1、C+面向对象程序设计第六章课后习题答案第2版谭浩强第六章课后习题答案(第二版谭浩强)1:/xt61/cppinclude iostream /如用VC+应改为include iosttram。husing namespace std; /如用VC+应取消此行#include ”cylinder.hinclude point.cpp#include circle.cppinclude cylinder。cppint main()Cylinder cy1(3。5,6。4,5.2,10); cout”noriginal cylinder:nx=”cy1。getX(), y=cy1.getY(), r
2、=cy1.getRadius(), h=cy1.getHeight()”narea=cy1.area(), volume=”cy1。volume()endl; cy1.setHeight(15); cy1。setRadius(7。5); cy1.setPoint(5,5); coutnnew cylinder:n”cy1; Point &pRef=cy1; coutnpRef as a point:pRef; Circle &cRef=cy1; coutncRef as a Circle:”cRef; return 0;3:解法一include iostreamusing namespace
3、std;class Pointpublic: Point(float a,float b):x(a),y(b) Point()coutexecuting Point destructorendl; private: float x; float y;class Circle:public Pointpublic: Circle(float a,float b,float r):Point(a,b),radius(r) Circle()coutusing namespace std;class Pointpublic: Point(float a,float b):x(a),y(b) Point
4、()cout”executing Point destructor”endl; private: float x; float y;class Circle:public Pointpublic:Circle(int a,int b,int r):Point(a,b),radius(r) Circle()coutexecuting Circle destructorendl; private: float radius;;int main()Point *p=new Circle(2.5,1.8,4.5); Circle *pt=new Circle(2.5,1。8,4。5); delete
5、pt; return 0;3:解法三#include iostreamusing namespace std;class Pointpublic: Point(float a,float b):x(a),y(b) virtual Point()cout”executing Point destructor”endl; private: float x; float y;;class Circle:public Pointpublic:Circle(float a,float b,float r):Point(a,b),radius(r) virtual Circle()cout”executi
6、ng Circle destructorendl; private:float radius;void main()Point *p=new Circle(2。5,1.8,4.5); delete p;4:include using namespace std;/定义抽象基类Shapeclass Shapepublic: virtual double area() const =0; /纯虚函数;/定义Circle类class Circle:public Shapepublic:Circle(double r):radius(r) /结构函数 virtual double area() con
7、st return 3.14159*radius*radius;; /定义虚函数 protected: double radius; /半径;/定义Rectangle类class Rectangle:public Shapepublic: Rectangle(double w,double h):width(w),height(h) /结构函数 virtual double area() const return widthheight; /定义虚函数protected: double width,height; /宽与高;class Triangle:public Shapepublic:
8、Triangle(double w,double h):width(w),height(h) /结构函数 virtual double area() const return 0。5*width*height; /定义虚函数 protected: double width,height; /宽与高;/输出面积的函数void printArea(const Shape &s)couts.area()endl; /输出s的面积int main() Circle circle(12。6); /建立Circle类对象circle cout”area of circle =; printArea(cir
9、cle); /输出circle的面积 Rectangle rectangle(4。5,8。4); /建立Rectangle类对象rectangle coutarea of rectangle =”; printArea(rectangle); /输出rectangle的面积 Triangle triangle(4.5,8.4); /建立Triangle类对象 coutarea of triangle =”; printArea(triangle); /输出triangle的面积 return 0;5:#include iostreamusing namespace std;/定义抽象基类Sha
10、peclass Shapepublic: virtual double area() const =0; /纯虚函数;/定义Circle(圆形)类class Circle:public Shapepublic:Circle(double r):radius(r) /结构函数 virtual double area() const return 3.14159*radius*radius;; /定义虚函数 protected: double radius; /半径;/定义Square(正方形)类class Square:public Shapepublic: Square(double s):s
11、ide(s) /结构函数 virtual double area() const return sideside; /定义虚函数 protected: double side;;/定义Rectangle(矩形)类class Rectangle:public Shapepublic: Rectangle(double w,double h):width(w),height(h) /结构函数 virtual double area() const return widthheight; /定义虚函数 protected: double width,height; /宽与高;/定义Trapezoid
12、(梯形)类class Trapezoid:public Shapepublic: Trapezoid(double t,double b,double h):top(t),bottom(t),height(h) /结构函数 virtual double area() const return 0.5*(top+bottom)height; /定义虚函数 protected: double top,bottom,height; /上底、下底与高;/定义Triangle(三角形)类class Triangle:public Shapepublic: Triangle(double w,double
13、 h):width(w),height(h) /结构函数 virtual double area()const return 0。5width*height; /定义虚函数 protected: double width,height; /宽与高;int main() Circle circle(12.6); /建立Circle类对象circle Square square(3。5); /建立Square类对象square Rectangle rectangle(4.5,8.4); /建立Rectangle类对象rectangle Trapezoid trapezoid(2.0,4。5,3.2); /建立Trapezoid类对象trapezoid Triangle triangle(4.5,8。4); /建立Triangle类对象 Shape pt5=circle,square,rectangle,&trapezoid,triangle; /定义基类指针数组pt,使它每一个元素指向一个派生类对象 double areas=0.0; /areas为总面积 for(int i=0;i5;i+) areas=areas+pti-area(); cout”totol of all areas=”areasendl; /输出总面积 return 0;
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