1、有用的小学到初中所有数学公式大全有用的小学到初中所有数学公式大全(Useful mathematics from elementary school to junior middle school)1, the number of copies of each number x = total number, each number of copies, copies number = = each number2, 1 times of a few a few multiples of multiples of multiples of x = 1, = several multiples
2、of multiples of multiples of multiples / = 1 times3, speed time distance, distance = x = distance / time time speed = speed4, the number of the total price, price x = = = the number of total number of unit price, unit price5, work efficiency * working time = total amount, total work efficiency = wor
3、king timeThe total amount of work, work time = work efficiency6, the addend addend = + and - addend = other addend7, the minuend - = = - difference difference reduction minuend difference + = minuend meiosis meiosis8, factor X factor = product divided by a factor = another factor9, dividend, dividen
4、d, divisor = business taking = x = dividend dividend divisor quotientMathematical formulas for elementary school mathematics1, square: C perimeter, S area, a length side length = perimeter = 4C=4a area = length side * S=a * a2, the cube: V: volume a: edge length surface area = length x length x 6 S
5、=a * a * 6Volume = edge length x x long * x V=a x a * a3, rectangle:C perimeter, S area, a, side length, perimeter = (length + width) * 2 C=2 (a+b) area = * * width S=ab4, cuboidV: volume s:, area a: long, b: width, h: height(1) surface area (length * width + length * height + width * height) * 2 S=
6、2 (ab+ah+bh)(2) volume = long * width * high V=abh5, triangleS a h high end area bottom area = x height / 2 s=ah / 2Triangle area high = x 2 / bottomTriangle area = x 2 / high6, parallelogram: s area a, bottom h, high area = bottom * high s=ah7, ladder: s area a b h high bottom bottom area = (+ down
7、 on the bottom end) * / 2 s= (a+b) * H / 28 round: S C d= r= diameter radius circumference pi(1) = =2 * * * perimeter diameter radius C= d=2 pi pi pi * r(2) * * * area = radius radius9, cylinder: V, volume h:, high S: bottom area R: bottom radius C: bottom perimeter(1) the side area = the circumfere
8、nce of the bottom * high(2) surface area = side area + base area * 2(3) volume = base area * height(4) = 2 / X volume side area radius10, V: h s high volume cone bottom area R bottom radius size = base area x height / 3The total, the total number of copies = average numberEquation of sum and differe
9、nce(+ and difference) 83019 2 = number(and poor) 83019 2 = decimalDoubling problemAnd (1 = decimal multiples).Decimal = multiple = large number(or sum = decimal = large number)Difference problem(1 / difference multiples) = decimalDecimal = multiple = large number(or decimal + difference = large numb
10、er)Tree planting problem1, the problem of tree planting on non closed lines can be divided into the following three cases:If a non closed line at both ends are planting trees, so:Number = number of + 1 / 1 = length spacing* (1 = length spacing number)Full length (1 / spacing = number)If you want to
11、plant trees in the end of non closed line, the other end is not planting, so:Number = number = length / spacingLength = x number of rows= length / number of rowsIf both ends in non closed line are not planting trees, so:Number section number = - 1 / 1 = length spacing* (number = length spacing + 1)=
12、 length / spacing (number 1)2, the number of trees on closed lines is as followsNumber = number = length / spacingLength = x number of rows= length / number of rowsProfit and loss(profit + loss), the two distribution of the difference between the number of copies in the distribution of =(large surpl
13、us - small surplus) / two distribution of the difference between the number of copies in the distribution of =(burned - a small loss of two times), the difference between the number of copies is assigned to participate in the distribution of theEncounter problemEncounter distance = speed and X meeti
14、ng timeMeet time = distance / speed and meetThe speed and distance, the encounter time = meetCatch up with problemsTracking distance = speed difference * tracking timeChase and chase and distance / time = speed differenceThe speed difference and distance = chase chase and time.Flow problemDownstream
15、 velocity = hydrostatic velocity + flow velocityCountercurrent velocity = hydrostatic velocity - flow velocityHydrostatic speed = (downstream velocity and velocity), 2Flow rate = (downstream speed velocity), 2Concentration problemThe weight of the solute + the weight of the solvent = the weight of t
16、he solutionThe weight, the weight of the solute solution x 100% = concentrationWeight of solution = concentration = solute weightThe weight, concentration of solute solution = weightProfit and discount problemsProfit = selling price - costThe rate of profit, profit = cost X 100% = (sold / cost 1) *
