C语言操作题常考编程题库讲解学习.docx

1、C语言操作题常考编程题库讲解学习C语言操作题常考编程题库C语言编程题覆盖到的算法：1、个人所得税计算；2、求一组数的正、负数（或奇、偶数）的个数和平均值；3、二维数组主、次对角线之和；4、求素数（用函数实现）；5、级数有限项求和问题；6、两个一维数组相加（用函数实现）；7、求最大、最小值；8、判断闰年（用函数实现）；9、求水仙花数；10、百钱百鸡；11、求最大公约数、最小公倍数。12、求回文数；13、排序；14、二维数组的转置；15、递归函数求阶乘；16、求斐波那契数列；17、求和：a+aa+aaa+aaaa+.；18、求符合条件的整数（如：是某个二位数的平方，个位、十位、百位数各不相同等）；

2、(包括素数，回文，完数，等等)19、字符串加密；20、统计字符串中字母和数字的个数；/*1.个人所得税计算，以实验指导P24T5为标准*/#includevoid main() int i,n; double a,b,c; n=i/400; printf(please input income:n); scanf(%d,&i); a=(i-800)*0.05,b=20+(i-1200)*0.08,c=84+(i-2000)*0.2; switch(n) case 0: case 1:printf(不需缴税n);break; case 2:printf(需交纳%lf元n,a);break; ca

3、se 3: case 4:printf(需交纳%lf元n,b);break; default:printf(需交纳%lf元n,c);break; /*2. 求一组数的奇数个数，偶数个数和平均值#include#define N 10void main() int aN; int i,m=0,n=0,sum=0; double average; printf(please input 10 numbers:n); for(i=0;iN;i+) scanf(%d,&ai); if(ai%2=0) m+; else n+; sum+=ai; average=(double)sum/N; printf

4、(we have %d odds and %d evensn,n,m); printf(average=%lfn,average);*/*2.求一组数的正数个数和负数个数与平均值*/#include#define N 10void main() int aN; int i,m=0,n=0,sum=0; double average; printf(please input 10 numbers:n); for(i=0;i0) m+; else n+; sum+=ai; average=(double)sum/N; printf(we have %d positive numbers and %

5、d nagetive numbersn,m,n); printf(the average =%lf,average); /*3.求二维数组的主次对角线之和*/#include#define M 5 #define N 5void main() int aMN; int i,j,sum1=0,sum2=0; printf(please input the matrix:n); for(i=0;iM;i+) for(j=0;jN;j+) scanf(%d,&aij); for(i=0,j=0;iM;i+,j+) sum1+=aij; for(i=0,j=N-1;iM;i+,j-) sum2+=ai

6、j; printf(主对角线和为%dn,sum1); printf(次对角线和为%dn,sum2);/*4.调用函数判断素数*/#include#includeint isPrime(int n) int i; for(i=1;isqrt(n);i+) if(n%i=0) return 0; return 1;void main() int n,i; printf(please input a numbern); scanf(%d,&n); i=isPrime(n); if(i) printf(%d is a primen,n); else printf(%d is not a primen,

7、n);/5.级数有限项求和(以格里高利公式求为例)/#include#includevoid main() int n=1; double p=0,t,pi; t=1/(pow(-1),(n+1)*2*(n-1); while(fabs(t)=1e-6) pi+=t; n+; pi=4*p; printf(%lf,pi);/6.两个一维数组相加/*#include#define N 5void main() int aN,bN,cN; int i; printf(please input the first array aN:n); for(i=0;iN;i+) scanf(%d,&ai);

8、printf(please input the second array bN:n); for(i=0;iN;i+) scanf(%d,&bi); for(i=0;iN;i+) ci=ai+bi; printf(the sum is:n); for(i=0;iN;i+) printf(%dt,ci);*/6.1调用函数实现/#include#define N 5int f(int a,int b) int sum; sum=a+b; return sum;void main() int aN,bN,cN; int i; printf(please input the first array a

9、N:n); for(i=0;iN;i+) scanf(%d,&ai); printf(please input the second array bN:n); for(i=0;iN;i+) scanf(%d,&bi); for(i=0;iN;i+) ci=f(ai,bi); printf(the sum is:n); for(i=0;iN;i+) printf(%dt,ci);/*7.求一组数的最大最小值*/*#includevoid main() int i,max,min; int a10; printf(please input ten numbersn); for(i=0;i10;i+

10、) scanf(%d,&ai); max=a0; min=a0; for(i=1;imax) max=ai; if(aimin) min=ai; printf(max is %d,min is %dn,max,min); */*随机数*/#include#includevoid main() int i,max,min; int a10; for (i=0;i10;i+) ai=rand()%90+10; printf(%dt,ai); max=a0; min=a0; for(i=1;imax) max=ai; if(aimin) min=ai; printf(max=%dtmin=%dn,m

11、ax,min);/*8.判断闰年*/#includeint f(int n) if(n%4=0&n%100!=0|n%400=0) return 1; else return 0;void main() int n; printf(please input year:n); scanf(%d,&n); if(f(n) printf(%d是闰年n,n); else printf(%d不是闰年n,n);/*可能会有要输出某一范围内所有闰年，思想一样，用循环调用函数即可*/*9.判断水仙花数（运用循环）#includevoid main() int n,a,b,c,m; printf(please

12、input a number:n); scanf(%d,&n); a=n/100; b=n/10%10; c=n%10; m=a*a*a+b*b*b+c*c*c; if(m=n) printf(%d is the number we wantn,n); else printf(%d is not the numbern,n);*/*9.输出所有水仙花数（调用函数(书P108为循环做法)）*/#includeint f(int n) int a,b,c,m; a=n/100; b=n/10%10; c=n%10; m=a*a*a+b*b*b+c*c*c; if(m=n) return 1; el

