完整word版导线应力弧垂计算.docx

1、完整word版导线应力弧垂计算导线应力弧垂计算代表情况温度t( C)风速v(m/s)冰厚b（ mm）最高气温40最低气温-10最大风速-525覆冰-5105年均温15内过电压15150外过电压15100安装情况-5100川气象区条件一、确定相关参数 表一截面积A（ mm ）外径（mm）温膨系数（1/C）弹性模数E（Mpa）348.3624.2618.9咒1076000单位长度质量G（kg/km）瞬时破坏应力bp （M pa）安全系数K1210282.02.5表二LGJ-30050型导线参数2.冰重比载食(5,0)27.728嘗血=27.7285548!F 灯.600pa/m)3.垂直总比载(5

2、,0) =(0,0) +丫2(5,0) = 45.66 勺0d(M pa/m)4.无冰风压比载叽乂 =空=62.5( Pa)1.61.6V2 252=一=390.63( Pa)1.61.61）外过电压、安装有风：r W 2 3 62 5 3丫4（0,10） = Pcf scdsin2 9x10律.0x0.85x1.1x24.26x一 x10, A 348.36-3=4.10x 10- （ Mpa/m）2）最大设计风速: 计算强度:7X0,25） PcSscdsin2ex10 = 1.0x0.85x1.1x24.26x390c 10A 348.363=25.43 X10- （ Mpa/m）低于5

3、00kv的线路Pc取1.0,计算强度时 5按表取0.85，当d17mm时lsc取1.1.计算风偏:丫4（0,25） = P，f scd sin2 日 x 10, = 1.0x 0.75x 1.1 x 24.26咒 390.63x 10A 348.363=22.44 X10- （ Mpa/m）计算风偏时J取0.753）内过电压:2 2V 15WV = 丄=140.625 （Pa）1.61.6丫4（0,15） = PcjPscdsin2 日咒10 =1.0咒0.85咒 1.1咒 24.26咒140625厂0A 348.36=9.16 X10-3 （ Mpa/m）5.覆冰风压比载V2 102WV =

4、 =62.51.61.6（5,10） = P afAsCB（d +2b） sin2&咒10A62 5TZ11.21 （24.26 + 10）站血= 8.11 0-3（ Mp a/m）6.无冰综合比载外过电压、安装有风:丫6（0,25） = （0,0）2 + 丫4（0,10）2 =34.062 +4.102 咒10-3 = 34.31咒 10（M pa/m）最大设计风速（计算风偏）：%(0,25) =jYi(O,O)2 + 7/0,25)2=V34.062 +25.432 x10-3 =42.51x10(M pa/m)%(0,25)=(1(O,O)2 + 丫4(0,25)2=J34.O62 +2

5、2.442 x10-3 =40.79x10(Mpa/m)内过电压:%(0,10)=尹 i(0,0)2 + 丫4(0,12.5)2 =J34.O62 +9.162 MO-3 =35.27dO(M pa/m)7.覆冰综合比载丫7(5,10) =JY3(5,O)2 + 丫5(5,10)2 =46.37x10”(M pa/m)名称符号结果3(X1O- MPa/m)自重比载丫 1(0,934.06冰重比载丫 2(5,0)11.6O垂直比载丫 3(5,O)45.66无冰风压比载丫 4（00）（外过电压、安装有风）4.1O丫 4（25）（最大风，计算强 度）25.43丫 4（25）（最大风，计算风 偏）22

6、.257（0,15）（内过电压）9.61覆冰风压比载丫 5(5,10)8.11无冰有风丫 6（00）（外过电压、安装有风）34.31丫 6（05）（最大风，计算强42.51表三比载综合比载度)丫 6(25)(最大风，计算风 偏)40.79%(0,15)(内过电压)35.27覆冰有风综合比载丫 7(5,10)46.37三、确定应力值(2 )年平均运行应力上线:cTpj =cr pX 25% =282.0x25% =70.5( Mpa)四、计算临界档距，判断控制气象条件又覆冰时的比载大于最大风时因为覆冰与最大风情况下的最大使用应力和气温都相同, 的比载，故最大风不再作为控制气象图条件考虑。表四比值

