ImageVerifierCode 换一换
格式:DOCX , 页数:19 ,大小:17.39KB ,
资源ID:29665962      下载积分:3 金币
快捷下载
登录下载
邮箱/手机:
温馨提示:
快捷下载时,用户名和密码都是您填写的邮箱或者手机号,方便查询和重复下载(系统自动生成)。 如填写123,账号就是123,密码也是123。
特别说明:
请自助下载,系统不会自动发送文件的哦; 如果您已付费,想二次下载,请登录后访问:我的下载记录
支付方式: 支付宝    微信支付   
验证码:   换一换

加入VIP,免费下载
 

温馨提示:由于个人手机设置不同,如果发现不能下载,请复制以下地址【https://www.bdocx.com/down/29665962.html】到电脑端继续下载(重复下载不扣费)。

已注册用户请登录:
账号:
密码:
验证码:   换一换
  忘记密码?
三方登录: 微信登录   QQ登录  

下载须知

1: 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。
2: 试题试卷类文档,如果标题没有明确说明有答案则都视为没有答案,请知晓。
3: 文件的所有权益归上传用户所有。
4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
5. 本站仅提供交流平台,并不能对任何下载内容负责。
6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

版权提示 | 免责声明

本文(结构矩阵分析与程序设计钢架vb代码.docx)为本站会员(b****8)主动上传,冰豆网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知冰豆网(发送邮件至service@bdocx.com或直接QQ联系客服),我们立即给予删除!

结构矩阵分析与程序设计钢架vb代码.docx

1、结构矩阵分析与程序设计钢架vb代码=Structural Analysis Program For Plane Frame=Option ExplicitPublic nn As Integer, ne As Integer, nd As Integer, ndf As IntegerPublic nf As Integer, npj As Integer, npe As Integer, n As IntegerPublic al(50) As Double, t(6, 6) As Double, x(40) As Double, y(40) As DoublePublic jl(50) A

2、s Integer, jr(50) As Integer, ea(50) As Double, ei(50) As DoublePublic c(6, 6) As Double, r(120, 120) As Double, p(120) As Double, pe(120) As DoublePublic ibd(20) As Integer, ii(6) As Integer, bd(20) As Double, ff(6) As DoublePublic mj(20) As Integer, qj(20, 3) As Double, f(6) As Double, dis(6) As D

3、oublePublic mf(30) As Integer, ind(30) As Double, aq(30) As Double, bq(30) As DoublePublic q1(30) As Double, q2(30) As Double=main program=Sub frame()Open H:juzheng钢架tr3.2.11.txt For Input As #1Open H:juzheng钢架tw3.2.11.txt For Output As #2Call input1Call wstiffCall loadCall boundCall gaussCall nqmCl

4、ose 1Close 2End Sub=SUB-1 Read And Print Intial Data=Sub input1()Dim inti As Integer, intj As Integer, i As Integer, j As Integer, k As IntegerDim dx, dy As Double Print #2, Plane Frame structural Analysis Print #2, * Print #2, input data Print #2, = = = = = Print #2, Print #2, structural control da

5、ta Print #2, - Print #2, nn; Spc(3); ne; Spc(3); nf; Spc(3); nd; Spc(3); ndf; Spc(2); npj; Spc(2); npe; Spc(3); n Input #1, nn, ne, nf, nd, ndf, npj, npe n = 3 * (nn - nf) Print #2, nn; Spc(2); ne; Spc(2); nf; Spc(2); nd; Spc(2); ndf; Spc(2); npj; Spc(2); npe; Spc(2); n Print #2, Print #2, Nodal coo

6、rdinates Print #2, - Print #2, Node ; Spc(2); x; Spc(5); yi = nn For inti = 1 To i Input #1, inti, x(inti), y(inti) Print #2, inti; Spc(2); x(inti); Spc(3); y(inti) Next intiPrint #2,Print #2, Element InformationPrint #2, -Print #2, Ele.No.; Spc(4); ; jl; Spc(4); jr; Spc(6); ea; Spc(6); ei; Spc(6);

7、ali = ne For inti = 1 To i Input #1, inti, jl(inti), jr(inti), ea(inti), ei(inti) Next intiFor inti = 1 To iIf jl(inti) = jr(inti) Then StopNext intiFor inti = 1 To i j = jl(inti) k = jr(inti) dx = x(k) - x(j) dy = y(k) - y(j) al(inti) = Sqr(dx * dx + dy * dy) Print #2, Spc(3); inti; Spc(4); jl(inti

8、); Spc(3); jr(inti); Spc(2); ea(inti); Spc(2); ei(inti); Spc(2); al(inti)Next intiPrint #2,k = npj If k 0 Then Print #2, Nodal Load Print #2, - Print #2, i; Spc(13); mj; Spc(3); xd; Spc(2); yd; Spc(2); md For inti = 1 To k Input #1, inti, mj(inti), qj(inti, 1), qj(inti, 2), qj(inti, 3) Print #2, int

