ImageVerifierCode 换一换
格式:PDF , 页数:267 ,大小:18.94MB ,
资源ID:16124079      下载积分:3 金币
快捷下载
登录下载
邮箱/手机:
温馨提示:
快捷下载时,用户名和密码都是您填写的邮箱或者手机号,方便查询和重复下载(系统自动生成)。 如填写123,账号就是123,密码也是123。
特别说明:
请自助下载,系统不会自动发送文件的哦; 如果您已付费,想二次下载,请登录后访问:我的下载记录
支付方式: 支付宝    微信支付   
验证码:   换一换

加入VIP,免费下载
 

温馨提示:由于个人手机设置不同,如果发现不能下载,请复制以下地址【https://www.bdocx.com/down/16124079.html】到电脑端继续下载(重复下载不扣费)。

已注册用户请登录:
账号:
密码:
验证码:   换一换
  忘记密码?
三方登录: 微信登录   QQ登录  

下载须知

1: 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。
2: 试题试卷类文档,如果标题没有明确说明有答案则都视为没有答案,请知晓。
3: 文件的所有权益归上传用户所有。
4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
5. 本站仅提供交流平台,并不能对任何下载内容负责。
6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

版权提示 | 免责声明

本文(运筹学清华大学出版社(胡运权着)课后答案(.资料下载.pdf)为本站会员(b****2)主动上传,冰豆网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知冰豆网(发送邮件至service@bdocx.com或直接QQ联系客服),我们立即给予删除!

运筹学清华大学出版社(胡运权着)课后答案(.资料下载.pdf

1、运筹学教程第二版运筹学教程第二版 习题解答习题解答运筹学教程运筹学教程School of ManagementSchool of Managementpage page 2 26 January 20116 January 20111.1 用图解法求解下列线性规划问题。#并指出问 题具有惟一最优解、无穷多最优解、无界解还是无可 行解。#0,422664.32min)1(21212121xxxxxxstxxZ0,124322.23max)2(21212121xxxxxxstxxZ85105120106.max)3(212121xxxxstxxZ0,23222.65max)4(21212121xx

2、xxxxstxxZ运筹学教程运筹学教程School of ManagementSchool of Managementpage page 3 36 January 20116 January 2011是一个最优解无穷多最优解3,31,10,422664.32min)1(2121212121ZxxxxxxxxstxxZ该问题无解0,124322.23max)2(21212121xxxxxxstxxZ运筹学教程运筹学教程School of ManagementSchool of Managementpage page 4 46 January 20116 January 201116,6,1085

3、105120106.max)3(21212121ZxxxxxxstxxZ唯一最优解该问题有无界解0,23222.65max)4(21212121xxxxxxstxxZ运筹学教程运筹学教程School of ManagementSchool of Managementpage page 5 56 January 20116 January 20111.2 将下述线性规划问题化成标准形式。#.,0,2321422245243min)1(43214321432143214321无约束xxxxxxxxxxxxxxxxstxxxxZ无约束321321321321,0,0624322min)2(xxxxx

4、xxxxstxxxZ运筹学教程运筹学教程School of ManagementSchool of Managementpage page 6 66 January 20116 January 2011.,0,2321422245243min)1(43214321432143214321无约束xxxxxxxxxxxxxxxxstxxxxZ0,232142222455243max64241321642413215424132142413214241321xxxxxxxxxxxxxxxxxxxxxxxstxxxxxZ运筹学教程运筹学教程School of ManagementSchool of M

5、anagementpage page 7 76 January 20116 January 2011无约束321321321321,0,0624322min)2(xxxxxxxxxstxxxZ0,6243322max43231214323121323121323121xxxxxxxxxxxxxxstxxxxZ运筹学教程运筹学教程School of ManagementSchool of Managementpage page 8 86 January 20116 January 20111.3 对下述线性规划问题找出所有基解指出哪 些是基可行解并确定最优解。#6,1,0031024893631

6、223max)1(6153214321321jxxxxxxxxxxxstxxxZj)4,1(,0322274322325min)2(432143214321jxxxxxxxxxstxxxxZj运筹学教程运筹学教程School of ManagementSchool of Managementpage page 9 96 January 20116 January 20116,1,0031024893631223max)1(6153214321321jxxxxxxxxxxxstxxxZj基可行解x1x2x3x4x5x6Z03003.503001.5080300035000.7500022.252

7、.25运筹学教程运筹学教程School of ManagementSchool of Managementpage page 10106 January 20116 January 2011)4,1(,0322274322325min)2(432143214321jxxxxxxxxxstxxxxZj基可行解x1x2x3x4Z00.5205001152/5011/5043/5运筹学教程运筹学教程School of ManagementSchool of Managementpage page 11116 January 20116 January 20111.4 分别用图解法和单纯形法求解下述线

