1、高考数学真题汇编集合高考数学真题汇编-集合高考数学真题汇编-集合学校:_姓名:_班级:_考号:_一选择题(共29小题)1(2017北京)已知全集U=R,集合A=x|x2或x2,则UA=()A(2,2) B(,2)(2,+)C2,2 D(,22,+)2(2017新课标)已知集合A=(x,y)|x2+y2=1,B=(x,y)|y=x,则AB中元素的个数为()A3 B2 C1 D03(2017天津)设集合A=1,2,6,B=2,4,C=xR|1x5,则(AB)C=()A2 B1,2,4 C1,2,4,5 DxR|1x54(2017新课标)已知集合A=1,2,3,4,B=2,4,6,8,则AB中元素的
2、个数为()A1 B2 C3 D45(2017山东)设函数y=的定义域为A,函数y=ln(1x)的定义域为B,则AB=()A(1,2) B(1,2 C(2,1) D2,1)6(2017新课标)已知集合A=x|x2,B=x|32x0,则()AAB=x|x BAB= CAB=x|x DAB=R7(2017天津)设集合A=1,2,6,B=2,4,C=1,2,3,4,则(AB)C=()A2 B1,2,4 C1,2,4,6 D1,2,3,4,68(2017山东)设集合M=x|x1|1,N=x|x2,则MN=()A(1,1) B(1,2) C(0,2) D(1,2)9(2017新课标)已知集合A=x|x1,
3、B=x|3x1,则()AAB=x|x0 BAB=RCAB=x|x1 DAB=10(2017新课标)设集合A=1,2,3,B=2,3,4,则AB=()A1,2,3,4 B1,2,3 C2,3,4 D1,3,411(2017北京)若集合A=x|2x1,B=x|x1或x3,则AB=()Ax|2x1 Bx|2x3 Cx|1x1 Dx|1x312(2017浙江)已知集合P=x|1x1,Q=x|0x2,那么PQ=()A(1,2) B(0,1) C(1,0) D(1,2)13(2017新课标)设集合A=1,2,4,B=x|x24x+m=0若AB=1,则B=()A1,3 B1,0 C1,3 D1,514(20
4、16新课标)设集合A=0,2,4,6,8,10,B=4,8,则AB=()A4,8 B0,2,6 C0,2,6,10 D0,2,4,6,8,1015(2016山东)设集合U=1,2,3,4,5,6,A=1,3,5,B=3,4,5,则U(AB)=()A2,6 B3,6 C1,3,4,5 D1,2,4,616(2016新课标)设集合A=1,3,5,7,B=x|2x5,则AB=()A1,3 B3,5C5,7 D1,717(2016浙江)已知全集U=1,2,3,4,5,6,集合P=1,3,5,Q=1,2,4,则(UP)Q=()A1 B3,5C1,2,4,6 D1,2,3,4,518(2016四川)设集合
5、A=x|1x5,Z为整数集,则集合AZ中元素的个数是()A6 B5 C4 D319(2016北京)已知集合A=x|x|2,B=1,0,1,2,3,则AB=()A0,1 B0,1,2 C1,0,1 D1,0,1,220(2016北京)已知集合A=x|2x4,B=x|x3或x5,则AB=()Ax|2x5 Bx|x4或x5 Cx|2x3 Dx|x2或x521(2016浙江)已知集合P=xR|1x3,Q=xR|x24,则P(RQ)=()A2,3 B(2,3 C1,2) D(,21,+)22(2016山东)设集合A=y|y=2x,xR,B=x|x210,则AB=()A(1,1) B(0,1) C(1,+
6、) D(0,+)23(2016新课标)已知集合A=1,2,3,B=x|x29,则AB=()A2,1,0,1,2,3 B2,1,0,1,2C1,2,3 D1,224(2016新课标)设集合A=x|x24x+30,B=x|2x30,则AB=()A(3,) B(3,) C(1,) D(,3)25(2016新课标)已知集合A=1,2,3,B=x|(x+1)(x2)0,xZ,则AB等于()A1 B1,2 C0,1,2,3 D1,0,1,2,326(2016新课标)设集合S=x|(x2)(x3)0,T=x|x0,则ST=()A2,3 B(,23,+)C3,+) D(0,23,+)27(2016天津)已知集
