1、没有 实根);3 int c,f; printf(“input c:n”); scanf(“%d”,& f=*c+32;%d的华氏温度是%d,c,f); 选择结构程序设计DBBCD C1、|a|+|b|=612、PQ3、-14、606960Error!5、0,16、a+b+c=15 int a,b,c,min; min=a; if (minb) min=b;c) min=c; printf(“%d,”,min); int a;%da); if(a%3=0 & a%5=0 & a%7=0)yesno float x,y;%fx); if (x=0 & x=2 &4) y=pow(x+2,3);
2、y=2*x+5;x=%f,y=%f,x,y);4 float rate,tax,salary;,salary); if(salary1350 & salary=2850) rate=;2850 &5850) tax=rate*(salary-850);salary=%f,rate=%f,tax=%f,salary,rate,tax); 循环控制一、填空题: 3. 46 二、选择题:CDBBB CCCBD三、程序阅读:1、输出:332、输出:243、2#4#7#11#16#4、3#2#0#0#1#5、BADC6、DABC7、BCAD8、ADBC9、CCA10、BDA11、ADC四、编程1#inc
3、lude int x;x sqrt(x)n for(x=5;x=1000;x+)%d %fn, x, sqrt(x);2#include#include= item=flag*i; pi=pi+item; flag=-flag; i=i+2; pi=pi*4;pi=%f,pi);3教材126页例4#include int i,a,b,c; a=1;b=1;%d %d ,a,b); for(i=3;i=10;i+) c=a+b;%d ,c); a=b; b=c; 第4章 数组一、选择题:DDADC CDBDB DDDAB 二、程序填空:ABBDCDABBBDCACDCA1#2#3#1#1#329
4、8三、编程:1、#include 0) if(mark = 85) a+; else if (mark = 60) p+; else f+; scanf (=85:%dn, a);60-84:, p);60:, f);2、#include average) count=count+1;平均值为%f 大于平均值的数有%d个,average,count);3main( ) int a10; int i,j,t,n;printf(“请输入一个正整数n(1n10):”);scanf(“%d”,&n); for (i=0; in; i+)n for (j=0; jai) t=aj;aj=ai;ai=t;
5、The sorted numbers: nfor (i=0;,ai); 4#include int a66,n,i,j,x,y,max; printf(“请输入一个正整数n(1n6):printf(“请输入一个n行n列的矩阵:jmax) max=aij;x=i;y=j;printf(“绝对值最大的元素为:%d,下标分别为:%d,%dn”,max,x,y);第5章 函数ABCBDC7) BDAC8) DCBA9)DBB10) CCBB二、程序阅读题(1)3,5(2)4(3)s=10(4)5,257,15三、程序设计# includeint isprime(int m) int k, n, res
6、; if(m = 1) return 0; res = 1; n = (int)sqrt(m); for(k = 2; k = n; k+) if(m%k = 0) res=0; break; return res; int m,n; int sum=0; int i; doInput m,n mn like:3,10n scanf(%d,%dm,& while(m0 | n for(i=m;=n; if(isprime(i) sum+=i;The all primes sum is:,sum);int max_value(int arr4) int i,j,max; max=arr00;2;
7、 for(j=0;4; if(maxaij) max=aij; return max;int isTheFineNumber(int n) int flag=0; int a,b,c;1. if(int)sqrt(n)=sqrt(n)k,结果为C)2.D二、选择填空题:1.B2.C三、编程题:struct int year; int month; int day;date; int days;input year,month,day:%d%d%d; switch case 1:days=;break; case 2:days=+31; case 3:days=+59; case 4:days=
8、+90; case 5:days=+120; case 6:days=+151; case 7:days=+181; case 8:days=+212; case 9:days=+243; case 10:days=+273; case 11:days=+304; case 12:days=+334; if(%4=0&%100!=0|%400=0) &=3)days+=1;%d/%d is the %dth day in %dn,days,; int hour; int min; int sec;time1,time2,time3; input the first time hour,min,sec:input the second time hour,min,sec: = if a+; else if(n b+; else c+;正数有%d个,负数有%d个,零有%d个n,a,b,c);
copyright@ 2008-2022 冰豆网网站版权所有
经营许可证编号:鄂ICP备2022015515号-1