小升初英文奥数题.docx
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小升初英文奥数题
英文奥数
1.maths(English)
1)FindthesumofalltheprimenumbersBetween20and30.
2)Dividethesumofthefirstfiveoddnumbersbythesumofthefirsttwoprimenumbers.
3)Subtract2fromthesumofthefirstfiveevennumbers.Thedifferenceisthendividedbythefirstoddnumberfollowing5.Whatisthequotient?
4)Findthevalueof[4+8]÷[5×4-6]andgivetheanswercorrectto2decimalplaces
1)Alltheprimenumbersbetween20and30are23and29,
ThesumofalltheprimenumbersBetween20and30=23+29=52
2)Thefirstfiveoddnumbersare1,3,5,7and9
Thesumofthefirstfiveoddnumbers=1+3+5+7+9=25
3)Thefirsttwoprimenumbersare2and3
Thesumofthefirsttwoprimenumbers=2+3=5
4)Thefirstfiveevennumbersare2,4,6,8and10
Thesumofthefirstfiveevennumbers=2+4+6+8+10=30
5)Thedifferencebetweenthesumofthefirstfiveevennumbersand2
=30-2=28
6)Thefirstoddnumberfollowing5is7
Thequotient=28/7=4
7)Thevalueof[4+8]÷[5×4-6]
=12÷(20-6)=12÷14=0.86(Corr.to2decimalplaces)
2.Sixtreesareequallyspacedalongonesideofastraightroad.thedistancefromthefirsttreetothefourthis60feet.whatisthedistance
infeetbetween.Thefirstandlasttrees?
3.Attheendof 2005walterwashalfasoldashasgrandmother.Thesnmoftheyearsinwhichtheywerebornis3860.howoldwillwalterbeattheendof2006?
4.Thedigits1,2,3,4and9areeachusedoncetoformthegreatestpossibleevenfive-digitnumber.Whatisthedigitinthetensplace?
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1、In 2004, 16 June falls on a Wednesday. On what day of the week will 16 June fall in 2010?
2、 In a magic square the sum of the numbers in each row, in each diagonal and in each column are equal. In this magic square the value of x is:
3、If half of a number is 30, then three-quarters of that number is____.
4、The sum of the digits of the following product
999×555
5.Three positive integers have a sum of 28. The greatest possible product that these integers can
have is_____.
6、Jack was trying to tessellate regular pentagons. He managed thefollowing figure.
The size of angle .a. is______.
7、If the area of the shaded region of the regular hexagon in the diagram
below is 36 cm2, the area of the whole hexagon in cm2 is_____.
8、In what follows, □ and Δ are different numbers.
When 503 is divided by □ the remainder is 20.
When 503 is divided by Δ the remainder is 20.
When 493 is divided by □ x Δ the remainder is_____.
9、A lady, her brother, her son and her daughter (all related by birth) played
volleyball. The worst player's twin (who is one of the four players) and the
best player are of opposite sex.
The worst player and the best player are of the same age.
Who cannot be the worst player(s)?
A) brother only B) daughter only
C) son and daughter only D) lady and daughter only
E) lady only
10、If you continue the given number pattern, in what row and in what
position in that row will the number 320 be?
1 -------------- row 1
2 3 -------------- row 2
4 5 6 -------------- row 3
7 8 9 10 -------------- row 4
The answers are given in the order of row ; position.
参考答案:
1、Wednesday 2、12 3、45 4、27(求数位上上的数字之和)5、28=9+9+10,因此答案为810 6、36度 7、108 8、503-20=483 483=3×7×23=21×23,因此□ x Δ=483,因此此题余数是10. 9、D 10、25,20
##**##***************###############·········****#####
附一道考试真题:
At10:
30,theanglelessthan180°
Formetbyhourhandandminute
Handofnormalclockis
***(英汉词典:
angle角;lessthan小于;tofrom形成;hourhand时针;
Minutehand分针;normal正常,正规;clock钟,时钟)
***上面是一道关于时钟问题的英文奥数题,猜猜是什么意思?
附参考答案:
如果做过相关的时钟问题,借助于所给的解释可以理解到:
求10:
30分时,时针与分针所形成的小于180的夹角是多少?
答案:
135°。
****************
有学生问:
在钟面上,如果知道X时Y分,输入一个公式就能得出此时时针与分针夹角的度数。
请问这个公式怎么得来?
答:
钟面上分12大格60小格。
每1大格均为360除以12等于30度。
每过一分钟分针走6度,时针走0.5度,能追5.5度。
公式可这样得来:
X时时,夹角为30X度。
Y分,也就是分针追了时针5.5Y度。
可用:
整点时的度数30X减去追了的度数5.5Y。
如果减得的差是负数,则取绝对值,也就是直接把负号去掉,因为度数为非负数。
因为时针与分针一般有两个夹角,一个小于180度,一个大于180度,(180度时只有一个夹角)
因此公式可表示为:
|30X-5.5Y|或360-|30X-5.5Y|度。
||为绝对值符号。
如1:
40分,可代入得:
30×1-5.5×40=-190则为190度,另一个小于180度的夹角为:
170度。
如:
2:
10,可代入得:
60-55=5度。
大于180度的角为:
355度。
如:
11:
20,330-110=220度,小于180的角:
360-220=140度。
注:
此题为05小升初某重点中学招生考试题。
多个学校考了时钟问题。
学生问的这道题是十一学校的培训题,但具有普遍性,请大家必须掌握。
再来一个你试试:
3:
24时针与分针夹角多少度?
试试这道英语奥数题:
At10:
30,theanglelessthan1800
formetby hourhand andminute
hand of a normal colck is______________。
(英汉词典:
angle角;lessthan小于;tofrom形成,作成;hourhand时针;minutehand分针;normal正常,正规;clock钟,时钟)
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1、Anantcoversadistanceof90metresin3hours.Theaveragespeedoftheantindecimetresperminuteis____.
2、Inacertaintownsomepeoplewereaffectedbya’flu’epidemic.Inthefirstmonth20%ofthepopulationcontractedthefluwhilst80%werehealthy.
Inthefollowingmonth20%o