C语言程序设计谭浩强第四版课后答案解析.docx

1、C语言程序设计谭浩强第四版课后答案解析第一章 程序设计和C语言 【第15页】1-5 #include int main ( ) printf (*nn); printf( Very Good!nn); printf (*n); return 0;1-6#include int main()int a,b,c,max; printf(please input a,b,c:n); scanf(%d,%d,%d,&a,&b,&c); max=a; if (maxb) max=b; if (maxc) max=c; printf(The largest number is %dn,max); retu

2、rn 0;第2章算法程序的灵魂 【第36页】暂无答案第3章最简单的C程序设计顺序程序设计 【第82页】3-1 #include #include int main()float p,r,n; r=; n=10; p=pow(1+r,n); printf(p=%fn,p); return 0;3-2-1#include #include int main()float r5,r3,r2,r1,r0,p,p1,p2,p3,p4,p5; p=1000; r5=; r3=; r2=; r1=; r0=; p1=p*(1+r5)*5); #include #include int main()float

3、 d=300000,p=6000,r=,m; m=log10(p/(p-d*r)/log10(1+r); printf(m=%n,m); return 0;3-4#include int main()int c1,c2; c1=197; c2=198; printf(c1=%c,c2=%cn,c1,c2); printf(c1=%d，c2=%dn,c1,c2); return 0;3-5#include int main()int a,b; float x,y; char c1,c2; scanf(a=%d b=%d,&a,&b); scanf(%f %e,&x,&y); scanf(%c%c

4、,&c1,&c2); printf(a=%d,b=%d,x=%f,y=%f,c1=%c,c2=%cn,a,b,x,y,c1,c2); return 0;3-6#include int main()char c1=C,c2=h,c3=i,c4=n,c5=a; c1=c1+4; c2=c2+4; c3=c3+4; c4=c4+4; c5=c5+4; printf(passwor is %c%c%c%c%cn,c1,c2,c3,c4,c5); return 0;3-7#include int main ()float h,r,l,s,sq,vq,vz; float pi=; printf(请输入圆半

5、径r，圆柱高h); scanf(%f,%f,&r,&h); #include int main() int x,y; printf(输入x:); scanf(%d,&x); if(x1) /* x1 */ y=x; printf(x=%3d, y=x=%dn ,x,y); else if(x10) /* 1=x=10 */ y=3*x-11; printf(x=%d, y=3*x-11=%dn,x,y); return 0;4-7-1#include int main() int x,y; printf(enter x:); scanf(%d,&x); y=-1; if(x!=0) if(x0

6、) y=1; else y=0; printf(x=%d,y=%dn,x,y); return 0;4-7-2#include int main() int x,y; printf(please enter x:); scanf(%d,&x); y=0; if(x=0) if(x0) y=1; else y=-1; printf(x=%d,y=%dn,x,y); return 0;4-8#include int main() float score; char grade; printf(请输入学生成绩:); scanf(%f,&score); while (score100|score0)

7、printf(n 输入有误,请重输); scanf(%f,&score); switch(int)(score/10) case 10: case 9: grade=A;break; case 8: grade=B;break; case 7: grade=C;break; case 6: grade=D;break; case 5: case 4: case 3: case 2: case 1: case 0: grade=E; printf(成绩是 %,相应的等级是%cn ,score,grade); return 0;4-9#include #include int main() int

8、 num,indiv,ten,hundred,thousand,ten_thousand,place; .=%dn,sn); return 0; 5-6#include int main() double s=0,t=1; int n; for (n=1;n=20;n+) t=t*n; s=s+t; printf(1!+2!+.+20!=%n,s); return 0;5-7#include int main() int n1=100,n2=50,n3=10; double k,s1=0,s2=0,s3=0; for (k=1;k=n1;k+) /*计算1到100的和*/ s1=s1+k; f

9、or (k=1;k=n2;k+) /*计算1到50各数的平方和*/ s2=s2+k*k; for (k=1;k=n3;k+) /*计算1到10的各倒数和*/ s3=s3+1/k; printf(sum=%n,s1+s2+s3); return 0; 5-8#include int main() int i,j,k,n; printf(parcissus numbers are ); for (n=100;n1000;n+) i=n/100; j=n/10-i*10; k=n%10; if (n=i*i*i + j*j*j + k*k*k) printf(%d ,n); printf(n); r

10、eturn 0; 5-9-1#define M 1000 /*定义寻找范围*/#include int main() int k1,k2,k3,k4,k5,k6,k7,k8,k9,k10; int i,a,n,s; for (a=2;a=M;a+) /* a是2-1000之间的整数，检查它是否完数 */ n=0; /* n用来累计a的因子的个数 */ s=a; /* s用来存放尚未求出的因子之和，开始时等于a */ for (i=1;i1) printf(%d,%d,k1,k2); /* n1表示a至少有2个因子 */ if (n2) printf(,%d,k3); /* n2表示至少有3个因

11、子，故应再输出一个因子 */ if (n3) printf(,%d,k4); /* n3表示至少有4个因子，故应再输出一个因子 */ if (n4) printf(,%d,k5); /* 以下类似 */ if (n5) printf(,%d,k6); if (n6) printf(,%d,k7); if (n7) printf(,%d,k8); if (n8) printf(,%d,k9); if (n9) printf(,%d,k10); printf(n); return 0; 5-9-2#include int main() int m,s,i; for (m=2;m1000;m+) s