9、i; Spc(1), mj(inti); Spc(1); qj(inti, 1); Spc(1); qj(inti, 2); Spc(1); qj(inti, 3) Next inti End If Print #2, i = npe If i 0 Then Print #2, Element loads Print #2, - Print #2, i; Spc(5); mf; Spc(3); ind; Spc(3); aq; Spc(3); bq; Spc(3); q1; Spc(4); q2 For inti = 1 To i Input #1, inti, mf(inti), ind(i

10、nti), aq(inti), bq(inti), q1(inti), q2(inti) Print #2, inti; Spc(2); mf(inti); Spc(3); ind(inti); Spc(2); aq(inti); Spc(2); bq(inti); Spc(2); q1(inti); Spc(3); q2(inti) Next intiEnd IfPrint #2, j = ndf If j 0 Then Print #2, Bonundary conditions Print #2, - Print #2, i; Spc(5); ibd; Spc(3); bdFor int

11、i = 1 To j Input #1, inti, ibd(inti), bd(inti) Print #2, inti; Spc(3); ibd(inti); Spc(3); bd(inti) Next inti End IfEnd Sub=sub-2 Assemnble Structural Stiffness MatrixR=Sub wstiff()Dim i As Integer, j As Integer, ie As Integer, k1 As Integer, k2 As IntegerFor i = 1 To n For j = 1 To n r(i, j) = 0 Nex

12、t jNext iie = 1Do While ie = ne Call stiff(ie) Call locat(ie)For k1 = 1 To 6 i = ii(k1) If i = n Then For k2 = k1 To 6 j = ii(k2) If j = n Then r(i, j) = r(i, j) + c(k1, k2) End If Next k2 End If Next k1 ie = ie + 1LoopFor i = 2 To n For j = 1 To (i - 1) r(i, j) = r(j, i) Next jNext iEnd Sub =sub-3

13、set up Stiffness Matrixc=Sub stiff(ie)Dim i As Integer, j As IntegerDim cx As Double, cy As Double, b1 As Double, b2 As Double, b3 As Double, b4 As DoubleDim s1 As Double, s2 As Double, s3 As Double, s4 As Double, s5 As Double, s6 As Doublei = jl(ie)j = jr(ie)cx = (x(j) - x(i) / al(ie)cy = (y(j) - y

14、(i) / al(ie)b1 = ea(ie) / al(ie)b2 = 12# * ei(ie) / al(ie) 3b3 = 6# * ei(ie) / al(ie) 2b4 = 2# * ei(ie) / al(ie)s1 = b1 * cx 2 + b2 * cy 2s2 = (b1 - b2) * cx * cys3 = b3 * cys4 = b1 * cy 2 + b2 * cx 2s5 = b3 * cxs6 = b4c(1, 1) = s1c(1, 2) = s2c(1, 3) = s3c(1, 4) = -s1c(1, 5) = -s2c(1, 6) = s3c(2, 2)

15、 = s4c(2, 3) = -s5c(2, 4) = -s2c(2, 5) = -s4c(2, 6) = -s5c(3, 3) = 2# * s6c(3, 4) = -s3c(3, 5) = s5c(3, 6) = s6c(4, 4) = s1c(4, 5) = s2c(4, 6) = -s3c(5, 5) = s4c(5, 6) = s5c(6, 6) = 2# * s6For i = 2 To 6 For j = 1 To (i - 1) c(i, j) = c(j, i) Next jNext iEnd Sub=sub-4 set up element location vector=

16、Sub locat(ie)Dim i As Integer, j As Integeri = jl(ie)j = jr(ie)ii(1) = 3 * i - 2ii(2) = 3 * i - 1ii(3) = 3 * iii(4) = 3 * j - 2ii(5) = 3 * j - 1ii(6) = 3 * jEnd Sub=SUB-5 Set Up Total Nodal Vector P= Sub load()Dim i As Integer, j As Integer, k As Integeri = 1Do While i 0 Then For i = 1 To npj k = mj

17、(i) p(3 * k - 2) = qj(i, 1) p(3 * k - 1) = qj(i, 2)p(3 * k) = qj(i, 3) Next iEnd IfIf npe 0 Then Call eload i = 1 Do While i = np(i) = p(i) + pe(i) i = i + 1LoopEnd IfEnd Sub=SUB-6 Set up element effective load= Sub eload()Dim i As Integer, j As Integer, k As Integer, k1 As Integer, k2 As Integer, k