13、se return 0;void main() int i,t; for(i=100;i1000;i+) t=f(i); if(t=1) printf(%dt,i); /10.百钱买百鸡（题目见书P115）/#includevoid main() int i,j,k; for(i=0;i=20;i+) for(j=0;j=33;j+) for(k=3;k=99;k+=3) if(i+j+k=100)&(5*i+3*j+k/3=100) printf(公鸡%d只，母鸡%d只，小鸡%d只n,i,j,k); /*11.求最大公约数和最小公倍数，函数实现*/#includeint f(int m,in

14、t n) int i=1,t; if(mn) t=m; m=n; n=t; while(i=m%n)!=0) m=n; n=i; return n;int g(int m,int n) int i,j; i=f(m,n); j=m*n/i; return j;void main() int m,n,a,b; printf(please input two numbers:n); scanf(%d %d,&m,&n); a=f(m,n); b=g(m,n); printf(最大公约数为%dn,a); printf(最小公倍数为%dn,b);/12.1输出10-2000之间的回文数（循环）/*#i

15、ncludevoid main() int i,j,k=0,a; printf(10-2000之间的回文数有：n); for(i=10;i0) j=j*10+a%10; a/=10; if(i=j) printf(%dt,i); k+; if(k%5=0) printf(n); printf(n);*/12.2输出10-2000之间的回文数（函数调用）/*#includeint f(int n) int i=0; while(n0) i=i*10+n%10; n/=10; return i;void main() int n,k; printf(10-2000之间的回文数有：n); for(n

16、=10;n=2000;n+) if(n=f(n) printf(%dt,n); k+; if(k%5=0) printf(n); printf(n);*/12.3判断回文数（循环）/*#includevoid main() int i,a,j=0; printf(please input a number:n); scanf(%d,&i); a=i; while(a0) j=j*10+a%10; a/=10; if(j=i) printf(%d是回文数n,i); else printf(%d不是回文数n,i);*/12.4判断回文数（函数调用）/#includeint f(int n) int

17、 i=0; while(n0) i=i*10+n%10; n/=10; return i;void main() int n; printf(please inpit a number:n); scanf(%d,&n); if(n=f(n) printf(%d是回文数n,n); else printf(%d不是回文数n,n);/13.排序/选择法/*#include#define N 10void f(int a,int n) int i,j,k,t; for(i=0;i=n;i+) k=i; for(j=i+1;jn;j+) if(ajak) k=j; if(k!=i) t=ak; ak=a

18、i; ai=t; void main() int aN=8,2,34,5,12,78,4,78,76,9; int i=0; int size=sizeof(a)/sizeof(int); for(i=0;iN;i+) printf(%4d,ai); printf(n); f(a,size); for(i=0;iN;i+) printf(%4d,ai); printf (n);/冒泡法/#include#define N 5void f(int a,int n) int i,j; int t; for(i=0;in-1;i+) for(j=0;jaj+1) t=aj; aj=aj+1; aj+

19、1=t; */插入法/#include#define N 5void f(int a,int n) int i,j; int t; for(i=0;i0&aj-1t) aj=aj-1; -j; aj=t; void main() int aN=8,2,34,5,12; int i=0; int size=sizeof(a)/sizeof(int); for(i=0;iN;i+) printf(%4d,ai); printf(n); f(a,size); for(i=0;iN;i+) printf(%4d,ai); printf (n);/二维数组的转置/#include#define N 3#

20、define M 3void main() int aMN,bMN; int i,j; printf(please input aMNn); for(i=0;iM;i+) for(j=0;jN;j+) scanf(%d,&aij); for(i=0;iM;i+) for(j=0;jN;j+) bij=aji; printf(bMN=n); for(i=0;iM;i+) for(j=0;jN;j+) printf(%4d,bij); printf(n); printf(n);/15.调用递归函数求阶乘/#includeint f(int n) if(n=1|n=0) return 1; else

21、 return f(n-1)*n;void main() int n,m; printf(please input a number:n); scanf(%d,&n); m=f(n); printf(%d!=%dn,n,m);/*16.运用递归函数求斐波拉契数列（前30项）*/#includeint f(int n) if (n=1|n=2) return 1; else return f(n-1)+f(n-2);void main() int i,k=0; for (i=1;i=30;i+) printf(%dt,f(i); k+; if(k%5=0) printf(n); printf(n

22、);/17.求a+aa+aaa+aaaa./*#include#include#define N 5void main() int n,i,j,k,a,sum1=0; printf(please input a number:n); scanf(%d,&n); for(i=1;i=N;i+) k=fabs(10,i-1); j=n+n*(i-1)*k; sum1+=j; printf(sum=%dn,sum1);*/#include#define N 5int k(int a,int sum) sum=sum*10+a; return sum;void main() int a,i=0,j,s

23、um=0; printf(please input a number:n); scanf(%d,&a); sum=k(a,k(a,sum); printf(sum=%dn,sum);/18.求符合条件的整数（如是某个二位数的平方，个位、十位、百位数各不相同等）/#includevoid main() int a,b,c,n,m; for(m=10;m100;m+) n=m*m; a=n%10; b=n/10%10; c=n/100; if(a!=b&b!=c&c!=a) printf(%dt,m); printf(n);/19.字符串加密/#include#include#define N 80void main() char strN; char *p; printf(please