电力电子建模与仿真实验二.docx

电力电子建模与仿真实验二.docx

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电力电子建模与仿真实验二

Example5：

3-PhaseThyristorRectifierBridge

Problems

1.（a）Obtainva,vdandidwaveformsusingThyrect3.

Green：

Va，Red：

Vd，Blue：

Id

（b）Obtainvaandiawaveforms.

（c）Obtain（va）pcc,（vab）pccandiawaveforms.

2.Fromtheplots,obtainthecommutationintervaluandidatthestartofthecommutation.

Verify（验证）thefollowingcommutationequation:

whereLs=Ls1+Ls2.ForId,usetheaveragevalueofidoritsvalueatthestartofthecommutation.

averagevalueofid=23.459A

u=5.108°

cos（a+u）=0.641

=0.635

3.BymeansofFourieranalysisofis,calculateitsharmoniccomponentsasaratioofIs1.

FOURIERCOMPONENTSOFTRANSIENTRESPONSEI（L_Ls1a）

DCCOMPONENT=3.027748E-05

HARMONICFREQUENCYFOURIERNORMALIZEDPHASENORMALIZED

NO（HZ）COMPONENTCOMPONENT（DEG）PHASE（DEG）

16.000E+012.591E+011.000E+00-4.756E+010.000E+00

21.200E+026.800E-032.624E-04-9.772E+01-2.597E+00

31.800E+021.475E-045.693E-06-8.097E+016.172E+01

42.400E+027.200E-032.778E-041.695E+023.598E+02

53.000E+025.977E+002.306E-01-5.762E+011.802E+02

63.600E+021.650E-046.369E-061.730E+024.583E+02

74.200E+022.701E+001.042E-01-1.537E+021.793E+02

84.800E+026.615E-032.553E-041.562E+025.366E+02

95.400E+025.425E-052.094E-061.753E+026.034E+02

106.000E+026.756E-032.607E-046.227E+015.379E+02

116.600E+022.233E+008.615E-02-1.635E+023.597E+02

127.200E+021.348E-045.200E-066.503E+016.358E+02

137.800E+021.521E+005.869E-021.013E+027.196E+02

148.400E+025.914E-032.282E-044.837E+017.142E+02

159.000E+024.640E-051.791E-066.686E+007.201E+02

169.600E+026.088E-032.349E-04-4.516E+017.158E+02

171.020E+031.298E+005.009E-029.093E+018.995E+02

181.080E+031.663E-046.415E-06-3.839E+018.177E+02

191.140E+031.011E+003.900E-02-4.139E+008.995E+02

201.200E+034.938E-031.906E-04-5.981E+018.914E+02

211.260E+038.547E-053.298E-06-8.519E+019.136E+02

221.320E+035.071E-031.957E-04-1.526E+028.937E+02

231.380E+038.592E-013.316E-02-1.462E+011.079E+03

241.440E+031.707E-046.586E-06-1.261E+021.015E+03

251.500E+037.160E-012.763E-02-1.096E+021.079E+03

261.560E+033.641E-031.405E-04-1.692E+021.067E+03

271.620E+037.340E-052.832E-06-1.730E+021.111E+03

281.680E+033.752E-031.448E-049.800E+011.430E+03

291.740E+035.972E-012.304E-02-1.202E+021.259E+03

301.800E+031.324E-045.111E-061.355E+021.562E+03

TOTALHARMONICDISTORTION=2.852178E+01PERCENT

Is5/Is1=5.977/25.91=0.231

Is7/Is1=2.701/25.91=0.104

Is11/Is1=2.701/25.91=0.086

Is13/Is1=1.521/25.91=0.059

4.CalculateIs,%THDintheinputcurrent,theinputdisplacementpowerfactorandtheinputpowerfactor.

THD=28.52%,DPF==cos（-47.56）=0.675,Is1=18.32A,Idisp=5.15A,Is（rms）=19.03A

PF=0.650

5.Verifythefollowingequation:

Displacementpowerfactor

α=45°，,μ=10.22°，

=0.6742

DPF=0.675

6.Atthepointofcommoncoupling,obtainthefollowingfromthevoltagevpccwaveform:

（a）Line-notchdepthρ（%）

ρ（%）=273.996-258.096=15.9

（b）Line-notchareaand,

[（255.811-266.899）+15.9]*（12.043-11.800）/2=3.279（V*ms）

（c）voltageTHD%

THD%=3.013%

7.ObtaintheaveragedcvoltageVd.Verifythat

.

