java实验考试大纲101.docx

1、java实验考试大纲1011. 任意从键盘输入一个0到9999之间的数，判断输入的数是几位数。import javax.swing.JOptionPane; public class Count public static void main(String args) loopNumber(); static void loopNumber() int number=0,d4,d3,d2,d1; String str=JOptionPane.showInputDialog(输入一个0至9999之间的数); number=Integer.parseInt(str); if(number=0&nu

2、mber0) /判断number是4位数的条件 System.out.println(number+是4位数); else if(d4=0&d30) /判断number是3位数的条件 System.out.println(number+是3位数); else if(d2!=0) System.out.println(number+是2位数); else if(d1!=0) System.out.println(number+是1位数); else if(d4=0&d3=0&d2=0&d1=0) System.out.println(number+是1位数); else System.out.p

3、rintf(n%d不在0至9999之间,number); 2. 铁路运货的运费与路程远近及货物的重量有关，设有如下的单位运费：不足100千米，每吨每千米为1.0元100千米以上，不足300千米，每吨每千米为0.9元300千米以上，不足500千米，每吨每千米为0.8元500千米以上，不足1000千米，每吨每千米为0.7元1000千米以上，每吨每千米为0.6元编程：对输入的货物重量和路程，计算相应的运费。import java.util.Scanner; public class expenditure public double getExpenditure(double kilometer,

4、double ton) double ex = 0; if (kilometer = 100 & kilometer = 300 & kilometer = 500 & kilometer = 1000) ex = ton * kilometer * 0.6; return ex; public static void main(String args) double distance,weight; String s1 = null; expenditure e = new expenditure(); System.out.println(请输入路程：); Scanner scan2 =

5、new Scanner(System.in); s1= scan2.nextLine(); distance = Double.parseDouble(s1); String s2 = null; System.out.println(请输入重量：); Scanner t = new Scanner(System.in); s2 = scan2.nextLine(); weight = Double.parseDouble(s2); System.out.println(e.getExpenditure(distance, weight); 运行结果：3. 根据下面的要求实现圆类Circle。

6、 圆类Circle的成员变量：radius表示圆的半径。 圆类Circle的方法成员：Circle（）：构造方法，将半径置0。Circle（double r）：构造方法，创建Circle对象时将半径初始化为r。double getRadius（）：获得圆的半径值。double getPerimeter（）：获得圆的周长。void disp（）：将圆的半径、圆的周长和圆的面积输出到屏幕。import java.util.Scanner;public class Circle private double radius; public Circle() this.radius = 0; publi

7、c Circle(double r) this.radius = r; public double getRadius() return this.radius; public double getPerimeter() return 2 * Math.PI * this.radius; public double getArea() return Math.PI * this.radius * this.radius; public void disp() System.out.println(半径: + getRadius(); System.out.println(周长: + getPe

8、rimeter(); System.out.println(面积: + getArea(); public static void main(String args) String s1 = null;Circle e = new Circle(); System.out.println(请输入半径：); Scanner scan = new Scanner(System.in); s1= scan.nextLine(); e.radius= Double.parseDouble(s1); e.disp(); 运行结果：4、列出两个数m，n之间的所有素数import java.applet.*

9、; import java.awt.*;import java.awt.event.*;public class P extends Applet implements ActionListener Label result,name; TextField in1,in2; Button btn; int a=0,b=0,m,n,p; TextArea anser=new TextArea(5,30); public void init() result=new Label (请输入两个整形数据：); name=new Label (姓名 ：阿力木江 学号：2010101576); in1=n

10、ew TextField(5); in2=new TextField(5); btn=new Button (计算); add (name); add (result); add (in1); add (in2); add(btn); add(anser); btn.addActionListener(this); public void actionPerformed(ActionEvent e) int count=0; a=Integer.parseInt(in1.getText(); b=Integer.parseInt(in2.getText(); if(ab) m=a;a=b;b=

11、m; for(n=a;n=b;n+) for(p=2;p=n;p+) if(n%p=0) break; if(n=p) anser.append( +n+ ); count+=1; if(count%10=0) anser.append(n ); 运行结果：5.使用 java.util.Arrays，将Java所有关键字存在一个字符串数组中，判断一个字符串是否是Java关键字。Java所有关键字： abstract,boolean,break,byte,case,catch,char,class, continue,default,do,double,else,extends,false,fi

12、nal,finally,float,for,if, implements,import,instanceof,int,interface,long,native,new,null,package, private,protected,public,return,short,static,super,switch,synchronized,this, throw,throws,transient,true,try,void,volatile,whileimport java.util.Arrays;import java.util.List;public class aa public stat

13、ic void main(String args) String s = abstract,boolean,break,byte,case,catch,char,class, continue,default,do,double,else,extends,false,final,finally,float,for,if, implements,import,instanceof,int,interface,long,native,new,null,package, private,protected,public,return,short,static,super,switch,synchro

14、nized,this, throw,throws,transient,true,try,void,volatile,while; List l = Arrays.asList(s); System.out.println(被查字符串：throws); if(l.contains(throws) System.out.println(是java关键字); else System.out.println(不存在); System.out.println(我的学号：2010101576); 6.找出程序中错误，编译出正确结果；求二维数组的鞍点。鞍点是行中最大，列中最小。代码：public class

15、 Dort public static void main(String args) for (int i=0;imat.length;i+) for (int j=0;jmati.length;j+) System.out.print( +matij); System.out.println(); boolean find = false; int row=0; int max=0; while (!find & rowmat.length) max=0; for (int j=0;jmatrowmax) max = j; boolean yes = true; while (yes & j

16、mat.length) if (j!=row & matjmaxmatrowmax) yes = false; j+; if (yes) find = true; else row+; if (find) System.out.println(The dort: +matrowmax); else System.out.println(The dort: null); public class Dort public static void main(String args) int mat = 1,2,3,4,5,6,7,8,9; for (int i=0;imat.length;i+) f

17、or (int j=0;jmati.length;j+) System.out.print( +matij); System.out.println(); boolean find = false; int row=0; int max=0; while (!find & rowmat.length) max=0; for (int j=0;jmatrowmax) max = j; boolean yes = true; int j=0; while (yes & jmat.length) if (j!=row & matjmax0); System.out.println(); System.out.print(姓名：阿力木江 学号：2010101576);