1、使用beam189梁单元 MPTEMP,MPTEMP,1,0MPDATA,EX,1,210e9MPDATA,PRXY,1,0.3MPDATA,DENS,1,7850SECTYPE,1, BEAM, RECT, secA, 0定义梁截面secA SECOFFSET, CENTSECDATA,0.005,0.01,0,0,0,0,0,0,0,0K, , !建模与分网 K, ,2, K, ,2,1,LSTR, 1, 2LATT,1, ,1, , 3, ,1LESIZE,1, , ,20, , , , ,1LMESH, 1FINISH/SOL静力大变形求解 ANTYPE,0 NLGEOM,1PSTRE
2、S,ON计及预应力效果 DK,1, , , ,0,ALL, , , , , ,ACEL,0,9.8,0,只考虑重力作用 TIME,1AUTOTS,1 NSUBST,20, , ,1KBC,0SOLVE/SOLUTIONANTYPE,2进行模态求解 MSAVE,0MODOPT,LANB,10MXPAND,10, , ,0取前十阶模态 PSTRES,1打开预应力效应 MODOPT,LANB,10,0,0, ,OFF 修正坐标以得到正确的应力 PSOLVE,TRIANG三角化矩阵 PSOLVE,EIGLANB提取特征值和特征向量 /SOLUEXPASS,1扩展模态解 PSOLVE,EIGEXP/PO
3、ST1SET,LIST观察结果 问题二:循环对称结构模态分析 这是ANSYS HELP里的例子,但那个命令流似乎有些问题,下面是整理过的命令流。2、define cyclic 3、定义约束 4、求模态解 5、展开并察看结果 r1=5建模 r2=10 d1=2 nsect=24 alpha_deg=360/nsect alpha_rad=2*acos(-1)/nsect /prep7 csys,1 k,1,0,0,0 k,2,0,0,d1 k,3,r1,0,0 k,4,r1,0,d1 l,3,4 arotat,1,1,2,alpha_deg/2 k,7,r2,0,0 k,8,r2,0,d1 l,
4、7,8 arotat,5,1,2,alpha_deg/2 arotat,2,1,2,alpha_deg/2 arotat,6,1,2,alpha_deg/2 a,5,6,10,9 mshkey,1 et,1,181 r,1,0.20 r,2,0.1 mp,ex,1,10e6 mp,prxy,1,0.3 mp,dens,1,1e-4 esize,0.5 asel,1,4 aatt,1 asel,5 aatt,2 allsel CYCLIC, , , ,CYCLIC定义基本扇区 AMESH,all分网 求模态解 ANTYPE,2 PSTRES,0 DK,5, , , ,0,UZ, , , , ,
5、,SET,LIST SET, , ,1, , , ,4,/CYCEXPAND, ,ONPLNS,U,SUM观察扩展模态 FINISH 问题三:三角平台受谐波载荷作用,求结构响应 谐波载荷为作用在平台上面一点的集中力,幅值为10N,频率范围5Hz70Hz 2. 求模态解 3、用模态叠加法作谐分析 4. 观察结果 ET,1,BEAM189 ET,2,SHELL93 R,1,0.01, , , , , ,MP,EX,1,210e9MP,PRXY,1,0.3MP,DENS,1,7850SECDATA,0.005,0.008,0,0,0,0,0,0,0,0K, ,-0.5,K, ,0.5,K, ,1,
6、K, ,1,1,K, ,-0.5,1, K, ,0.5,1,K, ,0.5,A,4,5,6 5 3, 4 2, 6LSEL,S,LINE,4,6 LATT,1,1,1, , 7, ,1LSEL, , , ,ALLLESIZE,ALL, , ,10, , , , ,1LMESH,4,6TYPE,2MSHAPE,0,2DMSHKEY,1 AMESH,1为了使用模态叠加法谐分析 MODOPT,LANB,20先取结构前20阶模态MXPAND,20, , ,0MODOPT,LANB,20,0,0, ,OFF KSEL,S,KP,1,3DK,ALL, , , ,0,ALL, , , , , ,最好事先看一
7、下模态结果 以了解模态频率范围 模态叠加法谐响应分析 ANTYPE,3 HROPT,MSUPHROUT,ON HROPT,MSUP,20, , HROUT,ON,OFF,0F,177,FY,-10,施加10N的力在节点177的负Y方向 HARFRQ,5,70,载荷的强制频率范围 NSUBST,200,KBC,1ALPHAD,5,/POST26察看位移响应 FILE,rfrq NUMVAR,20NSOL,2,139,U,Y,PLVAR,2 问题四:三角平台受一地震谱激励,求应力分布和支反力 2、求模态解 3、求谱解 4、扩展模态 5、模态合并 6、观察结果 LSEL,S,LINE,4,6LSEL, , , ,ALL 谱分析 ANTYPE,8 SPOPT,SPRS,10,1 SVTYP,3 SED,0,1,0,给出激励方向 FR
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