部分ACM题目与答案解析Word下载.docx

1、n）!=-1） for（i=0;i=n;i+） sum+=i; printf（%dnn,sum）; 1089 A+B for Input-Output Practice （I）Your task is to Calculate a + b.Too easy?! Of course! I specially designed the problem for acm beginners. You must have found that some problems have the same titles with this one, yes, all these problems were de

2、signed for the same aim. The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line. For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input. 1 510 20630lcyR

3、ecommendJGShining main（） int a,b; while（scanf（%d%da,&b）!=EOF）%dn,a+b）;1090 A+B for Input-Output Practice （II）Input contains an integer N in the first line, and then N lines follow. Each line consists of a pair of integers a and b, separated by a space, one pair of integers per line. 2#define M 1000v

4、oid main（） int a ,b,n,jM,i; /printf（please input n:n）; scanf（n）;n;b）;%d %d,a,b）; ji=a+b; i=0; while（in）,ji）; i+; 1091 A+B for Input-Output Practice （III）Input contains multiple test cases. Each test case contains a pair of integers a and b, one pair of integers per line. A test case containing 0 0 t

5、erminates the input and this test case is not to be processed.0 0 while（!（a=0&b=0）1092 A+B for Input-Output Practice （IV）Your task is to Calculate the sum of some integers.Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test cas

6、e starting with 0 terminates the input and this test case is not to be processed.For each group of input integers you should output their sum in one line, and with one line of output for each line in input. 4 1 2 3 45 1 2 3 4 50 1015#include int main（） int n,sum,i,t;=EOF&n!=0）t）; sum=sum+t;1093 A+B

7、for Input-Output Practice （V）Your task is to calculate the sum of some integers.Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line. int n,a,b,i,j,sum;=-1） for（j=0;jb;j+）a）; sum+=a;1094 A+B for Input-O

8、utput Practice （VI）Input contains multiple test cases, and one case one line. Each case starts with an integer N, and then N integers follow in the same line. For each test case you should output the sum of N integers in one line, and with one line of output for each line in input. Copy to Clipboard

9、 Save to File1095 A+B for Input-Output Practice （VII）For each pair of input integers a and b you should output the sum of a and b, and followed by a blank line. 1096 A+B for Input-Output Practice （VIII）For each group of input integers you should output their sum in one line, and you must note that t

10、here is a blank line between outputs.33 1 2 3 int a,b,i,j,l1000,k;i）; getchar（）; for（j=1;=i; lj=0; for（k=1;k=b） if（c=a）%c %c %cn,b,a,c）; else if（b=c）,c,b,a）; else if（b,a,c,b）; else if（a,c,a,b）;2001计算两点间的距离输入两点坐标（X1,Y1）,（X2,Y2）,计算并输出两点间的距离。输入数据有多组，每组占一行，由4个实数组成，分别表示x1,y1,x2,y2,数据之间用空格隔开。对于每组输入数据，输出一行

11、，结果保留两位小数。0 0 0 10 1 1 01.001.41math.h double a,b,c,d,s;%lf %lf %lf %lfc,&d）! s=sqrt（a-c）*（a-c）+（b-d）*（b-d）;%.2lfn,s）; 2002计算球体积根据输入的半径值，计算球的体积。输入数据有多组，每组占一行，每行包括一个实数，表示球的半径。输出对应的球的体积，对于每组输入数据，输出一行，计算结果保留三位小数。1.54.18914.137Hint#define PI 3.1415927 double a,v;%lfa）! v=4*PI*a*a*a/3;%.3lfn,v）;2003求绝对值求

12、实数的绝对值。输入数据有多组，每组占一行，每行包含一个实数。对于每组输入数据，输出它的绝对值，要求每组数据输出一行，结果保留两位小数。123-234.00123.00234.00 double a; if（a100|n=90）printf（An=80）printf（Bn=70）printf（Cn=60）printf（Dn else printf（En return 0;2005第几天？给定一个日期，输出这个日期是该年的第几天。输入数据有多组，每组占一行，数据格式为YYYY/MM/DD组成，具体参见sample input ,另外，可以向你确保所有的输入数据是合法的。对于每组输入数据，输出一行，表示该日期是该年的第几天。1985/1/202006/3/122071 int a,b,c,d,e,f,g;%d/%d/%d if（b=1） d=c; else if（b=2） d=31+c; else if（b=3） d=31+28+c; else if（b=4） d=31+28+31+c;