ForId,usetheaveragevalueofidoritsvalueatthestartofthecommutation.

Vd（avg）=DCCOMPONENT=1.875908E+02=187.59V

averagevalueofid=23.459A

=1.35*208*cos（45）-3*2*60*0.0012*23.459=188.42V

Problems

1.（a）Obtainva,vdandidwaveformsusingThyinv3

（b）Obtainvaandiawaveforms

2.CalculateIs,%THDintheinputcurrent,theinputdisplacementpowerfactorandtheinputpowerfactor.

FOURIERCOMPONENTSOFTRANSIENTRESPONSEI（L_Lsa_L）

DCCOMPONENT=-1.354084E-02

HARMONICFREQUENCYFOURIERNORMALIZEDPHASENORMALIZED

NO（HZ）COMPONENTCOMPONENT（DEG）PHASE（DEG）

16.000E+011.620E+011.000E+002.945E+010.000E+00

21.200E+021.344E-028.298E-04-1.757E+02-2.346E+02

31.800E+025.968E-033.684E-041.757E+028.736E+01

42.400E+027.628E-034.709E-04-1.080E+02-2.258E+02

53.000E+024.149E+002.562E-01-2.815E+01-1.754E+02

63.600E+027.563E-044.669E-051.583E+02-1.844E+01

74.200E+021.389E+008.573E-023.144E+00-2.030E+02

84.800E+026.237E-033.851E-04-1.416E+02-3.772E+02

95.400E+021.971E-031.217E-041.583E+02-1.068E+02

106.000E+025.717E-033.529E-04-8.280E+01-3.773E+02

116.600E+021.445E+008.918E-02-4.308E+01-3.671E+02

127.200E+023.834E-042.367E-051.373E+02-2.162E+02

137.800E+028.324E-015.139E-027.811E+00-3.751E+02

148.400E+025.678E-033.506E-04-1.290E+02-5.414E+02

159.000E+021.185E-037.315E-051.427E+02-2.991E+02

169.600E+025.486E-033.387E-04-7.260E+01-5.439E+02

171.020E+038.556E-015.282E-02-5.098E+01-5.517E+02

181.080E+032.623E-041.619E-051.162E+02-4.139E+02

191.140E+035.942E-013.668E-023.584E+00-5.560E+02

201.200E+035.547E-033.425E-04-1.218E+02-7.108E+02

211.260E+038.490E-045.242E-051.273E+02-4.912E+02

221.320E+035.452E-033.366E-04-6.627E+01-7.142E+02

231.380E+035.984E-013.695E-02-5.816E+01-7.356E+02

241.440E+032.041E-041.260E-059.540E+01-6.115E+02

251.500E+034.572E-012.823E-02-2.319E+00-7.387E+02

261.560E+035.562E-033.434E-04-1.161E+02-8.819E+02

271.620E+036.631E-044.094E-051.121E+02-6.832E+02

281.680E+035.507E-033.400E-04-6.119E+01-8.859E+02

291.740E+034.533E-012.799E-02-6.519E+01-9.193E+02

301.800E+031.707E-041.054E-057.492E+01-8.087E+02

TOTALHARMONICDISTORTION=3.010848E+01PERCENT

THD=30.11%

DPF=0.869

Is1=11.48AIsdisp=3.40AIs（rms）=11.97A

PF=0.832

3.Studythestartupoftheinverteroperation.Increasethedelayangletoavaluecloseto180︒andlookattheva,vdandidwaveforms.Repeattheaboveprocedureby

reducingαslowlytoitsnominalvalueof160︒.PlottheaveragedccurrentIdversus

α.

α=178°

α=178°I=558.91Aα=176°I=569.56A

α=174°I=558.33Aα=172°I=561.50A

α=170°I=557.65Aα=168°I=522.79A

α=166°I=0α=164°I=300.01A

α=162°I=511.80Aα=160°I=14.64A

Figure：

I=f（α）