17、100%Amount of fluctuation = principal * Change PercentageThe actual price discount, the original price x = 100% ( 1 discount)Interest = principal * interest rate * timeAfter tax interest rates * * * = principal time (120%)Length Conversion1 kilometers 1 meters =1000 meters =10.1 cm =100 cm =10 1 met
18、er decimeter1 cm =10 mmArea Conversion1 sq km =100 hectares1 hectares =10000 square meters1 square meters =100 square decimeter1 square =100 square centimeter decimeter1 mm2 =100 mm2Volume (volume) product unit conversion1 cubic meters =1000 cubic decimeter1 cubic meter =1000 cubic centimeter1 DM3 =
19、1 L1 cubic centimeter =1 ml.1 cubic meters =1000 litersWeight unit conversion1 tons =1000 kg1 kilograms =1000 grams1 kg =1 kgUnit conversion of Renminbi1 yuan =10 Jiao1 jiao =10 minutes1 yuan =100 centstime conversionFirst Century =100, 1 years =12 monthsMonth (31 days): 135781012 monthXiaoyue (30 d
20、ays) are: 46911 monthThere are 28 days in February, a leap year 29 days in FebruaryThere are 365 days a year, a leap year 366 days a year1 days =24 hours, 1 hours =60 minutes1 minutes, =60 seconds, 1 hours, =3600 secondsMathematical formulas of geometry, perimeter, area and volume of Primary Mathema
21、tics1, the perimeter of the rectangle = (long + width) * 2 C= (a+b) * 22, square perimeter = side length * 4 C=4a3, rectangular area = long * width S=ab4, square area = length side * side length S=a.a= a5, the bottom of the triangle area = x height / 2 S=ah / 26. The area of the parallelogram = bott
22、om * high S=ahArea = 7, trapezoidal (bottom + bottom) x height / 2 S= (a + b) H / 28 x 2 d=2r diameter = radius radius = 2 D / 2 r= diameter.9, the circumference of a circle diameter x = pi = pi * * 2 c= D =2 radius Pi Pi R10, the area of a circle radius radius = pi * *Common formulas for junior hig
23、h school mathematics1 there is only one line after two2 the line between two points is the shortest3 the same angle or isometric equal margin4 with the angle of the complement of equal or constant5 having only one line and perpendicular to the known line6, the line outside a point and the line on al
24、l points connected by the line, the vertical line segment is the shortest7 parallel axioms follow a point outside the straight line and have only one line in parallel with the line8 if the two lines are parallel to the third lines, the two lines are parallel to each other9 corresponding angles are e
25、qual, the two parallel lines10 alternate angles are equal, the two parallel lines11 complementary interior angles on the same side, two parallel lines12 the two parallel lines, corresponding angles are equal13 two line parallel, alternate angles are equal14 the two parallel lines, complementary inte
26、rior angles on the same sideThe sum of 15 sides of a triangle is greater than third16 infer that the difference between the sides of a triangle is less than third17 triangle triangle sum theorem three angles and equal to 180 degrees18 inference 1 the two acute angles of right triangle overlap each o
27、ther19 a corollary of a triangle is equal to the 2 corners and two angles it is adjacent and20 a corollary of a triangle with 3 corners than any one and it is not adjacent.The corresponding sides of 21 congruent triangles and equal angles22 edge axioms (SAS) are congruent with two triangles of equal
28、 angles on both sides and their angles23 corner corner axiom (ASA) has two triangles congruent horns and their edges corresponding to the equal24 inference (AAS) had two horns and one of the angle on the side corresponding to the equal two congruent triangles25 side axioms (SSS) having two equal tri
29、angles equal to three sides26 bevel and right side axioms (HL) have two equal angles of right triangle and one right angleCongruent27 theorem 1 the distance between points on the bisector of an angle to the sides of this angle is equalThe point at which the distance between 2 and 28 angles is the sa
30、me as in the bisector of this angleThe bisector of 29 angles is the set of all points equal to the two sides of the angleTwo and 30 are equal isosceles triangle theorem of an isosceles triangle (i.e. equal equilateral angle)31 infer that the bisector of the 1 isosceles triangle vertex is equal to th
31、e base and perpendicular to the base32 the top angles of the isosceles triangle, the bisector, the middle line on the bottom edge and the height on the bottom edge coincide with each other33 corollary 3 equilateral triangles whose angles are equal, and each angle equal to 60 degrees34 the decision t
32、heorem of isosceles triangle, if a triangle has two angles equal, then these two anglesThe opposite sides are equal (equal angles, equal sides)35 corollary 1 three angles are equal triangle is an equilateral triangle36 corollary 2 an isosceles triangle with an angle equal to 60 degrees is an equilateral triangle37 in a right triangl
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