ3+l4sinθ4=0

Movingalltermsexceptthosecontainingl3totheRHSandSquaringbothsides

l32cos2θ3=(l1-l2cosθ2-l4cosθ4)2

l32sin2θ3=(-l2sinθ2-l4sinθ4)2

Addingtheabove2equationsandusingtherelationships

cos(θ2-θ4)=cosθ2cosθ4+sinθ2sinθ4) 

and 

sin2θ+cos2θ=1

thefollowingrelationshipresults..

sEquationresultsfromthisrelationshipas

K1cosθ2+K2cosθ4+K3=cos(θ2-θ4)

K1=l1/l4 

K2=l1/l2 

K3=(l32-l12-l22-l24)/2l2l4

Thisequationenablestheanalyticsynthesisofa4barlinkage. 

Ifthreepositionoftheoutputleverarerequiredcorrespondingtotheangularpositionoftheinputleveratthreepositionsthenthisequationcanbeusedtodeterminetheappropriateleverlengthsusingthreesimultaneousequations...

VelocityVectorsforLinks

Thevelocityofonepointonalinkmustbeperpendiculartotheaxisofthelink,otherwisetherewouldbeachangeinlengthofthelink.

OnthelinkshownbelowBhasavelocityofvAB=ω.ABperpendiculartoA-B."

Thevelocityvectorisshown...

Consideringthefourbararrangementshownbelow.Thevelocityvectordiagramisbuiltupasfollows:

∙AsAandDarefixedthenthevelocityofDrelativetoA=0aanddarelocatedatthesamepoint

∙ThevelocityofBrelativetoaisvAB=ω.ABperpendiculartoA-B.Thisisdrawntoscaleasshown

∙ThevelocityofCrelativetoBisperpediculartoCBandpassesthroughb

∙ThevelocityofCrelativetoDisperpediculartoCDandpassesthroughd

∙ThevelocityofPisobtainedfromthevectordiagrambyusingtherelationshipbp/bc=BP/BC

Thevelocityvectordiagramiseasilydrawnasshown...

VelocityofslidingBlockonRotatingLink

ConsiderablockBslidingonalinkrotatingaboutA.TheblockisinstantaneouslylocatedatB'

onthelink..

ThevelocityofB'

relativetoA=ω.ABperpendiculartotheline.ThevelocityofBrelativetoB'

=v.Thelinkblockandtheassociatedvectordiagramisshownbelow..

AccelerationVectorsforLinks

Theaccelerationofapointonalinkrelativetoanotherhastwocomponents:

∙1)thecentripetalcomponentduetotheangularvelocityofthelink.ω2.Length

∙2)thetangentialcomponentduetotheangularaccelerationofthelink....

∙Thediagrambelowshowshowtotoconstructavectordiagramfortheaccelerationcomponentsonasinglelink.

Thecentripetalaccelerationab'

=ω2.ABtowardsthecentreofrotation. 

Thetangentialcomponentb'

b=α.ABinadirectionperpendiculartothelink..

Thediagrambelowshowshowtoconstructanaccelerationvectordrawingforafourbarlinkage.

∙ForAandDarefixedrelativetoeachotherandtherelativeacceleration=0(a,daretogether)

∙TheaccelerationofBrelativetoAaredrawnasfortheabovelink

∙ThecentripetalaccelerationofCrelativetoB=v2CBandisdirectedtowardsB

展开阅读全文
相关资源
猜你喜欢
相关搜索

当前位置:首页 > 人文社科 > 视频讲堂

copyright@ 2008-2022 冰豆网网站版权所有

经营许可证编号:鄂ICP备2022015515号-1