110KV35KV变电站继电保护整定计算书Word下载.docx

1、Sj、Uj、Ij、Xj一以基准量表示的容量（MVA）、电压（KV）、电流（KA）、电抗（）Se-额定容量（MVA）； Ud%-阻抗电压百分数； X”d%-超瞬变电抗百分数；XO-每千米电抗（/km）； Up-平均额定电压（KV）； X%-电抗百分数；L-线路长度（km）；1、1#主变：X1=Ud%/100*Sj/Se=7.85/100*100/20=0.3925 2#主变：X2=Ud%/100*Sj/Se=8.06/100*100/20=0.4032、6KV线路：（集配站6302线路） X3线= XO* L* Sj/ Up2=0.4*3.2*100/6.32=3.225 X3缆= XO* L*

2、 Sj/ Up2=0.08*0.19*100/6.32=0.038 X3=X3线+X3缆=3.225+0.038=3.263（旭飞公司6303线路） X4线= XO* L* Sj/ Up2=0.353*2.2*100/6.32=1.9567 X4缆= XO* L* Sj/ Up2=0.08*0.1*100/6.32=0.0202 X4=X4线+X4缆=1.9567+0.0202=1.9769（恒兴公司6304线路） X5线= XO* L* Sj/ Up2=0.347*4*100/6.32=3.4971 X5缆= XO* L* Sj/ Up2=0.08*0.15*100/6.32=0.0302

3、X5=X5线+X5缆=3.4971+0.0302=3.5273（金能公司6305线路） X6线= XO* L* Sj/ Up2=0.347*4.6*100/6.32=4.0217X6缆= XO* L* Sj/ Up2=0.08*0.15*100/6.32=0.0302X6= X6线+X6缆=4.0217+0.0302=4.0519（一采区路线路）因6306线路为相分裂架设，故： X7线= XO* L* Sj/ Up2/2=0.333*2.6*100/6.32/2=1.091 X7缆= XO* L* Sj/ Up2/2=0.08*0.4*100/6.32/2=0.0403 X7= X7线+X7缆

4、=1.091+0.0403=1.1313（环兴磁场6307线路） X8线= XO* L* Sj/ Up2=0.347*4*100/6.32=3.4971 X8缆= XO* L* Sj/ Up2=0.08*0.17*100/6.32=0.0171 X8= X8线+X8缆=3.4971+0.0171=3.5142（乳化车间6308线路） X9线= XO* L* Sj/ Up2=0.347*6.4*100/6.32=5.5954X9缆= XO* L* Sj/ Up2=0.08*0.07*100/6.32=0.0141 X9= X9线+X9缆=5.5954+0.0141=5.6095（众元洗煤三分厂6

5、309线路） X10（架空）= XO* L* Sj/ Up2/2=0.333*1.7*100/6.32=1.4263 X10（电缆）= XO* L* Sj/ Up2/2=0.08*0.24*100/6.32=0.0484 X10= X10（架空）+ X10（电缆）=1.4263 +0.0484=1.4747（1#动力变6311线路） X11（电缆）= XO* L* Sj/ Up2/2=0.08*0.22*100/6.32=0.0443（三泵房6402线路） 因6402线路为电缆线路，故：XO为0.08/kmX12= XO* L* Sj/ Up2=0.08*0.4*100/6.32=0.0806

6、（深井专线6403线路） X13线= XO* L* Sj/ Up2=0.353*2.5*100/6.32=2.2235 X13缆= XO* L* Sj/ Up2=0.08*0.5*100/6.32=0.1008 X13= X13线+X13缆=2.2235+0.1008=2.3243（众元洗煤厂6404线路） 因6404线路为电缆线路，故：X14= XO* L* Sj/ Up2=0.08*0.5*100/6.32=0.1008（一采区路线路）因6406线路为相分裂架设，故： X15线= XO* L* Sj/ Up2/2=0.325*3.6*100/6.32/2=1.4739X15缆= XO* L

7、* Sj/ Up2/2=0.08*0.32*100/6.32/2=0.0302 X15= X15线+X15缆=1.4739+0.03225=1.5062（石康铸造6407线路） X16线= XO* L* Sj/ Up2=0.365*0.3*100/6.32=0.2759 X16缆= XO* L* Sj/ Up2=0.08*0.15*100/6.32=0.2653 X16= X16线+X16缆=0.2759+0.2653=0.5412（化工厂6408线路） X17线= XO* L* Sj/ Up2=0.347*8.4*100/6.32=7.3439 X17缆= XO* L* Sj/ Up2=0.

