双语建模与仿真实验九及答案Word下载.docx

1、FOURIER COMPONENTS OF TRANSIENT RESPONSE V（N00396,N00826）DC COMPONENT = -1.364900E+00 HARMONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZED NO （HZ） COMPONENT COMPONENT （DEG） PHASE （DEG） 1 4.000E+01 2.152E+02 1.000E+00 7.240E+01 0.000E+00 2 8.000E+01 8.215E-01 3.817E-03 -1.373E+02 -2.821E+02 3 1.200

2、E+02 1.087E+00 5.052E-03 -8.038E+01 -2.976E+02 4 1.600E+02 6.943E-01 3.226E-03 -8.213E+01 -3.717E+02 5 2.000E+02 5.693E-01 2.645E-03 -9.786E+01 -4.599E+02 6 2.400E+02 6.443E-01 2.993E-03 8.586E+01 -3.485E+02 7 2.800E+02 9.711E-01 4.512E-03 3.420E+01 -4.726E+02 8 3.200E+02 1.027E+00 4.772E-03 9.653E+

3、01 -4.827E+02 9 3.600E+02 1.231E+00 5.722E-03 1.556E+02 -4.960E+02 10 4.000E+02 1.534E+00 7.125E-03 3.867E+01 -6.853E+02 11 4.400E+02 6.245E-01 2.902E-03 1.273E+02 -6.690E+02 12 4.800E+02 3.197E-01 1.485E-03 -3.498E+01 -9.037E+02 13 5.200E+02 1.613E+00 7.495E-03 -1.635E+02 -1.105E+03 14 5.600E+02 1.

4、071E+00 4.974E-03 -1.276E+01 -1.026E+03 15 6.000E+02 2.202E-01 1.023E-03 7.034E+01 -1.016E+03 16 6.400E+02 1.064E+00 4.943E-03 -4.897E+01 -1.207E+03 17 6.800E+02 6.628E-01 3.079E-03 -1.572E+02 -1.388E+03 18 7.200E+02 1.169E+00 5.433E-03 -8.197E+01 -1.385E+03 19 7.600E+02 8.240E-01 3.828E-03 -8.104E+

5、01 -1.457E+03 20 8.000E+02 1.059E+00 4.919E-03 1.142E+02 -1.334E+03 21 8.400E+02 2.719E+00 1.263E-02 1.428E+02 -1.378E+03 22 8.800E+02 3.061E-01 1.422E-03 1.006E+02 -1.492E+03 23 9.200E+02 5.888E+01 2.735E-01 -5.381E+01 -1.719E+03 TOTAL HARMONIC DISTORTION = 2.745429E+01 PERCENT JOB CONCLUDED TOTAL

6、JOB TIME .88 V01（peak）= 2.152E+02,that is 215.2V, V（rms）=152.17V, the phase of V01 is 7.240E+01,that is 72.40 so 2*pi *f=2*3.141592*40=251.33rad/s, so V01=152.17sin（251.33t+72.4*pi/180 ）While its precalculated ominal value:Vo1（rms） = 153.33 V, Vo1,peak = 216.8V.3, Using the results of Problem 2, obt

7、ain the ripple component V ripple waveform in the output voltage.V01=152.17sin（251.33*time+72.4*pi/180） ,the ripple component vripple isV0-V01=V0-152.17sin（251.33*time+72.4*pi/180） ,the waveform as follow.4, Obtain i01 by means of Fourier analysis of the io waveform. Compare i01 with itsFOURIER COMP

8、ONENTS OF TRANSIENT RESPONSE I（R_R1） DC COMPONENT = -4.719698E-01 1 4.000E+01 1.354E+01 1.000E+00 4.403E+01 0.000E+00 2 8.000E+01 3.947E-02 2.916E-03 -1.560E+02 -2.441E+02 3 1.200E+02 7.786E-02 5.752E-03 -1.118E+02 -2.439E+02 4 1.600E+02 2.435E-02 1.799E-03 -1.555E+02 -3.317E+02 5 2.000E+02 2.570E-0

9、2 1.899E-03 -1.064E+02 -3.265E+02 6 2.400E+02 1.252E-02 9.249E-04 1.561E+02 -1.081E+02 7 2.800E+02 2.285E-03 1.688E-04 1.474E+02 -1.609E+02 8 3.200E+02 4.269E-03 3.154E-04 1.430E+02 -2.092E+02 9 3.600E+02 4.284E-03 3.165E-04 1.701E+02 -2.262E+02 10 4.000E+02 9.197E-03 6.794E-04 -1.136E+02 -5.539E+02

