谭浩强C习题答案.docx

1、谭浩强C习题答案第一章1.6main()int a,b,c,max; printf(input three numbers:n); scanf(%d,%d,%d,&a,&b,&c); max=a; if(maxb)max=b; if(maxc)max=c; printf(max=%d,max);第二章2.3(1)(10)10=(12)8=(a)16(2)(32)10=(40)8=(20)16(3)(75)10=(113)8=(4b)16(4)(-617)10=(176627)8=(fd97)16(5)(-111)10=(177621)8=(ff91)16(6)(2483)10=(4663)8=

2、(963)16(7)(-28654)10=(110022)8=(9012)16(8)(21003)10=(51013)8=(520b)162.6aabb (8)cc (8)abc (7)AN2.7main()char c1=C,c2=h,c3=i,c4=n,c5=a; c1+=4, c2+=4, c3+=4, c4+=4, c5+=4; printf(%c%c%c%c%cn,c1,c2,c3,c4,c5);2.8main()int c1,c2; c1=97;c2=98; printf(%c %c,c1,c2);2.9(1)=2.5(2)=3.52.109,11,9,102.12(1)24 (2

3、)10 (3)60 (4)0 (5)0 (6)0第三章3.4main()int a,b,c; long int u,n; float x,y,z; char c1,c2; a=3;b=4;c=5; x=1.2;y=2.4;z=-3.6; u=51274;n=128765; c1=a;c2=b; printf(n); printf(a=%2d b=%2d c=%2dn,a,b,c); printf(x=%8.6f,y=%8.6f,z=%9.6fn,x,y,z); printf(x+y=%5.2f y+z=%5.2f z+x=%5.2fn,x+y,y+z,z+x); printf(u=%6ld n

4、=%9ldn,u,n); printf(c1=%cor %d(ASCII)n,c1,c1); printf(c2=%cor %d(ASCII)n,c2,c2);3.557 5 767.856400,-789.12396267.856400,-789.123962 67.86 -789.12,67.856400,-789.123962,67.856400,-789.1239626.785640e+001,-7.89e+002A,65,101,411234567,4553207,d68765535,177777,ffff,-1COMPUTER, COM3.6a=3 b=7/x=8.5 y=71.8

5、2/c1=A c2=a/3.7 10 20Aa1.5 -3.75 +1.4,67.8/(空3)10(空3)20Aa1.5(空1)-3.75(空1)(随意输入一个数），67.8回车3.8main()float pi,h,r,l,s,sq,sv,sz; pi=3.1415926; printf(input r,hn); scanf(%f,%f,&r,&h); l=2*pi*r; s=r*r*pi; sq=4*pi*r*r; sv=4.0/3.0*pi*r*r*r; sz=pi*r*r*h; printf(l=%6.2fn,l); printf(s=%6.2fn,s); printf(sq=%6.2

6、fn,sq); printf(vq=%6.2fn,sv); printf(vz=%6.2fn,sz);3.9main()float c,f; scanf(%f,&f); c=(5.0/9.0)*(f-32); printf(c=%5.2fn,c);3.10#includestdio.hmain()char c1,c2; scanf(%c,%c,&c1,&c2); putchar(c1); putchar(c2); printf(n); printf(%c%cn,c1,c2);第四章4.3(1)0 (2)1 (3)1 (4)0 (5)14.4main()int a,b,c; scanf(%d,%

7、d,%d,&a,&b,&c); if(ab) if(bc) printf(max=%dn,c); else printf(max=%dn,b); else if(ab)?a:b; max=(ctemp)?c:temp; printf(max=%d,max); 4.5main()int x,y; scanf(%d,&x); if(x1)y=x; else if(x=0&score9999) place=5; else if(num999) place=4; else if(num99) place=3; else if(num9) place=2; else place=1; printf(pl