7、Y /b。计算结果及其排序表气象条件最低温覆冰有风年均温气温-10-515(10-3M pa/m)34.0646.3734.06bo(M pa)112.8112.870.5g(1/m)0.302 X10-30.411 X10-30.483X10-3排序abc临界档距计算(无高差)24x 70.5 -112.8 +1.4346(15 + 5)1 b = J760OOX (0.483X 10)2 -(0.411X 10)2虚数表五可能控制气象条件可能的控制条件a（最低温）b（覆冰）临界档距（m）lab =170.72lbc =虚数lac =虚数因为a,b档内均存在虚数，所以 a,b不再成为控制气象

8、条件。所以可以判定不论档距多大,年均温为控制气象条件。五、状态方程求应力已知年均温为控制气象条件已知条件年均温t( C)15b(mm)0v(m/s)0Y(x 10-3M pa/m)34.06cMM pa)70.5已知条件参数表六状态方程计算式:牛401-宇2-呻2 7)24貯02 24%11.最高温:带入数据得:023(0.00074134.64)CT J -3.67I2 =0当档距为以下各值时，由状态方程求得应力:3 2 2 250m: %(0.000750 -34.64)CT02 -3.650=03 2100m: cr02 +(0.00074x100 34.64)cy02 =45.20(

9、Mpa)3 2150m: 02 + (0.00074咒150 -34.64)%2 -3.67X1002 =02 202 3.67x150 =0O02 =50.44( Mpa)3 2200m: %2 +(0.0007恥2002-34.64)2 2CT02 -3.67X2002=0CT02 =54.49( Mpa)3 2250m: CT02 +(0.00074x250-34.64)2022-3.67x250O02 =57.58( Mpa)3 2300m: %2 + (0.00074X300-34.64)2-3.67 咒 300b02 =59.95( Mpa)3 2350m: cr02 +(0.00

10、07350-34.64)-3.67X3502b02 =61.78( Mpa)3 / 2400m: %2 +(0.0007400-34.64)2 2%2 3.67咒400% =63.21(M pa)450m: cr023 +(0.00074%4502-34.64)2 2CT02 -3.67咒 4502b02 =64.33(M pa)3 2500m: 02 +(0.0007500-34.64)%22 -3.67天 50022.最低温:EYi2|% - 01 -aE(t2 -t1)24% 24%1带入数据得:呢-76003406：103)2加=7込7600(4竺23)2刘2 -1.4364(-10-

11、42402?247052即：cr023 +(0.000742 -106.41) cr022 -3.67I2 =0当档距为以下各值时，由状态方程求得应力:3 , 2 、 2 250m02 +(0.00074x50 -106.41) cr02 -3.650 =0O02 =105.39(M pa)3 2100m: %2 (0.00074 100 -106.41)2 2CT02 -3.67x1002 =0CT 02 =102.50(M pa)150m: cr023 (0.00074 150106.41)2 2CT02 -3.67x1502 =002 =98.30( Mpa)3 2200m: %2 +

12、(0.00074X200 -106.41)2022-3.67X200 =002 =93.58(M pa)3 2250m: 02 +(0.00074X250 -106.41)-3.62500b02 =88.82( Mpa)3 2300m: cr02 + (0.0007300 -106.41)-3.67 咒 3002 =00-02 =85.06( Mpa)3 2350m: %2 + (0.00074X350 -106.41)2-3.67X350 =002 =82.23(M pa)400m: cr023 (0.0007400106.41)-3.67咒4002 =0b02 =79.80( Mpa)3

13、2450m: 02 + (0.0007450 -106.41)2 3.67 咒 450 =03 2500m: 02 + (0.00074X500 -106.41)-3.67天5002 =03.最大风:%-霁一Hd24002 24001带入数据得:即：b023 +(0.000742 -99.20) b025.7210当档距为以下各值时，由状态方程求得应力:3 2 2 250口： 02 +(0.00074咒50 -99.20) CTo? 5.72咒50 =002 =98.81(M pa)b02 =97.78( Mpa)b02 =96.40( Mpa)% =94.97( Mpa)02 =93.68(

