1、SQL练习题例题1、写出一条Sql语句:取出表A中第31到第40记录 (Mysql)select * from Alimit 30, 10MS-SQLServer解1:select top 10 * from A where id not in (select top 30 id from A)解2:select top 10 * from A where id (select max(id) from (select top 30 id from A )as A)解3:select * from (select *, Row_Number() OVER (ORDER BY id asc) r
2、owid FROM A) as A where rowid between 31 and 40Oracleselect *from (select A.*,row_number() over (order by id asc) rankFROM A) where rank =31 AND rank=40;2、用一条SQL语句 查询出每门课都大于80分的学生姓名name kecheng fenshu张三语文 81张三数学 75李四语文 76李四数学 90王五语文 81王五数学 100王五英语 90A: select distinct name from table where name not
3、in (select distinct name from table where fenshu803、学生表 如下:自动编号学号姓名 课程编号 课程名称 分数1 2005001张三0001数学 692 2005002李四0001数学 893 2005001张三0001数学 69删除除了自动编号不同,其他都相同的学生冗余信息A: delete tablename where自动编号not in(select min(自动编号) from tablename group by学号,姓名,课程编号,课程名称,分数)4、请用SQL语句实现:从TestDB数据表中查询出所有月份的发生额都比101科目相
4、应月份的发生额高的科目。请注意:TestDB中有很多科目,都有112月份的发生额。AccID:科目代码,Occmonth:发生额月份,DebitOccur:发生额。数据库名:JcyAudit,数据集:Select * from TestDB答:select a.*from TestDB a,(select Occmonth,max(DebitOccur) Debit101ccur from TestDB where AccID=101 group by Occmonth) bwhere = and 5、一个叫team的表,里面只有一个字段name,一共有4条纪录,分别是a,b,c,d,对应四个
5、球对,现在四个球对进行比赛,用一条sql语句显示所有可能的比赛组合.你先按你自己的想法做一下,看结果有我的这个简单吗select , from team a, team bwhere 6、面试题:怎么把这样一个表儿year month amount1991 1 1991 2 1991 3 1991 4 1992 1 1992 2 1992 3 1992 4 查成这样一个结果year m1 m2 m3 m41991 1992 答案一、select year,(select amount from aaa m where month=1 and = as m1,(select amount fro
6、m aaa m where month=2 and = as m2,(select amount from aaa m where month=3 and = as m3,(select amount from aaa m where month=4 and = as m4from aaa group by year7、说明:复制表(只复制结构,源表名:a新表名:b)SQL: select * into b from a where 11 (where1=1,拷贝表结构和数据内容)Oracle:create table bAsSelect * from a where 1=2(不等于)(SQL
7、 Server Compact)比较两个表达式。 当使用此运算符比较非空表达式时,如果左操作数不等于右操作数,则结果为 TRUE。 否则,结果为 FALSE。8、说明:拷贝表(拷贝数据,源表名:a目标表名:b)SQL: insert into b(a, b, c) select d,e,f from a;9、说明:显示文章、提交人和最后回复时间SQL: select , from table a,(select max(adddate) adddate from table where = b10.说明:外连接查询(表名1:a表名2:b)SQL: select , , , , , from a
8、 LEFT OUTER JOIN b ON = ORACLE:select , , , , , from a ,bwhere = (+)11.说明:日程安排提前五分钟提醒SQL: select * from日程安排where datediff(minute,f开始时间,getdate()512.说明:两张关联表,删除主表中已经在副表中没有的信息SQL:Delete from info where not exists (select * from infobz where = )13.有两个表A和B,均有key和value两个字段,如果B的key在A中也有,就把B的value换为A中对应的va
9、lue这道题的SQL语句怎么写update b set =(select from a where = where in(select from b,a where =;高级sql面试题14.原表:courseid coursename score-1Java702 oracle 903 xml 404 jsp 305 servlet 80-为了便于阅读,查询此表后的结果显式如下(及格分数为60):courseid coursename score mark-1Java70 pass2 oracle 90 pass3 xml 40 fail4 jsp 30 fail5 servlet 80 p
10、ass-写出此查询语句select courseid, coursename ,score ,decode(sign(score-60),-1,fail,pass) as mark from course(SQL: select courseid, coursename ,score ,(case when score desc course_vName Null Type- - -COURSEID NUMBERCOURSENAME VARCHAR2(10)SCORE NUMBERSQL select * from course_v;COURSEID COURSENAME SCORE- - -
11、1 java 702 oracle 903 xml 404 jsp 305 servlet 80SQL select courseid, coursename ,score ,decode(sign(score-60),-1,fail,pass) as mark from course_v;COURSEID COURSENAME SCORE MARK- - - -1 java 70 pass2 oracle 90 pass3 xml 40 fail4 jsp 30 fail5 servlet 80 pass面试题(1)create table testtable1(id int IDENTIT
12、Y,department varchar(12)select * from testtable1insert into testtable1 values(设计)insert into testtable1 values(市场)insert into testtable1 values(售后)/*结果id department1 设计2 市场3 售后*/create table testtable2(id int IDENTITY,dptID int,name varchar(12)insert into testtable2 values(1,张三)insert into testtable2 values(1,李四)insert into testtable2 values(2,王五)insert into testtable2 values(3,彭六)insert into testtable2 values(4,陈七)/*用一条
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