10、 11 4.400E+02 1.157E-02 8.546E-04 1.496E+02 -3.348E+02 12 4.800E+02 6.981E-03 5.157E-04 1.585E+02 -3.699E+02 13 5.200E+02 1.201E-02 8.870E-04 1.259E+02 -4.466E+02 14 5.600E+02 8.194E-03 6.053E-04 -1.427E+02 -7.591E+02 15 6.000E+02 5.535E-03 4.089E-04 -1.350E+02 -7.956E+02 16 6.400E+02 4.930E-03 3.64

11、2E-04 -1.476E+02 -8.522E+02 17 6.800E+02 4.122E-03 3.045E-04 1.635E+02 -5.851E+02 18 7.200E+02 7.549E-03 5.577E-04 1.583E+02 -6.343E+02 19 7.600E+02 4.627E-03 3.418E-04 -1.707E+02 -1.007E+03 20 8.000E+02 1.062E-03 7.843E-05 1.569E+02 -7.238E+02 21 8.400E+02 3.030E-02 2.238E-03 7.941E+01 -8.453E+02 2

12、2 8.800E+02 2.964E-03 2.190E-04 -1.272E+02 -1.096E+03 23 9.200E+02 1.030E+00 7.612E-02 -1.418E+02 -1.155E+03 TOTAL HARMONIC DISTORTION = 7.650194E+00 PERCENT TOTAL JOB TIME .86I （peak）= 1.354E+01 ,that is 13.54A, I（rms）=9.574A,the phase is 4.403E+01Io1（rms） = 10 A at a 0.866 pf （lagging）,I （peak）=14

13、.14A.5, Using the results of Problem 4, obtain the ripple component Iripple in the output current=9.574sin （2*pi*f*time+44.03*pi/180）=9.574sin（2*pi*40+44.03*pi/180）the ripple component iripple is （I- I）,its waveform is as follow6, Obtain Id（avg） and id2 （the component at the 2nd harmonic frequency）

14、by means of theFourier analysis of the id waveform. Compare them with their precalculated nominalvalues.FOURIER COMPONENTS OF TRANSIENT RESPONSE I（V_V1） DC COMPONENT = -4.893025E+00 1 4.000E+01 4.692E-01 1.000E+00 6.937E+01 0.000E+00 2 8.000E+01 5.423E+00 1.156E+01 -1.554E+02 -2.942E+02 3 1.200E+02

15、6.118E-02 1.304E-01 3.030E+01 -1.778E+02 4 1.600E+02 8.395E-02 1.789E-01 5.346E+01 -2.240E+02 5 2.000E+02 4.896E-02 1.043E-01 -9.629E+00 -3.565E+02 6 2.400E+02 3.820E-02 8.141E-02 -5.784E+00 -4.220E+02 7 2.800E+02 4.377E-02 9.328E-02 -1.139E+02 -5.995E+02 8 3.200E+02 5.191E-02 1.106E-01 7.187E+01 -4

16、.831E+02 9 3.600E+02 3.148E-02 6.709E-02 -1.697E+02 -7.940E+02 10 4.000E+02 5.119E-02 1.091E-01 -7.545E+01 -7.691E+02 11 4.400E+02 3.731E-02 7.952E-02 -1.656E+02 -9.287E+02 12 4.800E+02 1.236E-02 2.634E-02 6.434E+01 -7.681E+02 13 5.200E+02 4.233E-02 9.020E-02 -1.740E+02 -1.076E+03 14 5.600E+02 2.151

17、E-02 4.585E-02 -9.854E+01 -1.070E+03 15 6.000E+02 3.325E-02 7.085E-02 1.731E+02 -8.674E+02 16 6.400E+02 4.631E-02 9.869E-02 3.875E+01 -1.071E+03 17 6.800E+02 4.390E-02 9.355E-02 1.430E+02 -1.036E+03 18 7.200E+02 5.532E-02 1.179E-01 -8.981E+01 -1.338E+03 19 7.600E+02 3.294E-02 7.020E-02 3.511E+01 -1.

18、283E+03 20 8.000E+02 1.153E-01 2.458E-01 7.638E+00 -1.380E+03 21 8.400E+02 2.876E-02 6.129E-02 -4.330E+00 -1.461E+03 22 8.800E+02 1.266E+00 2.698E+00 1.513E+02 -1.375E+03 23 9.200E+02 1.669E-01 3.556E-01 -5.120E+01 -1.647E+03 TOTAL HARMONIC DISTORTION = 1.188283E+03 PERCENTId=4.893025E+00,that is 4.