14、M pa)02 =92.69(M pa)3 2350口202(0.0007350-99.20)2-99.20)%2 -5.72X 4002=03 2 2 2450m: %2 +(0.0007450 -99.20) CT02 -5.7450 =0cy02 =90.51(M pa)3 , 2 、 2 2500m: 02 +(0.0007500 -99.20) cr02 -5.7500 =0O02 =90.15( Mpa)4.覆冰无风:E%22 EYj22%-耘r右Bi带入数据得:%-76000(4637)2如=705一760皿64竺03)2汗 _1.4364(-5-1512 7Q52即：cr023

15、 + (0.000742 -99.20) CT026.81l0当档距为以下各值时，由状态方程求得应力:3 9 2 950m: b02 +(0.00074咒502 99.20) b02 -6.8500b02 =99.08( Mpa)3 2100m: %2 +(0.00074天100 -99.20)2 2CT 02 6.81X100 =0b02 =98.78( Mpa)150m:貯023 +(0.00074咒1502 -99.20)2 2CT02 -6.8仔1502 =0b02 =98.38( Mpa)3 2200m: 02(0.0007200 -99.20)022 -6.81天2002 =002

16、 =97.98( Mpa)3 2250m: 02(0.0007250 99.20)3 9300m: 02 + (0.0007炉3002 -99.20)3 2350m: CT02 +(0.00074x350 -99.20)2 2b02 6.81x350 =0cy02 =97.02( Mpa)3 2400m: cr02 +(0.0007400 -99.20)2 2CT02 一6.81咒400 =0o02 =96.88( Mpa)3 2450m: b02 +(0.0007450 -99.20)2 2%2 -6.8450 =0b02 =96.73( Mpa)3 2500m: %2 +(0.00074X

17、500 -99.20)%22 -6.81X5002 =0O02 =96.61(M pa)5.安装%- 01 aE(t2 7)2402 2如01带入数据得:屯-76003431；103)2如=7込7600(4竺23)2汗 -1.4364(-5-132%22470523 0 2 9即：cro2 +(0.000742 -99.20) CT02 -3.731 =0当档距为以下各值时，由状态方程求得应力:50m: %3 +(0.00074502 99.20) CTq?2 -3.73咒 502 =0b02 =98.31(M pa)%2 -3.73X1002 =03 2100m: 02 +(0.000741

18、00 -99.20)02 =95.86( Mpa)3 2150m: 02 +(0.00074勺50 99.20)3 9200m: 02 + (0.000720099.20)cy02 =85.12( Mpa)o02 =82.24(M pa)CT 02 =79.98( Mpa)b02 =78.26(M pa)b02 =76.94( Mpa)o02 =75.93( Mpa)6.外过有风% - 24 0124 i E(t2 -t1)24% 2如 01带入数据得:023 +(0.000742 -70.5) CT025.72l0当档距为以下各值时，由状态方程求得应力:3 2 2 250m02 +(0.00

19、074x50 -70.5) b02 5.72x50 =03 2 2 2100m: b02 + (0.00074X100 -70.5)02 -5.72100 =0%22 -5.72天1502 =03 2150m: cr02 (0.00074150 -70.5)cy02 =76.08( Mpa)3 / 2200m: CT02 + (0.00074%200-70.5)2b02-5.72X2002 =0O02 =78.16( Mpa)3 2250m: %2 +(0.0007恥2502-70.5)-5.72X2502 =0b02 =80.05( Mpa)3 2300m: CT02 +(0.00074x3

20、00-70.525.72x300 =0O02 =81.23( Mpa)3 2350m: %2 + (0.00074X350-70.5)2022-5.72 咒 350 =002 82.59(M pa)3 2400m: cr02 (0.0007400 -70.5)-5.74000b02 =83.46( Mpa)3 2450m: %2 +(0.0007450 -70.5)-5.72X4502 =0b02 =84.17( Mpa)500m: cr023 +(0.00074% 5002 70.5-5.72X5002 =0b02 =84.72( Mpa)7.外过无风% - E2 01 - E4 E(t2

