1、实验九: 多态性(一)1、 定义计数器Counter类,对其重载运算符 + 。实验代码:#include class counterprivate:int n;public:counter( ) n=0;counter(int i) n=i;counter operator+(counter c)counter temp;temp.n=n+c.n;return temp; void disp( )coutn=nendl;void main() counter c1(15),c2(10),c3; c3=c1+c2; c1.disp(); c2.disp(); c3.disp();实验结果:2、
2、定义一个基类BaseClass,从它派生出类DerivedClass,BaseClass有成员函数fn1()、fn2(),DerivedClass也有成员函数fn1()、fn2(),在主程序中定义一个DerivedClass的对象,分别用DerivedClass的对象以及BaseClass和DerivedClass的指针来调用fn1()、fn2(),观察运行结果。实验代码:#include class BaseClasspublic: void fn1(); void fn2(); ; void BaseClass:fn1()cout 调用基类的函数fn1() endl; void BaseC
3、lass:fn2()cout 调用基类的函数fn2() endl; class DerivedClass : public BaseClass public:void fn1(); void fn2(); ; void DerivedClass:fn1() cout 调用派生类的函数fn1() endl; void DerivedClass:fn2() cout 调用派生类的函数fn2() fn1(); pBaseClass-fn2(); pDerivedClass-fn1(); pDerivedClass-fn2(); 实验结果:3、 实现重载函数Double(x),返回值为输入参数的两倍;
4、参数分别为整型、长整型、浮点型、双精度型,返回值类型与参数一样。实验代码:#includeusing namespace std;int Double(int a)return 2.0*a;long int Double(long int a)return 2*a;float Double(float a)return 2.0*a;double Double(double a)return 2.00000*a;void main()int m;coutm;cout它的两倍是Double(m)endl;long int p;coutp;cout它的两倍是Double(p)endl;float r
5、;coutr;cout它的两倍是Double(r)endl;double n;coutn;cout它的两倍是Double(n)endl;实验结果:4、 定义一个复数类,重载“+”;“-”;“*”,“/”运算符实现复数的四则运算。实验代码:#include class complex private:double real; double imag; public:complex() real=imag=0; complex(double rpart,double ipart) real=rpart;imag=ipart;complex operator+(const complex &com)
6、 complex temp;temp.real=real+com.real;temp.imag=imag+com.imag;return temp;complex operator-(const complex &com) complex temp;temp.real=real-com.real;temp.imag=imag-com.imag;return temp;complex operator*(const complex &com) complex temp;temp.real=real*com.real-imag*com.imag;temp.imag=real*com.imag+im
7、ag*com.real;return temp;complex operator/(const complex &com) complex temp;temp.real=(real*com.real+imag*com.imag)/(com.real*com.real+com.imag*com.imag);temp.imag=(imag*com.real-real*com.imag)/(com.real*com.real+com.imag*com.imag);return temp;void display() if(imag=0)cout(real+imagi);elsecout(realim
8、agi);int main(void)double a,b,c,d;coutabcd;complex n1(a,b),n2(c,d);cout两个复数值为:;coutA=; n1.display();cout B=;n2.display(); coutendl;coutendlendl两个复数的加法:endl;complex result1;result1=n1+n2; n1.display();cout+;n2.display();cout=;result1.display(); coutendlendl两个复数的减法:endl;complex result2;result2=n1-n2;
9、n1.display();cout-;n2.display();cout=;result2.display(); coutendlendl两个复数的乘法:endl;complex result3;result3=n1*n2; n1.display();cout;n2.display();cout=;result3.display(); coutendlendl两个复数的除法:endl; if(c=0&d=0) cout不能进行运算,除数不能为0endl;elsecomplex result4; result4=n1/n2; n1.display();cout;n2.display();cout=;result4.display(); coutendl;return 0;实验结果:
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