8、08*0.11*100/6.32=0.02217 X17= X17线+X17缆=7.3439+0.02217=7.366（四泵房6409线路） X18线= XO* L* Sj/ Up2=0.347*4*100/6.32=3.4971 X18缆= XO* L* Sj/ Up2=0.08*0.15*100/6.32=0.0302 X18= X18线+X18缆=3.4971+0.0302=3.5273（然尔特6410线路） X19线= XO* L* Sj/ Up2=0.325*2.1*100/6.32=1.719 X19缆= XO* L* Sj/ Up2=0.08*0.3/2*100/6.32=0.

9、030 X19= X线+X缆=1.719+0.030=1.749（三矿物业6412线路） X20线= XO* L* Sj/ Up2=0.353*1.8*100/6.32=1.601 X20缆= XO* L* Sj/ Up2=0.08*0.1*100/6.32=0.0202 X20= X19线+X19缆=1.601+0.0202=1.6212三、计算K2点的短路参数（K2点前的总阻抗及短路电流）1、最大运行方式下：XK2max=0.24756+0.3925=0.64006最小运行方式下：XK2min=0.37084+0.3925=0.763342、k2点的超瞬变短路电流I”：（用来作继电保护的整

10、定计算和校验断路器的断流量）根据：I”k2=Ij/ XK2max 设基准容量为：Sj =100 MVA且基准电流为：Ij= Sj/ Up=100/*6.3=9.165（KA）I”k2=Ij/ XK2max=9.165/0.64006=14.319（KA）同理：I”k2=Ij/ XK2min 且基准电流为：I”k2=Ij/ XK2 min =9.165/0.76334=12.006（KA）四、计算末端K6302- K6412点的短路参数（K6302- K6412各点的阻抗及三相短路电流）1、 K6302 max= XK2max+X3=0.64006+3.263=3.90306 K6302 min

11、= XK2min+X3=0.7634+3.263=4.0264I” 6302 max =Ij/ K6302 max =9.165/3.90306=2.349（KA）I” 6302 min =Ij/ K6302 min=9.165/4.0264=2.277（KA）2、 K6303 max= XK2max+X4=0.64006+1.9769=2.617 K6303 min= XK2min+X4=0.76334+1.9769=2.740I” 6303 max =Ij/ K6303max =9.165/2.617=3.502（KA）I” 6303min =Ij/ K6303 min=9.165/2.7

12、4=3.345（KA）3、 K6304 max= XK2max+X5=0.64006+3.5273=4.167 K6304 min= XK2min+X5=0.7634+3.5273=4.291I” 6304 max =Ij/ K6304max =9.165/4.167=2.199（KA）I” 6304min =Ij/ K6304 min=9.165/4.291=2.136（KA）4、 K6305 max= XK2max+X6=0.64006+4.0519=4.5755 K6305 min= XK2min+X6=0.76334+4.0519=4.6996I” 6305 max =Ij/ K630

13、5max =9.165/4.5755=2.003（KA）I” 6305min =Ij/ K6305min=9.165/4.6996=1.950（KA）5、 K6306 max= XK2max+X7=0.64006+1.1313=1.771 K6306 min= XK2min+X7=0.76334+1.1313=1.895I” 6306max =Ij/ K6306max =9.165/1.771=5.175（KA）I” 6306min =Ij/ K6306min=9.165/1.895=4.836（KA）6、 K6307 max= XK2max+X8=0.64006+3.5142=4.154 K6307 min= XK2min+X8=0.76334+3.5142=4.278I” 6307max =Ij/ K6307max =9.165/4.154=2.206（KA）I” 6307min =Ij/ K6307min=9.165/4.278=2.142（KA）7、 K6308 max= XK2max+X9=0.63006+5.6095=6.2396 K6308 min= XK2m