12、=0; for (i=1;im;i+) if (m%i)=0) s=s+i; if(s=m) printf(%d,its factors are ,m); for (i=1;im;i+) if (m%i=0) printf(%d ,i); printf(n); return 0; 5-10#include int main() int i,n=20; double a=2,b=1,s=0,t; for (i=1;i=n;i+) s=s+a/b; t=a, a=a+b, b=t; printf(sum=%n,s); return 0; 5-11#include int main() double

13、 sn=100,hn=sn/2; int n; for (n=2;n=10;n+) sn=sn+2*hn; /*第n次落地时共经过的米数*/ hn=hn/2; /*第n次反跳高度*/ printf(第10次落地时共经过%f米n,sn); printf(第10次反弹%f米n,hn); return 0; 5-12#include int main() int day,x1,x2; day=9; x2=1; while(day0) x1=(x2+1)*2; /*第1天的桃子数是第2天桃子数加1后的2倍.*/ x2=x1; day-; printf(total=%dn,x1); return 0;

14、5-13#include #include int main() float a,x0,x1; printf(enter a positive number:); scanf(%f,&a); x0=a/2; x1=(x0+a/x0)/2; do x0=x1; x1=(x0+a/x0)/2; while(fabs(x0-x1)=1e-5); printf(The square root of % is %n,a,x1); return 0; 5-14#include #include int main() double x1,x0,f,f1; x1=; do x0=x1; f=(2*x0-4)*

15、x0+3)*x0-6; f1=(6*x0-8)*x0+3; x1=x0-f/f1; while(fabs(x1-x0)=1e-5); printf(The root of equation is %n,x1); return 0; 5-15#include #include int main() float x0,x1,x2,fx0,fx1,fx2; do printf(enter x1 & x2:); scanf(%f,%f,&x1,&x2); fx1=x1*(2*x1-4)*x1+3)-6; fx2=x2*(2*x2-4)*x2+3)-6; while(fx1*fx20); do x0=(

16、x1+x2)/2; fx0=x0*(2*x0-4)*x0+3)-6; if (fx0*fx1)=1e-5); printf(x=%n,x0); return 0; 5-16#include int main() int i,j,k; for (i=0;i=3;i+) for (j=0;j=2-i;j+) printf( ); for (k=0;k=2*i;k+) printf(*); printf(n); for (i=0;i=2;i+) for (j=0;j=i;j+) printf( ); for (k=0;k=4-2*i;k+) printf(*); printf(n); return

17、0; 5-17#include int main() char i,j,k; /*是a的对手;j是b的对手;k是c的对手*/ for (i=x;i=z;i+) for (j=x;j=z;j+) if (i!=j) for (k=x;k=z;k+) if (i!=k & j!=k) if (i!=x & k!=x & k!=z) printf(A-%cnB-%cnC-%cn,i,j,k); return 0; 第6章利用数组处理批量数据 【第168页】6-1#include #include int main()int i,j,n,a101; for (i=1;i=100;i+) ai=i; a

18、1=0; for (i=2;isqrt(100);i+) for (j=i+1;j=100;j+) if(ai!=0 & aj!=0) if (aj%ai=0) aj=0; printf(n); for (i=2,n=0;i=100;i+) if(ai!=0) printf(%5d,ai); n+; if(n=10) printf(n); n=0; printf(n); return 0;6-2#include int main()int i,j,min,temp,a11; printf(enter data:n); for (i=1;i=10;i+) printf(a%d=,i); scan

19、f(%d,&ai); printf(n); printf(The orginal numbers:n); for (i=1;i=10;i+) printf(%5d,ai); printf(n); for (i=1;i=9;i+) min=i; for (j=i+1;jaj) min=j; temp=ai; ai=amin; amin=temp; printf(nThe sorted numbers:n); for (i=1;i=10;i+) printf(%5d,ai); printf(n); return 0; 6-3#include int main()int a33,sum=0;int

20、i,j; printf(enter data:n); for (i=0;i3;i+) for (j=0;j3;j+) scanf(%3d,&aij); for (i=0;i3;i+) sum=sum+aii; printf(sum=%6dn,sum); return 0;6-4#include int main() int a11=1,4,6,9,13,16,19,28,40,100; int temp1,temp2,number,end,i,j; printf(array a:n); for (i=0;iend) a10=number; else for (i=0;inumber) temp

21、1=ai; ai=number; for (j=i+1;j11;j+) temp2=aj; aj=temp1; temp1=temp2; break; printf(Now array a:n); for (i=0;i11;i+) printf(%5d,ai); printf(n); return 0; 6-5#include #define N 5int main() int aN,i,temp; printf(enter array a:n); for (i=0;iN;i+) scanf(%d,&ai); printf(array a:n); for (i=0;iN;i+) printf(

22、%4d,ai); for (i=0;iN/2;i+) n,number); printf(continu or not(Y/N); scanf( %c,&c); if (c=N|c=n) flag=0; return 0; 6-10#include int main() int i,j,upp,low,dig,spa,oth; char text380; upp=low=dig=spa=oth=0; for (i=0;i3;i+) printf(please input line %d:n,i+1); gets(texti); for (j=0;j=A& textij=a & textij=0 & textij=9) dig+; else if (textij= ) spa+; else oth+; printf(nupper case: %dn,upp); printf(lower case: %dn,low); printf(digit : %dn,dig); printf(space : %dn,spa); printf(other : %dn,oth); return 0;6-11#include int main() char a5=*,*,*,*,*; int i