C语言编程题.docx

1、C语言编程题1、求1+2+3+.+100。（循环）答案#include void main() int i,sum=0; for(i=1;i=100;i+) sum=sum+i; printf(%d,sum); 2、 求1*2*3*.*10。（循环）答案void main() int i=0,j=1; for (i=2;i=10;i+) j*=i; printf(%d,j); return 0; 3、 输入三个数字，输出他们的最大值。（if）答案#includevoid main() int a,b,c,d; scanf(%d,%d,%d,&a,&b,&c); d=max(a,b,c); pr

2、intf(max=%d,d); getch();/*暂停看运行结果*/ int max(int x,int y,int z)int u; if(x=y&x=z) u=x; else if(y=x&y=z) u=y; else u=z; return(u); 4.用起泡法对十个数据排序（数组实现）答案#includemain ( )int i,j,t; static int a10=5,7,4,2,3,6,1,0,9,8; for(j=0;j9;j+) for(i=0;ia) t=a;a=a;a=t ; for(i=0;i10;i+)printf(%2d,a); 5、输入十个数字，逆序输出。（数

3、组实现）答案#includemain()int a10,i=0;for(i=0;i=0;i-)printf(%f,a);6输入两个数，交换他们的值并输出。(元素交换)答案#includeint main ()int m,n,temp;scanf(%d%d,&m,&n);if (mn)temp=m;m=n;n=temp;printf(%d,m);return 0;7.输出9*9乘法表。（双层循环)答案#include void main()int i=1;for(i; i=9; i+)int j=1;for(j;j=i;j+) printf(%d*%d=%d , i, j, i*j);print

4、f(n);8.输入一行字符，将所有的小写字母转换成大写字母，大写字母转换成小写字母，其余字符不变。输出转变后的这行字符。答案#include stdio.hvoid main()char an;int i;scanf(%s,a);printf(大写为：);for(i=0;i=n;i+) if(a=a) a=a-32; printf(%c,a);printf(n小写为：);for(i=0;i=65&c=97&c=48&c=100&x1000) a=0.01*x;b=10*(0.01*x-a);c=x-100*a-10*b;if(x=(pow(a,3)+pow(b,3)+pow(c,3) prin

5、tf(%5d,x);x+;6.7main()int m,i,j,s;for(m=6;m10000;m+)s=1;for(i=2;im;i+)if(m%i=0) s=s+i;if(m-s=0)printf(%5d its fastors are 1 ,m);for(j=2;jm;j+) if(m%j=0)printf(%d ,j);printf(n);或main()int m,i,j,s;for(m=6;m1000;m+)s=m-1;for(i=2;im;i+)if(m%i=0) s=s-i;if(s=0)printf(%5d its fastors are 1 ,m);for(j=2;jm;j

6、+) if(m%j=0)printf(%d ,j);printf(n);6.8main()int i=1,n;double t,x=1,y=2,s,sum=0;scanf(%ld,&n);while(i=n) s=y/x;sum=sum+s;t=y;y=y+x;x=t;i+;printf(%fn,sum);11，P128例6.10（译码）#includevoid main()char c;while(c=getchar()!=n)c=c+4;if(cZ+4|cz)c=c-26;printf(%c,c);printf(n);12，P1115.55.6（switch）5.5#include mai

7、n()int x,y;printf(输入x：);scanf(%d,&x);if(x1) y=x;printf(x=%3d, y=x=%dn,x,y);else if (x10) y=2*x-1;printf(x=%3d, y=2*x-1=%dn,x,y);else y=3*x-11;printf(x=%3d, y=3*x-11=%dn,x,y);5.6#include main() float score;char grade;case 2:printf(请输入学生成绩：);scanf(%f,&score);while(score100|(score0) printf(n输入有误,请重新输入：

8、);scanf(%f,&score);switch(int)(score/10) case 10:case 9: grade=A;break;case 8: grade=B;break;case 7: grade=C;break;case 6: grade=D;break;case 5:case 4:case 3:case 1:case 0: grade=E;printf(成绩是%5.1f，相应的等级是%c。n,score,grade);13，P108例5.5(一元二次方程求根)例5.6（求闰年）5.5#includevoid main()int year,leap;scanf(%d,&yea

9、r);if(year%4=0)if(year%100=0)if(year%400=0)leap=1;elseleap=0;elseleap=1;elseleap=0;if(leap)printf(%d is,year);elseprintf(%d is not,year);printf(a leap year.n)5.614，P31 例2.17 例2.182.17输出50个学生中成绩高于80分者的学号和成绩2.18输出20002500年每一年是否闰年#include void main() int year; year=2000; go: if(year%4 = 0)&(year%100 !=

10、 0) | (year%400 = 0) printf(%d is run nian,year); if(year2500) goto end;goto go; end: getch(); 1、求1+2+3+.+100。（循环）答案#include void main() int i,sum=0; for(i=1;i=100;i+) sum=sum+i; printf(%d,sum); 2、 求1*2*3*.*10。（循环）答案void main() int i=0,j=1; for (i=2;i=10;i+) j*=i; printf(%d,j); return 0; 3、 输入三个数字，输出他们的最大值。（if）答案#includevoid main() int a,b,c,d; scanf(%d,%d,%d,&a,&b,&c); d=max(a,b,c); printf(max=%d,d); getch();/*暂停看运行结果*/ int max(int x,int y,int z)int u; if(x