19、893A,Id （peak）= 5.423E+00,Id （rms）=3.835A,its phase is -1.554E+02,that is -155.4their precalculated nominal values:Id=*cos=4.656A=3.801A7, Using the results of Problem 6, obtain the high frequency ripple component id,ripple inthe input dc current. Calculate its rms valueanswer:Io1（peak）= 4.692E-01,t

20、hat is 0.4692A,its rms value is 0.3318A, TOTAL HARMONIC DISTORTION = 1.188283E+03 PERCENT,%THD=1188.283%, the high frequency ripple component of id,ripple=0.3318*11.88283=3.942A,so its rms value is 3.942A EXAMPLE 16Three-Phase PWM InverterObtain the following waveforms using :（a） vAN and iA.（b） vAn

21、and iA.（c） vAN and id.Answer（a） vAN waveform:IA waveform:（b） vAn waveform:（c） vAN waveform:2, Obtain vAn1 by means of Fourier analysis of the vAn waveform. Compare vAn1 withits precalculated nominal value.FOURIER COMPONENTS OF TRANSIENT RESPONSE V（VA,VNEUTRAL）DC COMPONENT = -2.239930E-021 4.762E+01

22、1.491E+02 1.000E+00 1.372E+02 0.000E+00 2 9.524E+01 4.832E-01 3.240E-03 -8.232E+01 -3.568E+02 3 1.429E+02 4.600E-02 3.085E-04 -1.106E+02 -5.222E+02 4 1.905E+02 4.246E-01 2.848E-03 1.929E+01 -5.296E+02 5 2.381E+02 6.052E-01 4.059E-03 3.124E+00 -6.830E+02 6 2.857E+02 4.407E-02 2.955E-04 -1.323E+02 -9.

23、557E+02 7 3.333E+02 7.786E-01 5.222E-03 1.476E+02 -8.130E+02 8 3.810E+02 6.795E-01 4.557E-03 1.786E+02 -9.192E+02 9 4.286E+02 4.730E-02 3.172E-04 -1.491E+02 -1.384E+03 10 4.762E+02 9.098E-01 6.101E-03 1.662E+02 -1.206E+03 11 5.238E+02 1.551E-01 1.040E-03 -7.099E+01 -1.580E+03 12 5.714E+02 4.816E-02

24、3.230E-04 -1.729E+02 -1.820E+03 13 6.190E+02 1.455E+00 9.758E-03 1.256E+02 -1.658E+03 14 6.667E+02 8.385E-01 5.623E-03 -9.956E+01 -2.021E+03 15 7.143E+02 4.384E-02 2.940E-04 1.718E+02 -1.887E+03 16 7.619E+02 2.030E-01 1.361E-03 -9.822E+01 -2.294E+03 17 8.095E+02 1.799E+00 1.207E-02 -9.840E+01 -2.431

25、E+03 18 8.571E+02 4.842E-02 3.247E-04 1.518E+02 -2.318E+03 19 9.048E+02 4.585E+01 3.075E-01 1.751E+02 -2.432E+03 20 9.524E+02 7.544E-01 5.059E-03 7.145E+01 -2.673E+03 21 1.000E+03 4.487E-02 3.009E-04 1.273E+02 -2.754E+03 22 1.048E+03 6.855E-01 4.597E-03 1.205E+02 -2.898E+03 23 1.095E+03 4.598E+01 3.

26、084E-01 4.126E+00 -3.152E+03 TOTAL HARMONIC DISTORTION = 4.359678E+01 PERCENTJOB CONCLUDEDTOTAL JOB TIME 2.80vAn1（peak）= 1.491E+02, vAn1（rms）=105.43V,its phase is 1.372E+02,that is 137.2,its precalculated nominal value:vLL1（rms）= *230=182.54V,vAn1（rms）= =105.39 V3, Using the results of Problem 2, ob

27、tain the ripple component vripple waveform in theoutput voltage vAn1=105.43sin（2*pi*47.619time+137.2*pi/180）the ripple component vripple waveform in the output voltage is（vAn-vAn1） ,its waveform:4, Obtain iA1 by means of Fourier analysis of iA waveform. Compare iA1 with itsDC COMPONENT = -1.633990E-

28、02HARMONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZED1 4.762E+01 1.417E+01 1.000E+00 1.076E+02 0.000E+00 2 9.524E+01 1.690E-02 1.193E-03 -1.546E+02 -3.698E+02 3 1.429E+02 8.724E-03 6.157E-04 1.718E+02 -1.510E+02 4 1.905E+02 7.686E-03 5.424E-04 1.213E+02 -3.090E+02 5 2.381E+02 1.073E-02 7.575E-04 -1.011E+02 -6.390E+02 6 2.857E+02 3.529E-03 2.491E-04 1.441E+02 -5.014E+02 7 3.333E+02 4.672E-03 3.297E-04 3.53