1、 & m & 个数:) m = m + 1n = InputBox(查找的数是:i = 0: flag = FalseDo If a(i) = n Then j = i: flag = True For k = j To UBound(a) - 1 a(k) = a(k + 1) Next k ReDim Preserve a(UBound(a) - 1) i = i - 1End If i = i + 1Loop While (i = UBound(a)If flag = False Then MsgBox n &不在该数组中Else删除 n &后的数组是: For i = 0 To UBo
2、und(a)3数组a中存放着升序排列的数据,使用array赋值,将inputbox输入的新数插入到数组中,插入后数组仍有序。要求利用动态数组,能够实现多次插入n = 8: ReDim a(n)a = Array(5, 15, 23, 52, 68, 88, 90, 99)n = n + 1: ReDim Preserve a(n)m = InputBox(请输入要插入的数据:For i = 1 To n - 1 If m singer(i).fenshu(k) Then t = singer(i).fenshu(j) singer(i).fenshu(j) = singer(i).fenshu
3、(k) singer(i).fenshu(k) = t End If For j = 2 To 5 singer(i).score = singer(i).score + singer(i).fenshu(j) singer(i).pingjun = singer(i).score / 4 For i = 1 To 3 For j = i To 4 If singer(i).score max Then max = a(i, j) If a(i, j) min Then min = a(i, j) sum = sum + a(i, j) Next j ave = (sum - max - mi
4、n) / (n - 2) b(i) = ave For j = i + 1 To n If b(i) b(j) Then t = b(i): b(i) = b(j): b(j) = t选手的得分由高到低为: Print b(i);5编写函数求一元二次方程ax2+bx+c=0的解。要求考虑方程有两相等实根、两不等实根和两个虚根的情况。Dim a As Single, b As Single, c As SingleDim s As Singlea = InputBox(请输入ab = InputBox(请输入bc = InputBox(请输入cs = b 2 - 4 * a * cIf s 47
5、 And Asc(Mid(a, i, 1) 96 And Asc(Mid(a, i, 1) 123 Then 64 And Asc(Mid(a, i, 1) 91 Then p = p + 17随机产生一个5*5的矩阵,将主对角线和次对角线元素都置为1,并求出矩阵的四周元素之和,显示在列表框中。Dim a(5, 5) As IntegerDim s As IntegerFor i = 1 To 5 If i = j Or i = 6 - j Then a(i, j) = 1 Else a(i, j) = Int(Rnd * 1000) Text1.Text = Text1.Text & a(i
6、, j) s = s + a(i, j) vbCrLf & vbCrLfList1.AddItem (s)8编写一个函数,能将字母按下列规律译成密码:AZ azBY by即第1个字母与第26个字母互换,第i个字母与第(26-i+1)个字母互换。在文本框中任意输入一个字符串,调用该函数将密码显示在另一个文本框中。Dim s1 As Strings1 = Text1.Text Text2.Text = convert(s1)Private Function convert(s1 As String) As StringFor i = 1 To Len(s1) If Asc(Mid(s1, i, 1
7、) 64 Then convert = convert & Chr(91 - Asc(Mid(s1, i, 1) + 64) ElseIf Asc(Mid(s1, i, 1) 96 Then Chr(123 - Asc(Mid(s1, i, 1) + 96)End Function9编写2个函数,分别求两个正整数的最大公约数和最小公倍数,用户任意输入两个数,采用函数嵌套调用,该函数将它们在窗体显示。Text1 = : Text2 = Private Sub Text1_KeyPress(KeyAscii As Integer) If KeyAscii = 13 Then Text2.SetFo
8、cusPrivate Sub Text2_KeyPress(KeyAscii As Integer)Dim m As Integer, n As Integer, r As Integer, t As Integer, xClsIf KeyAscii = 13 Then m = Text1.Text n = Text2.Text n Then t = m: m = n: n = t r = m Mod n While r 0 n = r: Wend Print 0 Or n x = MsgBox(请输入正数, vbCritical + vbOKCancel) If x = vbCancel T
9、hen End Text1 = Text1.SetFocus Print Text1.Text &和 Text2.Text &的最大公约数是:; n10. 编写计算阶乘的Function过程,利用ex的下列公式计算e(直到最后一项小于10-6为止)的近似值。ex1+x/1!+x2/2!+x3/3!+xn/n! Option ExplicitDim x As Integer, n As Integer, s As Doublex = InputBox(请输入一个数:n = 1: s = 1 s = s + x n / (jiecheng(n)Loop Until x n / (jiecheng(
10、n) i Then a(i, j) = 0 If i = j Then a(i, j) = a(i - 1, j) + a(i - 1, j - 1) If a(i, j) = 0 Then Exit For Picture1.Print Tab(g); a(i, j); g = g + 10 Picture1.PrintPrivate Sub Picture1_Click()12编写一个过程,输出以下菱形图形: A BBB CCCCC DDDDDDD主程序输入一个奇数(3),调用过程在窗体上输入图形。Dim n As IntegerIf n Mod 2 = 0 Or n = 3 Then错误
11、 Call draw(n)Sub draw(n As Integer)For i = 1 To (n + 1) / 2 s = Chr(64 + i) Print Tab(41 - i + 1); String(2 * (i - 1) + 1, s)c = 1For j = (n - 1) / 2 To 1 Step (-1) c = c + 1 s = Chr(64 + i - c) Print Tab(41 - i + c + 1); String(2 * (j - 1) + 1, s)13编写一个将十进制转换为二进制字符串输出的函数。调用函数计算用户输入一个十进制数,在文本框中输出二进制
12、值。输入数据为负数,应该将符号位输出如 -13 结果 -1101Dim a()Private Function convert(y) As StringDim i As Integeri = 1ReDim a(i)x = Abs(y)Do While x ReDim Preserve a(i) a(i) = x Mod 2 If a(i) = 1 Then x = (x - 1) / 2 x = x / 2Loop ReDim Preserve a(UBound(a)If y a(j) ThenPrivate Sub Command2_Click() For j = 1 To n - i If
13、 a(j) a(j + 1) Then t = a(j): a(j) = a(j + 1): a(j + 1) = t15编写程序,在窗体上输出3100之间的所有素数。要求每行显示4个数。Dim f As Boolean, c As IntegerFor i = 3 To 100 f = False For j = 2 To Int(Sqr(i) If i Mod j = 0 Then f = True: If f = False Then Print i; If c Mod 4 = 0 Then16把文本框1、文本框2指定的范围内的所有素数添加到列表框中,并选中列表框数据中最后一位是9的所有数据(设定selected属性),把它们的和值输出。Public a As IntegerPrivate Function fact(n) As Long If n = 1 Then fact = 1 ElseIf n = 2 Then fact = 1 Else: fact = fact(n - 2) + fact(n - 1)请输入nPrint fact(n)Private Function s(n) As Longs1 = 1: s2 = 1For i = 1 To n - 2 s = s1 + s2: t = s2: s2 = s: s1
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