21、-t1)24% 24%带入数据得:叫-7600。6：103)2 汗=7还 7600(4竺203)2 汗1.4364(1&e2血 022247052即： =705（m pa）8.操作过电压一心-ti)ey22i2 ey12i2D02 = b01 22402 2401带入数据得:%-76000(465：10Wl2 =705-76000+34竺z。3)2/ ,4364(1&1324022牛 7Q52即：b023 + (0.000742 -70.5) b022 -3.80I2 = 0当档距为以下各值时，由状态方程求得应力:3 , 2 、 2 250m:乐2 +(0.00074X50 70.5) 02

22、3.80x50 =0b02 =70.56( Mpa)3 2100m: cr02 + (0.00074100 -70.5)%2 -3.80X1002 =0CT 02 =70.71(M pa)3 2150m: %2 +(0.00074X150 -70.5)b022 -3.80咒1502 =0% =70.87( Mpa)200m: %3 (0.000720070.5)-3.80X2002 =0b02 =71.03( Mpa)3 2250m: 02 + (0.00074X250 -70.5)2-3.80咒 250 =0O02 =71.56( Mpa)3 2300m: %2 (0.0007300 -70

23、.5)202-3.80X3002 =0% =71.26( Mpa)3 2350m: 02 + (0.0007350 -70.5)-3.83500%2 =71.33( Mpa)3 2400m: 02 + (0.00074X400 -70.5)%22-3.80X400 =002 =71.39( Mpa)3 2 2 2450m:500m:c02(0.0007450 -70.5) CJ02 -3.8450 =0o-02 =71.44( Mpa)3 2 2 2%2 (0.00074%500 -70.5 b02 -3.8500 =002 =71.47( Mpa)档距(m)最高气温(Mp a)最低气温(Mp

24、 a)最大风速(Mp a)覆冰无风(Mp a)年均温(Mp a)5038.86105.3998.8199.0870.5010045.20102.5097.7898.7870.5015050.4498.3096.4098.3870.5020054.4993.5894.9797.9870.5025057.5888.8293.681 97.4370.5030059.9585.0692.6997.3270.5035061.7882.2391.8397.0270.5040063.2179.8091.091 96.8870.5045064.3378.0290.5196.7370.5050065.2476.

25、7590.1596.6170.50LGJ-30050型导线应力计算表表七续表档距(m)安装(Mpa)外过有风(Mp a)外过无风(Mp a)操作过电压(Mp a)5098.3171.4570.570.5610095.8673.7870.570.7115092.3876.0870.570.8720088.6078.1670.571.0325085.1280.0570.571.5630082.2481.2370.571.2635079.9882.5970.571.3340078.2683.4670.571.3945076.9484.1770.571.4450075.9385.7270.571.47

26、六、计算弧垂1.最高温:3 250m: f =34也2竺8x38.86= 0.274(m)100m: f150m: f200m: f250m: f300m: f350m: f400m: f450m: f500m: f2.外过无风:34.06 x10-3 x10028x45.20= 0.912(m)3 234.06X10- X150= 1.90(m)8x50.4434.06 x10-3 x20028x54.49= 3.13(m)34.06 x10-3 x25028 x 57.58= 4.62(m)-3 234.06x10 X3008X59.95= 6.39(m)34.06x10-3 x35028

27、X61.78= 8.44(m)34.06 x10-3 x40028X63.21= 10.78(m)34.06 x10-3 x 45028 咒 64.33= 13.40(m)34.06X10-3 x50028X65.24= 16.31(m)-3 250m: f =34.060 508X70.5= 0.14(m)100m: f150m: f200m: f250m: f300m: f350m: f400m: f450m: f500m: f3.覆冰无风:3 234.06x10- x1008x70.5= 0.55(m)34.06 x10-3 x15028x70.5= 1.24(m)34.06咒10-3 咒20028x70.5= 2