18、3 As Integeri = 1 Do While i = n pe(i) = 0# i = i + 1Loopj = 1Do While j = npe k = mf(j) Call trans(k) Call locat(k) Call efix(j) For k1 = 1 To 6 f(k1) = 0# For k2 = 1 To 6 f(k1) = f(k1) + t(k2, k1) * ff(k2) Next k2Next k1For k3 = 1 To 6i = ii(k3) If i = n Then pe(i) = pe(i) - f(k3) End IfNext k3j =

19、 j + 1LoopEnd Sub =sub-7 set up fixed-end force of element=Sub efix(i)Dim j As Integer, k As IntegerDim s1 As Double, a As Double, b As Double, p1 As Double, p2 As DoubleDim b1 As Double, b2 As Double, b3 As Double, c1 As Double, c2 As Double, c3 As DoubleDim d1 As Double, d2 As DoubleFor j = 1 To 6

20、ff(j) = 0#Next jk = mf(i)s1 = al(k)a = aq(i)b = bq(i)p1 = q1(i)p2 = q2(i)b1 = s1 - (a + b) / 2#b2 = b - ab3 = (a + b) / 2#c1 = s1 - (2# * b + a) / 3#c2 = b2c3 = (2# * b + a) / 3#d1 = b 3 - a 3d2 = b * b - a * aSelect Case ind(i) Case 1 ff(2) = -p1 * (s1 - a) 2 * (1# + 2# * a / s1) / s1 2 ff(3) = p1

21、* a * (s1 - a) 2 / s1 2 ff(5) = -p1 - ff(2) ff(6) = -p1 * a 2 * (s1 - a) / s1 2 Case 2 ff(2) = -p1 * b2 * (12# * b1 2 * s1 - 8# * b1 3 + b2 2 * s1 - 2# * b1 * b2 2) / (4# * s1 3) ff(3) = p1 * b2 * (12# * b3 * b1 2 - 3 * b1 * b2 2 + b2 2 * s1) / 12# / s1 2 ff(5) = -p1 * b2 - ff(2) ff(6) = -p1 * b2 *

22、(12# * b3 2 * b1 + 3# * b1 * b2 2 - 2# * b2 2 * s1) / 12# / s1 2 Case 3 ff(2) = -p2 * c2 * (18 * c1 2 * s1 - 12 * c1 3 + c2 2 * s1 - 2 * c1 * c2 2 - 4 * c2 3 / 45) / 12 / s1 3 ff(3) = p2 * c2 * (18# * c3 * c1 2 - 3# * c1 * c2 2 + c2 2 * s1 - 2# * c2 3 / 15#) / 36# / s1 2 ff(5) = -0.5 * p1 * c2 - ff(

23、2) ff(6) = -p2 * c2 * (18# * c3 2 * c1 + 3 * c1 * c2 2 - 2 * c2 2 * s1 + 2 * c2 3 / 15#) / 36# / s1 2 Case 4 ff(2) = -6# * p1 * a * (s1 - a) / s1 3 ff(3) = p1 * (s1 - a) * (3# * a - s1) / s1 2 ff(5) = -ff(2) ff(6) = p1 * a * (2# * s1 - 3# * a) / s1 2 Case 5 ff(2) = -p1 * (3# * s1 * d2 - 2# * d1) / s

24、1 3 ff(3) = p1 * (2# * d2 + (b - a) * s1 - d1 / s1) / s1 ff(5) = -ff(2) ff(6) = p1 * (d2 - d1 / s1) / s1 Case 6 ff(1) = -p1 * (1# - a / s1) ff(4) = -p1 * a / s1 Case 7 ff(1) = -p1 * (b - a) * (1# - (b + a) / (2# * s1) ff(4) = -p1 * d2 / 2# / s1 Case 8 ff(3) = -a * (p1 - p2) * ei(k) / b ff(6) = -ff(3

25、)End SelectEnd Sub=sub-8 set up coordinate transfer matrixt=Sub trans(ie)Dim i As Integer, j As IntegerDim cx As Double, cy As Doublei = jl(ie)j = jr(ie)cx = (x(j) - x(i) / al(ie)cy = (y(j) - y(i) / al(ie)For i = 1 To 6 For j = 1 To 6 t(i, j) = 0# Next jNext iFor i = 1 To 4 Step 3 t(i, i) = cx t(i, i + 1) = cy t(i + 1, i) = -cy t(i + 1, i + 1) = cx t(i + 2, i + 2) = 1#Next iEnd Sub=sub-9 introduce support conditions= Sub bound()Dim i As Integer, j As Integer, k As IntegerDim a As Double If ndf 0 Then For j = 1 To ndf a = 1E+20 For i = 1 To ndf k = ibd(i) r(k, k) = a p(k) = a

copyright@ 2008-2022 冰豆网网站版权所有

经营许可证编号:鄂ICP备2022015515号-1