1、(5) 根据卡片TLOADi输入的强迫加速度、速度、位移得到加速度历程a) 定义b) 强迫加速度c) 强迫速度d) 强迫位移e) 使用大质量法,同样要乘比例因子4 瞬态分析中的大刚度法对强迫位移,(2) 作用力P于弹簧或结构表面得到期望的,弹簧KL 在卡片CELAS1 或 CELAS2 中输入;比例因子 KL 在 DAREA 或DLOAD 中输入(3) 大质量应该为结构质量的102104倍,其中为激励的截断频率5 瞬态分析中的LAGRANGE乘子法(1) 通过DMIG或模拟约束的瞬态函数增加动态矩阵的行和列(2) 每行表示如下形式的约束(3) 每列表示称为Lagrange乘子的附加自由度,其值
2、为第j个约束自由度的约束力(4) 在直接瞬态分析中,EPOINTs, SPOINTs或GRID用于描述Lagrange乘子,模态响应分析中仅用EPOINTs(5) Nastran输入中需要设置卡片SDCOMP = 326 强迫位移例子(1)大质量法在TLOAD1的第5字段中,指定uB为强迫运动 (2)大刚度法在TLOAD1中指定PB为力,乘以强迫运动值kB,在DAREA中输入Large Mass MethodSOL 109TIME 10CENDTITLE=SDOF, GROUND MOTIONSUBTI= LARGE MASSLABEL = X VIA XSET 1=1DLOAD=105TST
3、EP=6DISPL=ALLACCEL=ALLOLOAD=1BEGIN BULKDAREA,105,1,1,1.0E8CONM2,3,2,1.0CONM2,999,1,1.0E8CROD,1,1,1,2GRID,1,0.,0.,0.,23456GRID,2,1.,0.,0.,23456MAT1,1,1.,0.PARAM,USETPRT,1PROD,1,1,34784TABLED1,8,+TAB1+TAB1,0.,0.,.025,0.,.05,0.,.075,0.,+TAB2+TAB2,5.075,12.5,10.075,25.0,ENDTTLOAD1,105,105,1,8TSTEP,6,199
4、,.025,1ENDDATALarge Stiffness MethodSUBTI= LARGE STIFFNESSLABEL = X VIA FORCINGSPC = 100DAREA,105,1,1,4.0E8GRID,99,-1.,0.,0.SPC,100,99,123456CELAS2,5,4.0E8,99,1,1,1TLOAD1,105,105,0,8(3)Lagrange乘子法运动方程(静力部分)为其中,x为一个小整数,用K2PP输入Lagrange乘子Lagrange Multiplier MethodSUBTI= LAGRANGE MULT - DISPLK2PP=STIFOL
5、OAD=ALLDAREA,105,1001,0,1.0DMIG,STIF,0,6,1,0DMIG,STIF,1001,101,-1.0E-10DMIG,STIF,1001,1,1, .1EPOINT,10017 频率响应分析中的大质量法 在频率响应中,假设输入和响应都为简谐函数动力学方程为施加加速度如瞬态分析中的大质量法一样,使大质量移动的力和加速度为因此,对施加位移可以得到加速度为因此作用力为其中,或由卡片TABLED1或TABLED4输入8 频率响应分析中的大刚度法 与大质量方法一样,期望的力为对施加位移,力为对施加加速度,力为用TABLED1 输入9 例子:具有强迫加速度的直接瞬态响应问
6、题:一250Hz的单位加速度正弦脉冲作用在地基的z方向,1000lb的大质量施加在基础上,结构阻尼系数为0.06, 在250Hz处将结构阻尼转化为等效粘性阻尼(2) 输入文件ID SEMINAR, PROB7TIME 30TITLE = TRANSIENT RESPONSE WITH BASE EXCITATIONSUBTITLE = USING DIRECT TRANSIENT METHOD, NO REDUCTIONECHO = UNSORTEDSPC = 200SET 111 = 23, 33DISPLACEMENT (SORT2) = 111VELOCITY (SORT2) = 111
7、ACCELERATION (SORT2) = 111SUBCASE 1DLOAD = 500TSTEP = 100$OUTPUT (XYPLOT)XGRID=YESYGRID=YESXTITLE= TIME (SEC)YTITLE= BASE ACCELERATIONXYPLOT ACCELERATION RESPONSE / 23 (T3)YTITLE= BASE DISPLACEMENTXYPLOT DISP RESPONSE / 23 (T3)YTITLE= TIP CENTER DISPLACEMENT RESPONSEXYPLOT DISP RESPONSE / 33 (T3)$ P
8、LATE MODEL DESCRIBED IN NORMAL MODES EXAMPLEINCLUDE plate.bdfPARAM, COUPMASS, 1PARAM, WTMASS, 0.00259$ SPECIFY STRUCTURAL DAMPINGPARAM, G, 0.06PARAM, W3, 1571.$ APPLY EDGE CONSTRAINTSSPC1, 200, 12456, 1, 12, 23, 34, 45$ PLACE BIG FOUNDATION MASS (BFM) AT BASECMASS2, 100, 1000., 23, 3$ RBE MASS TO RE
9、MAINING BASE POINTSRBE2, 101, 23, 3, 1, 12, 34, 45$ APPLY LOADING TO FOUNDATION MASSTLOAD2, 500, 600, , 0, 0.0, 0.004, 250., -90.DAREA, 600, 23, 3, 2.588$ SPECIFY INTEGRATION TIME STEPSTSTEP, 100, 200, 2.0E-4, 1(3)结果 具有强迫位移的直接频率响应图示平板在角点受0.1的强迫位移,在频率范围20,1000内使用步长20Hz,结构阻尼系数0.06ID SEMINAR, PROB8SOL
10、108TITLE= FREQUENCY RESPONSE DUE TO .1 DISPLACEMENT AT TIPSUBTITLE= DIRECT METHODECHO= UNSORTEDSPC= 1SET 111= 11, 33, 55DISPLACEMENT(PHASE, SORT2)= 111$SDISP(PHASE, SORT2)= ALLset 222 = 11OLOAD= 222DLOAD= 500FREQUENCY= 100XTGRID= YESYTGRID= YESXBGRID= YESYBGRID= YESYTLOG= YESYBLOG= NOXTITLE= FREQUEN
11、CY (HZ)YTTITLE= DISPLACEMENT RESPONSE AT LOADED CORNER, MAGNITUDEYBTITLE= DISPLACEMENT RESPONSE AT LOADED CORNER, PHASEXYPLOT DISP RESPONSE / 11 (T3RM, T3IP)YTTITLE= DISPLACEMENT RESPONSE AT TIP CENTER, MAGNITUDEYBTITLE= DISPLACEMENT RESPONSE AT TIP CENTER, PHASEXYPLOT DISP RESPONSE / 33 (T3RM, T3IP
12、)YTTITLE= DISPLACEMENT RESPONSE AT OPPOSITE CORNER, MAGNITUDEYBTITLE= DISPLACEMENT RESPONSE AT OPPOSITE CORNER, PHASEXYPLOT DISP RESPONSE / 55 (T3RM, T3IP)$ APPLY UNIT DISPLACEMENT AT TIP POINTCMASS2, 5000, 1.0E+5, 11, 3RLOAD2, 500, 600, , ,310TABLED4, 310, 0., 1., 0., 10000.,0., 0., -34784, ENDTDAREA, 600, 11, 3, 25.8799$ SPECIFY FREQUENCY STEPSFREQ1, 100, 20., 20., 49(3) 结果
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