8、ace=%dn,place); ten_thousand=num/10000; thousand=(num-ten_thousand*10000)/1000; hundred=(num-ten_thousand*10000-thousand*1000)/100; ten=(num-ten_thousand*10000-thousand*1000-hundred*100)/10; indiv=num-ten_thousand*10000-thousand*1000-hundred*100-ten*10; switch(place) case 5:printf(%d,%d,%d,%d,%dn,te

9、n_thousand,thousand,hundred,ten,indiv); printf(%d,%d,%d,%d,%dn,indiv,ten,hundred,thousand,ten_thousand); break; case 4:printf(%d,%d,%d,%dn,thousand,hundred,ten,indiv); printf(%d,%d,%d,%dn,indiv,ten,hundred,thousand); break; case 3:printf(%d,%d,%dn,hundred,ten,indiv); printf(%d,%d,%dn,indiv,ten,hundr

10、ed); break; case 2:printf(%d,%dn,ten,indiv); printf(%d,%dn,indiv,ten); break; case 1:printf(%dn,indiv); printf(%dn,indiv); 4.8main()long i; float bonus,bon1,bon2,bon4,bon6,bon10; bon1=100000*0.1; bon2=bon1+100000*0.075; bon4=bon2+200000*0.05; bon6=bon4+200000*0.03; bon10=bon6+400000*0.015; scanf(%ld

11、,&i); if(i=1e5)bonus=i*0.1; else if(i=2e5)bonus=bon1+(i-100000)*0.075; else if(i=4e5)bonus=bon2+(i-200000)*0.05; else if(i=6e5)bonus=bon4+(i-400000)*0.03; else if(i10)branch=10; switch(branch) case 0:bonus=i*0.1;break; case 1:bonus=bon1+(i-100000)*0.075;break; case 2: case 3:bonus=bon2+(i-200000)*0.

12、05;break; case 4: case 5:bonus=bon4+(i-400000)*0.03;break; case 6: case 7 case 8: case 9:bonus=bon6+(i-600000)*0.015;break; case 10:bonus=bon10+(i-1000000)*0.01; printf(bonus=%10.2f,bonus); 4.9main()int t,a,b,c,d; scanf(%d,%d,%d,%d,&a,&b,&c,&d); if(ab)t=a;a=b;b=t; if(ac)t=a;a=c;c=t; if(ad)t=a;a=d;d=

13、t; if(bc)t=b;b=c;c=t; if(bd)t=b;b=d;d=t; if(cd)t=c;c=d;d=t; printf(%d %d %d %dn,a,b,c,d);4.10main()int h=10; float x,y,x0=2,y0=2,d1,d2,d3,d4; scanf(%f,%f,&x,&y); d1=(x-x0)*(x-x0)+(y-y0)*(y-y0); d2=(x-x0)*(x-x0)+(y+y0)*(y+y0); d3=(x+x0)*(x+x0)+(y-y0)*(y-y0); d4=(x+x0)*(x+x0)+(y+y0)*(y+y0); if(d11&d21

14、&d31&d41)h=0; printf(h=%d,h);第五章 循环控制5.1main()int a,b,num1,num2,temp; scanf(%d,%d,&num1,&num2); if(num1=a&c=A&c=0&c=9)digit+; else other+; printf(letters=%dnspace=%dndigit=%dnother=%dn,letters,space,digit,other);5.3main()int a,n,count=1,sn=0,tn=0; scanf(%d,%d,&a,&n); while(count=n) tn+=a; sn+=tn; a*

15、=10; +count; printf(a+aa+aaa+.=%dn,sn);5.4main()float n,s=0,t=1; for(n=1;n=20;n+) t*=n; s+=t; printf(s=%en,s);5.5main()int N1=100,N2=50,N3=10; float k; float s1=0,s2=0,s3=0; for(k=1;k=N1;k+)s1+=k; for(k=1;k=N2;k+)s2+=k*k; for(k=1;k=N3;k+)s3+=1/k; printf(s=%8.2fn,s1+s2+s3);5.6main()int i,j,k,n; for(n