8、性规划 问题并对照指出单纯形表中的各基可行解对应图解 法中可行域的哪一顶点。#0,825943.510max)1(21212121xxxxxxstxxZ运筹学教程运筹学教程School of ManagementSchool of Managementpage page 12126 January 20116 January 20110,24261553.2max)2(21212121xxxxxxstxxZ运筹学教程运筹学教程School of ManagementSchool of Managementpage page 13136 January 20116 January 2011l.5

9、 上题(1)中若目标函数变为max Z=cx1+dx2 讨论c,d的值如何变化使该问题可行域的每个顶 点依次使目标函数达到最优。#解得到最终单纯形表如下Cjcd00CB基bx1x2x3x4dx23/2015/14-3/4cx1110-2/1410/35j00-5/14d+2/14c 3/14d-10/14c运筹学教程运筹学教程School of ManagementSchool of Managementpage page 14146 January 20116 January 2011当c/d在3/10到5/2之间时最优解为图中的A点当 c/d大于5/2且c大于等于0时最优解为图中的B点当c

10、/d 小于3/10且d大于0时最优解为图中的C点当c/d大于 5/2且c小于等于0时或当c/d小于3/10且d小于0时最优解 为图中的原点。#运筹学教程运筹学教程School of ManagementSchool of Managementpage page 15156 January 20116 January 2011式中1c1 3,4c2 6,-1a11 3,2a12 5,8b1 12,2a21 5,4a22 6,10b2 14,试确定 目标函数最优值的下界和上界。#0,.max21222212112121112211xxbxaxabxaxastxcxcZl.6 考虑下述线性规划问题运

11、筹学教程运筹学教程School of ManagementSchool of Managementpage page 16166 January 20116 January 2011最优值上界为210,14421221.63max21212121xxxxxxstxxZ解上界对应的模型如下c,b取大a取小运筹学教程运筹学教程School of ManagementSchool of Managementpage page 17176 January 20116 January 2011最优值下界为6.40,1064853.4max21212121xxxxxxstxxZ解下界对应的模型如下 c,b

12、取小a取大运筹学教程运筹学教程School of ManagementSchool of Managementpage page 18186 January 20116 January 2011l.7 分别用单纯形法中的大M法和两阶段法求解 下列线性规划问题并指出属哪类解。#该题是无界解。#3,1,00222623max)1(3231321321jxxxxxxxxstxxxZj运筹学教程运筹学教程School of ManagementSchool of Managementpage page 19196 January 20116 January 20116,0,54,590,623824.

13、32min)2(3212121321321ZxxxxxxxxxxstxxxZ最优解之一该题是无穷多最优解。#运筹学教程运筹学教程School of ManagementSchool of Managementpage page 20206 January 20116 January 2011517,0,1,59,524,1,042634334max)3(43214213212121ZxxxxjxxxxxxxxxstxxZj该题是唯一最优解运筹学教程运筹学教程School of ManagementSchool of Managementpage page 21216 January 20116

14、 January 2011该题无可行解。#3,1,052151565935121510max)4(321321321321jxxxxxxxxxxstxxxZj运筹学教程运筹学教程School of ManagementSchool of Managementpage page 22226 January 20116 January 20111.8 已知某线性规划问题的初始单纯形表和用单 纯形法迭代后得到下面表格试求括弧中未知数al值。#项 目X1X2X3X4X5X46(b)(c)(d)10X51-13(e)01Cj Zja-1200X1(f)(g)2-11/20X54(h)(i)11/21Cj

15、 Zj0-7jk(l)b=2,c=4,d=-2,g=1,h=0,f=3,i=5,e=2,l=0,a=3,j=5,k=-1.5运筹学教程运筹学教程School of ManagementSchool of Managementpage page 23236 January 20116 January 20111.9 若X(1)、X(2)均为某线性规划问题的最优解 证明在这两点连线上的所有点也是该问题的最优解。#也是最优解。#所以也是可行解且满足两点连线上的点对于任何满足和设XXCXCXaCaXCXaCaXCXCXaaXXXaXbAXXCZXXTTTTTTTT,)1()1(,100max)2()2

16、()2()1()2()1()2()1()2()1(运筹学教程运筹学教程School of ManagementSchool of Managementpage page 24246 January 20116 January 20111.10 线性规划问题max ZCX,AXbX0设 X0为问题的最优解。#若目标函数中用C*代替C后问题 的最优解变为X*求证(C*-C)(X*-X0)00)()()(;#0max;#0max0*00*0*00XXCXXCXXCCXCXCXCZXCXCXCXZX的最优解故是的最优解故是运筹学教程运筹学教程School of ManagementSchool of Managementpage page 25256 January 20116 January 20111.11 考虑线性规划问题0,)(75232)(24.42min432143214214321xxxxiixxxxixxxstxxxxZ模型中为参数要求(1)组成两个新的约束(i)(i)+(ii)(ii)(ii)一2(i)根据(i)(ii)以x1,x2 为基变量列出 初始单纯形表运筹学教程运筹学教程School of Manage

copyright@ 2008-2022 冰豆网网站版权所有

经营许可证编号:鄂ICP备2022015515号-1