系统级编程作业 lab1解析文档格式.docx

系统级编程作业 lab1解析文档格式.docx

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and

Performconversionfromeightbits（character）toeightbytestobedisplayedon

screen.

2.TypeandFormatinmemory–character,integer,shortandfloat

2.1

Thisexerciseistodeterminethememorysizeofdifferenttype.

lab1_1.cpp

//Determinethememorysizeofdeclarationandvariabletype

#include<

iostream.h>

stdio.h>

ctype.h>

conio.h>

string.h>

stdlib.h>

voidmain（）

{

charc;

chars[128];

shorti;

shortn[64];

printf（==\n,sizeof（c）,sizeof（char））;

printf（==\n,sizeof（s）,sizeof（char[128]））;

printf（==\n,sizeof（i）,sizeof（short））;

printf（==\n,sizeof（n）,sizeof（short[64]））;

}

Thedisplayis:

1

--

2018/10/21

Nowexecutetheaboveprogramandfillinthefollowing:

Sizeinbit

SizeinbyteType

162Short

81Char

64

512Short[32]

512Char[64]

2.2

integer[128],integer,float,theUsetheapproachoftheabove,determinememorysizeof

float[16]（lab1_2.cpp）

）]Writeaprogramtoverifyyouranswerandfillinthefollowing:

[hint,usesizeof（…Sizeinbit

TypeSizeinbyte

324Int

324Float

512

4096Int[128]

51264

Float[16]

Writedownyourcodesbelow:

#include<

voidmain（）{

intc;

ints[128];

floatI;

floatn[16];

printf（“==\n”,sizeof（c）,sizeof（int））;

printf（“==\n”,sizeof（s）,sizeof（int[128]））;

printf（“==\n”,sizeof（i）,sizeof（float））;

printf（“==\n”,sizeof（n）,sizeof（float[16]））;

Writedownyourexpressionamongstthedifferenceinsizebetweencharacter,integer,float,

short,char[8],int[8],short[8],float[8]

Character=1byte

Integer=4bytes

Float=4bytes

Short=2bytes

Char[8]=8bytes

Int[8]=32bytes

Short[8]=16bytes

Float[8]=32bytes

2

2.3

Thisexerciseistodisplaythedecimalandoctalvaluessothatyouknowhowitisstoredin

memory.

lab1_3.cpp

for（chari=30;

i<

41;

++i）

printf（i:

dec=%doct=%o\n,i,i）;

theoutputis:

well.unsignedashextotheaboveprogrammedisplaydecimal,octal,andmodifyNow

（Hints:

hex,%x,unsigned%u）

3

voidmain（）{

for（chari=30;

41;

++i）

dec=%doct=%ohex=%xunsigned=%u\n,i,i,i,i）;

}

Writedowntheoutputofthefirst4linessothatyouunderstandthedifferenceamongthem.

i:

dec=30oct=36hex=1eunsigned=30

i:

dec=31oct=37hex=1funsigned=31

dec=32oct=40hex=20unsigned=32

dec=33oct=41hex=21unsigned=33

2.4

Thisexerciseistodumpthecontentofmemoryofdifferenttypesothatyouknowhowitis

storedinmemory.

lab1_4.cpp

chara='

0'

;

//inhex0x30,not0

inti=0x00000013;

//indecimalis（1x16+3）=19

shortj=18;

//occupiestwobytes,

floatf=1.25;

//occupies4bytes

Inordertodisplay,youhavetosetabreakpointbypressing“F9”besidetheline,the

programwilldisplayaredcircleasfollows:

4

--2018/10/21

Now,typetheaddressofeachvariableasshownintheleft-bottomframetolocatewhether

.Since,visualC++reserves4bytesbuttheyare.Here,wedumptheaddressofvariable‘a'

（meansCCtothreeseebyte,youcanthattherestbytesaresetCCCConeccharuses

101010101010101010101010inbinary,thedefaultsetting）.

&

ais0x0065fdf4,youhavetotype1memorylocationofathenintheAddress,keyin0x0065fdf4,2itdisplays30CCCCCC

3

0x0065FDF4,thehexadecimalis0x30（ASCII）

5

Now,typeandexecutetheaboveprogramandfillinthefollowing,noteth