16、=100;n1000;n+) i=n/100; j=n/10-i*10; k=n%10; if(i*100+j*10+k=i*i*i+j*j*j+k*k*k) printf(n=%dn,n); 5.7#define M 1000main()int k0,k1,k2,k3,k4,k5,k6,k7,k8,k9; int i,j,n,s; for(j=2;j=M;j+) n=0; s=j; for(i=1;i1)printf(%d,%d,k0,k1); if(n2)printf(,%d,k2); if(n3)printf(,%d,k3); if(n4)printf(,%d,k4); if(n5)pr

17、intf(,%d,k5); if(n6)printf(,%d,k6); if(n7)printf(,%d,k7); if(n8)printf(,%d,k8); if(n9)printf(,%dn,k9); main()static int k10; int i,j,n,s; for(j=2;j=1000;j+) n=-1; s=j; for(i=1;ij;i+) if(j%i)=0) n+; s=s-i; kn=i; if(s=0) printf(j=%dn,j); for(i=0;in;i+) printf(%d,ki); printf(%dn,kn); 5.8main()int n,t,n

18、umber=20; float a=2;b=1;s=0; for(n=1;n=number;n+) s=s+a/b; t=a,a=a+b,b=t; printf(s=%9.6fn,s);5.9main()float sn=100.0,hn=sn/2; int n; for(n=2;n0) x1=(x2+1)*2; x2=x1; day-; printf(x1=%dn,x1);5.11#includemath.hmain()float a,xn0,xn1; scanf(%f,&a); xn0=a/2; xn1=(xn0+a/xn0)/2; do xn0=xn1; xn1=(xn0+a/xn0)/

19、2; while(fabs(xn0-xn1)=1e-5); printf(a=%5.2fn,xn1=%8.2fn,a,xn1);5.12#includemath.hmain()float x,x0,f,f1; x=1.5; do x0=x; f=(2*x0-4)*x0+3)*x0-6; f1=(6*x0-8)*x0+3; x=x0-f/f1; while(fabs(x-x0)=1e-5); printf(x=%6.2fn,x);5.13#includemath.hmain()float x0,x1,x2,fx0,fx1,fx2; do scanf(%f,%f,&x1,&x2); fx1=x1*

20、(2*x1-4)*x1+3)-6; fx2=x2*(2*x2-4)*x2+3)-6; while(fx1*fx20); do x0=(x1+x2)/2; fx0=x0*(2*x0-4)*x0+3)-6; if(fx0*fx1)=1e-5); printf(x0=%6.2fn,x0);5.14main()int i,j,k; for(i=0;i=3;i+) for(j=0;j=2-i;j+) printf( ); for(k=0;k=2*i;k+) printf(*); printf(n); for(i=0;i=2;i+) for(j=0;j=i;j+) printf( ); for(k=0;k

21、=4-2*i;k+) printf(*); printf(n); 5.15main()char i,j,k; for(i=x;i=z;i+) for(j=x;j=z;j+) if(i!=j) for(k=x;k=z;k+) if(i!=k&j!=k) if(i!=x&k!=x&k!=z) printf(na-%ctb-%ctc-%cn,i,j,k); 第六章 数组6.1 #include #define N 101 main() int i,j,line,aN; for (i=2;iN;i+) ai=i; for (i=2;isqrt(N);i+) for (j=i+1;jN;j+) if(ai!=0 & aj!=0) if (aj%ai=0) aj=0; printf(n); for (i=2,line=0;iN;i+) if(ai!=0) printf(%5d,ai); line+; if(line=10) printf(n); line=0; 6.2#define N 10main()int i,j,min,temp,aN; for(i=0;iN;i+) scanf(%d,&ai); for(i=0;iN-1;i+) min=i; for(j=i+1;jaj)min=j; t