1、(1) 999 (2)t/10 (3)x9、 _1_;(1) sum=0 (2)tii (3)110、_1_ fun(char ch)(1) char (2)ch=9 (3)011、s=0; i=_1_;(1) 0 (2)i+ (3)2.*i12、while (!feof(_1_)(1) fp (2)= (3)fp13、for(i=0; i _1_ ; i+)(1) N (2)substr (3)014、for(p=1; pb)?(bc?b :(ac:_1_):(ac)?_2_:(b_3_);(1) a (2)a (3)b16 if (cha)_1_(ch=len) strcpy(_1_);(
2、1) t,s (2)si (3)020、_1_ fun(struct student *a)(1)struct student * (2)a-scorei (3)a21、max = min = _1_;(1) ai (2)aj (3)aj22、void fun(int _1_ , int n)(1) tN (2)i=0;isno (2)-name (3)&t27、k=_1_;(注意和第49题不一样) t=_2_;(1) 1 (2)2*i (3) (-1)28、s=_1_;(1) 0 (2)n (3)(t*t)29、 ch=tolower(_1_);(1) *s (2)1 (3)kn30、_1_
3、 t;(1) struct student (2)n-1(3)ai.name,aj.name31、 if (_1_= 0) (1) ai%2 (2)aj (3) j32、 t=*n % _1_;(1) 10 (2)0 (3)x33、for(i=0; i+)(注意有相类似的) if(len (3)(2*i+1)39、for (i=0;_1_;ai = an-1-_2_;(注意有类似题)(1) n/2 (2)i (3)an-i-140、b = _1_;(1) a (2)b.name (3)scorei41、 for (_1_; ji; j+)(1) j=2 (2)i (3)j42、i=_1_;(1
4、) 1 (2)s (3)i*1043、_1_ fun(struct student a)(1) struct student (2)a.name(3)a.scorei44、p=(n%2=0)?n/2:n/2+_1_;(1) 1 (2)i (3)ap+i45、 if (ai%2=_1_)(1) 1 (2)j+ (3)j46、n=_1_;(1) 0 (2)x (3)t+47、 *(t+n)= _1_ ; n+; (1) *s (2)s+ (3)n48、#define OK(i, t, n) (_1_%t=0) & (i/tn)(1) i (2)t+ (3)count49、k= _1_ ;if(st
5、rlen(psk) tj + 1 )8.(1)void fun(long s,long *t) (2)while(s0)9.(1)double r; (2) while(fabs(m-n)0.001)10.(1)bk=*p; (2) bk= ;k+;11.(1)void fun (char *s, char *t) (2)t2*d = 0;12.(1)n=strlen(aa); (2)ch=aai;13.(1)fun(int x,int y, int z)(2)return j;14.(1) void fun(int aM, int m)(2)ajk=(k+1)*(j+1);15.(1)c=t
6、olower(c)(注:c小写); (2)c=c+5;16.(1) void fun(int *a)(2)aj=aj-1;17.(1) if (k%13 = 0) | (k%17 =0) (注:双等号) (2)(注:横线去掉)18.(1)for(i=1;=3;i+)(2)if(k=0&kamid)23.(1) sum=0;(2)if(i+1)%5=0)24.(1)d=1;s=0;(2)d=d/10;25.(1) k=i;(2)c=k;26.(1)double fun(double a,double x0)(2)if(fabs(x1-x0)0.00001)27.(1)k+; (2)if(m=k)
7、28.(1) for(i=0;stri;(2)if(substrk+1=0)29.(1) float fun(int k)(2)return s;30.(1) q=p+i; (2)while(qp)31.(1) fun (int n) (2)if(n=1)32.(1) if (n=0)(2)result *= n- ;33.(1) int k=0;(2)while( *p | *q )34.(1) t+=sk; (2)*aver=ave;35.(1) while(*w)(2)if(*r=*p)36.(1) a2=k/10;(注意是十)(2)return i;37.(1) double fun (int n)(2)c=a;a+=b;b=c;38.(1)double fun(int n)(2)s=s+(double)a/b;39.(1) n= *p-(2)n=n*8+*p-40.(1) sj+=si;(2
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