7、合A=1,2,3,4,B=y|y=3x2,xA,则AB=()A1 B4 C1,3 D1,428(2016四川)设集合A=x|2x2,Z为整数集,则AZ中元素的个数是()A3 B4 C5 D6高考数学真题汇编-集合参考答案与试题解析一选择题(共29小题)1 【解答】解:集合A=x|x2或x2=(,2)(2,+),全集U=R,UA=2,2,故选:C2、【解答】解:由,解得:或,AB的元素的个数是2个,故选:B3【解答】解:A=1,2,6,B=2,4,AB=1,2,4,6,又C=xR|1x5,(AB)C=1,2,4故选:B4【解答】解:集合A=1,2,3,4,B=2,4,6,8,AB=2,4,AB中
8、元素的个数为2故选:B5(解答】解:由4x20,解得:2x2,则函数y=的定义域2,2,由对数函数的定义域可知:1x0,解得:x1,则函数y=ln(1x)的定义域(,1),则AB=2,1),故选:D6【解答】解:集合A=x|x2,B=x|32x0=x|x,AB=x|x,故A正确,B错误;AB=x|x2,故C,D错误;故选:A7【解答】解:集合A=1,2,6,B=2,4,C=1,2,3,4,(AB)C=1,2,4,61,2,3,4=1,2,4故选:B8 【解答】解:集合M=x|x1|1=(0,2),N=x|x2=(,2),MN=(0,2),故选:C9 【解答】解:集合A=x|x1,B=x|3x1
9、=x|x0,AB=x|x0,故A正确,D错误;AB=x|x1,故B和C都错误故选:A10【解答】解:A=1,2,3,B=2,3,4,AB=1,2,3,4故选:A11【解答】解:集合A=x|2x1,B=x|x1或x3,AB=x|2x1故选:A12 【解答】解:集合P=x|1x1,Q=x|0x2,那么PQ=x|1x2=(1,2)故选:A13【解答】解:集合A=1,2,4,B=x|x24x+m=0若AB=1,则1A且1B,可得14+m=0,解得m=3,即有B=x|x24x+3=0=1,3故选:C14【解答】解:集合A=0,2,4,6,8,10,B=4,8,则AB=0,2,6,10故选:C15【解答】
10、解:集合U=1,2,3,4,5,6,A=1,3,5,B=3,4,5,则AB=1,3,4,5U(AB)=2,6故选:A16【解答】解:集合A=1,3,5,7,B=x|2x5,则AB=3,5故选:B17【解答】解:UP=2,4,6,(UP)Q=2,4,61,2,4=1,2,4,6故选:C18【解答】解:集合A=x|1x5,Z为整数集,则集合AZ=1,2,3,4,5集合AZ中元素的个数是5故选:B19【解答】解:集合A=x|x|2=x|2x2,B=1,0,1,2,3,AB=1,0,1故选:C20【解答】解:集合A=x|2x4,B=x|x3或x5,AB=x|2x3故选:C21 【解答】解:Q=xR|x
11、24=xR|x2或x2,即有RQ=xR|2x2,则P(RQ)=(2,3故选:B22 【解答】解:A=y|y=2x,xR=(0,+),B=x|x210=(1,1),AB=(0,+)(1,1)=(1,+)故选:C23【解答】解:集合A=1,2,3,B=x|x29=x|3x3,AB=1,2故选:D24 【解答】解:集合A=x|x24x+30=(1,3),B=x|2x30=(,+),AB=(,3),故选:D25【解答】解:集合A=1,2,3,B=x|(x+1)(x2)0,xZ=0,1,AB=0,1,2,3故选:C26 【解答】解:由S中不等式解得:x2或x3,即S=(,23,+),T=(0,+),ST
12、=(0,23,+),故选:D27【解答】解:把x=1,2,3,4分别代入y=3x2得:y=1,4,7,10,即B=1,4,7,10,A=1,2,3,4,AB=1,4,故选:D28【解答】解:A=x|2x2,Z为整数集,AZ=2,1,0,1,2,则AZ中元素的个数是5,故选:C29【解答】解:根据题意,集合A=1,2,3,而B=y|y=2x1,xA,则B=1,3,5,则AB=1,3,故选:A二填空题(共3小题)30【解答】解:集合A=1,2,B=a,a2+3AB=1,a=1或a2+3=1,当a=1时,A=1,1,B=1,4,成立;a2+3=1无解综上,a=1故答案为:131【解答】解:集合A=1,2,3,4,集合B=3,4,5,AB=3,4故答案为:3,432【解答】解:集合A=1,2,3,6,B=x|2x3,AB=1,2,故答案为:1,2
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