1、(2)如图分别进行编号1、2、3、4、5、6,并建立坐标系(3)编程进行求解,得出结果,其中假设力P=2000N调用Triangle2D3Node_Stiffness函数,求出单元刚度矩阵k1 = 1.0e+06 * 7.2857 -3.0000 -2.1429 0.8571 -5.1429 2.1429 -3.0000 7.2857 2.1429 -5.1429 0.8571 -2.1429 -2.1429 2.1429 2.1429 0 0 -2.1429 0.8571 -5.1429 0 5.1429 -0.8571 0 -5.1429 0.8571 0 -0.8571 5.1429 0
2、 2.1429 -2.1429 -2.1429 0 0 2.1429k2 = 5.1429 0 -5.1429 0.8571 0 -0.8571 0 2.1429 2.1429 -2.1429 -2.1429 0 -5.1429 2.1429 7.2857 -3.0000 -2.1429 0.8571 0.8571 -2.1429 -3.0000 7.2857 2.1429 -5.1429 0 -2.1429 -2.1429 2.1429 2.1429 0 -0.8571 0 0.8571 -5.1429 0 5.1429k3 = 2.1429 0 -2.1429 -2.1429 0 2.14
3、29 0 5.1429 -0.8571 -5.1429 0.8571 0 -2.1429 -0.8571 7.2857 3.0000 -5.1429 -2.1429 -2.1429 -5.1429 3.0000 7.2857 -0.8571 -2.1429 0 0.8571 -5.1429 -0.8571 5.1429 0k4 =调用Triangle2D3Node_Assembly函数,求出总体刚度矩阵求出的节点位移U = 0 -0.0004 0.0008 0.0005 0.0010 0.0007 0.0023 -0.0007 0.0026调用Triangle2D3Node_Stress函数,
4、求出应力,S1、S2、S3、中求出的分别为Sx,Sy,SxyS1 = 1.0e+03 * -4.4086 -0.7348 3.5914S2 = 4.4086 -0.6405 0.4086S3 = 1.8907 -1.0601 2.1093S4 = -1.89071.8907二、(1)如图划分四边形单元,工分成四个分别为调用 Quad2D4Node_Stiffness函数,求出单元刚度矩阵调用Quad2D4Node_Assembly函数,求出求出总体刚度矩阵求出节点位移 0.0012 0.0017 -0.0012 0.0016 0.0049 -0.0017 0.0052调用Quad2D4Node
5、_Stress函数,求出单元应力中的的S1、S2、S3分别为Sx,Sy,Sxy应力分量 0.0000 -0.2478 2.0000 1.0e+07 * 0.6856 4.1135 -1.7137程序附录一、1、三角形单元总程序:E=1e7;NU=1/6;t=1;ID=1;%调用Triangle2D3Node_Stiffness函数,求出单元刚度矩阵k1=Triangle2D3Node_Stiffness(E,NU,t,0,1,0,0,1,1,ID)k2=Triangle2D3Node_Stiffness(E,NU,t,0,0,1,0,1,1,ID)k3=Triangle2D3Node_Stif
6、fness(E,NU,t,1,1,1,0,2,0,ID)k4=Triangle2D3Node_Stiffness(E,NU,t,2,0,2,1,1,1,ID)%调用Triangle2D3Node_Assembly函数,求出总体刚度矩阵KK = zeros(12,12);KK=Triangle2D3Node_Assembly(KK,k1,1,2,3);KK=Triangle2D3Node_Assembly(KK,k2,2,4,3);KK=Triangle2D3Node_Assembly(KK,k3,3,4,5);KK=Triangle2D3Node_Assembly(KK,k4,5,6,3)%
7、边界条件的处理及刚度方程求解k=KK(5:12,5:12) p=0;0;2000u=kp%支反力的计算U=0;u %为节点位移P=KK*U%调用Triangle2D3Node_Strain函数,求出应变SN1、SN2、SN3中求出的分别为SNx,SNy,SNxyu1=U(1);U(2);U(3);U(4);U(5);U(6);u2=U(3);U(7);U(8);u3=U(5);U(6);U(9);U(10);u4=U(9);U(10);U(11);U(12); SN1=Triangle2D3Node_Strain(0,1,0,0,1,1,u1) SN2=Triangle2D3Node_Stra
8、in(0,0,1,0,1,1,u2) SN3=Triangle2D3Node_Strain(1,1,1,0,2,0,u3) SN4=Triangle2D3Node_Strain(2,0,2,1,1,1,u4) %调用Triangle2D3Node_Stress函数,求出应力,S1、S2、S3、中求出的分别为Sx,Sy,Sxy u1=U(1); S1=Triangle2D3Node_Stress(E,NU,0,1,0,0,1,1,u1,ID) S2=Triangle2D3Node_Stress(E,NU,0,0,1,0,1,1,u2,ID) S3=Triangle2D3Node_Stress(E
9、,NU,1,1,1,0,2,0,u3,ID) S4=Triangle2D3Node_Stress(E,NU,2,0,2,1,1,1,u4,ID)2、求刚度矩阵程序function k=Triangle2D3Node_Stiffness(E,NU,t,xi,yi,xj,yj,xm,ym,ID)%该函数计算单元的刚度矩阵%输入弹性模量E,泊松比NU,厚度t%输入三个节点i、j、m的坐标xi,yi,xj,yj,xm,ym%输入平面问题性质指示参数ID(1为平面应力,2为平面应变)%输出单元刚度矩阵k(6X6)%-A = (xi*(yj-ym) + xj*(ym-yi) + xm*(yi-yj)/2;
10、betai = yj-ym;betaj = ym-yi;betam = yi-yj;gammai = xm-xj;gammaj = xi-xm;gammam = xj-xi;B = betai 0 betaj 0 betam 0 ; 0 gammai 0 gammaj 0 gammam ; gammai betai gammaj betaj gammam betam/(2*A);if ID = 1 D = (E/(1-NU*NU)*1 NU 0 ; NU 1 0 ; 0 0 (1-NU)/2;elseif ID = 2 D = (E/(1+NU)/(1-2*NU)*1-NU NU 0 ; NU
11、 1-NU 0 ; 0 0 (1-2*NU)/2;endk= t*A*B*D*B;3、求整体刚度矩阵function z = Triangle2D3Node_Assembly(KK,k,i,j,m)%该函数进行单元刚度矩阵的组装%输入单元刚度矩阵k%输入单元的节点编号I、j、m%输出整体刚度矩阵KK DOF(1)=2*i-1;DOF(2)=2*i;DOF(3)=2*j-1;DOF(4)=2*j;DOF(5)=2*m-1;DOF(6)=2*m;for n1=1:6 for n2=1: KK(DOF(n1),DOF(n2)= KK(DOF(n1),DOF(n2)+k(n1,n2); endz=KK;4、求应变程序function strain=Triangle2D3Node_Strain(xi,yi,xj,yj,xm,ym,u)%该函数计算单元的应变%输入单元的位移列阵u(6X1)%输出单元的应力strain(3X1),由于它为常应变单元,则单元的应变分量为SNx,SNy,SNz%-
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