}
intmain()
{inta[N];
inti;
cout<<"input\t";//\t空格\n换行
for(i=0;icin>>a[i];
sort(a,N);
print(a,N);
return0;}
#include
#defineN4
usingnamespacestd;
intlookup(intx[],intn,inty)
{inti,p=-1;
for(i=0;i{if(x[i]==y){p=i;break;}}
returnp;}
voidmain()
{inti,k,y,n=N;
intx[N];
for(i=0;icin>>x[i];
cin>>y;
k=lookup(x,n,y);//functiondoesnottake1parameters需要重新输入
cout<#include
usingnamespacestd;
classPerson{intage;
public:
Person();
~Person();
voidsetage(intx);
voidsetage2(Persona);
voidshow_age();};
Person:
:
Person(){cout<<"novalue"<Person:
:
~Person(){cout<<"destructor"<voidPerson:
:
setage(intx){age=x;}
voidPerson:
:
show_age(){cout<voidPerson:
:
setage2(Persona){age=a.age;}
intmain(intargc,char*argv[])
{Personm,n,p;
intx;
cin>>x;
m.setage(x);
m.show_age();//析构函数在运行完(下一个重载或者整个函数运行完毕)开始进行析构,若无碍就最后析构
n.setage2(m);//复制构造亦属于构造的一种
n.show_age();
return0;}//结果是
//novalue
//novalue
//1
//1
//destructor
//1
//destructor
//destructor
#include
#defineN7
usingnamespacestd;
voidmain()
{intA[N],k[N],i,j,t,s;
for(i=0;i{cin>>A[i];k[i]=1;}
for(i=0;i{for(j=0;jA[j]){k[i]+=1;
for(t=j+1;tfor(s=0;s}
#include
usingnamespacestd;
voidf(floatx,int*y,float*z)
{*z=x-(int)x
;*y=x;
}
voidmain()
{floatx;inty;
floatz;
cout<<"请输入一个数字:
"<cin>>x;
f(x,&y,&z);
cout<<"整数部分是:
"<cout<<"小数部分是:
"<}
#include
usingnamespacestd;
classPerson{intage;
public:
Person();
~Person();
voidsetage(intx);
voidsetage2(Persona);
voidshow_age();};
Person:
:
Person(){cout<<"novalue"<Person:
:
~Person(){cout<<"destructor"<voidPerson:
:
setage(intx){age=x;}
voidPerson:
:
show_age(){cout<voidPerson:
:
setage2(Persona){age=a.age;}
intmain(intargc,char*argv[])
{Personm,n,p;
intx;
cin>>x;
m.setage(x);
m.show_age();//析构函数在运行完(下一个重载或者整个函数运行完毕)开始进行析构,若无碍就最后析构
n.setage2(m);//复制构造亦属于构造的一种
n.show_age();
return0;}//结果是
//novalue
//novalue
//1
//1
//destructor
//1
//destructor
//destructor
#include
usingnamespacestd;
voidmain()
{
unionexx
{
inta;
charch;
struct
{
intc;
chard;
}s;
}u={20},*p;
p=&u;
u.ch=p->a+77;
u.s.c=p->ch-32;
u.s.d=(*p).ch+32;
cout<<(*p).s.c<<'\t'<<(*p).ch<cout<a<<'\t'<s.d<}//结果(asciiA65a97)
//65A
//65a
#include
usingnamespacestd;
structst{intx;int*y;}*p;
ints[]={5,6,7,8};
sta[]={10,&s[0],20,&s[1],30,&s[2],40,&s[3]};
voidmain()
{p=a;
cout<x<<",";
cout<<(++p)->x<<",";
cout<<*(++p)->y<<",";
cout<<++(*(++p)->y)<}//结果10,20,7,9
#include
#definepi3.141693
usingnamespacestd;
classcirclea
{floats,c;
public:
circlea(floatr)
{s=pi*r*r;
c=pi*r*2;}
friendclasscircleb;
display()
{cout<<"面积是(circlea)"<
};
classcircleb
{public:
display(circleaobj)
{cout<<"周长是(circleb)"<};
voidmain()
{intr;
cout<<"请输入半径:
"<cin>>r;
if(r<0)cout<<"数据有误"<else
{circleaobja(r);
circlebobjb;
obja.display();
objb.display(obja);}
}
#include
usingnamespacestd;
classjiecheng
{intp;
public:
jiecheng(intn)
{if(n<0)cout<<"数据有误"<else
{p=1;//此处若改为intp=1;则出错这是重新定义了新的局部变量
//变量要一至必须只能定义一次
for(inti=1;i<=n;i++)p*=i;
}}
show()
{cout<<"!
"<<"="<
};
voidmain()
{intn;
cout<<"请输入数字:
";
cin>>n;
jiechenga(n);
cout<a.show();//不能改为cout<cout<}
#include
usingnamespacestd;
structper
{inti;
charc;
char*cp;
};
voidfunc(pera)//此处的a只是一个局部变量,不会改变主函数中的值(返回void)
//换为voidfunc(per&a)则为引用,改变值
{a.i=59;a.c='f';a.cp="li";
}
main()
{perq={62,'m',"luo"};
func(q);
cout<}
#include
usingnamespacestd;
unionex
{shortinti;
charch;
};
voidmain()
{exdata;
data.ch='A';
cout<<"data.i="<data.i=0x5566;
cout<<"data.i="<cout<<"data.ch="<data.ch='A';
cout<<"data.ch="<改变了低位。
cout<<"data.i="<}
//结果
//data.i=cc41
//data.i=5566
//data.ch=f
//data.ch=A
//data.i=5541
#include
#include
usingnamespacestd;
classpoint
{floatx,y;
public:
point(floata,floatb)
{x=a;y=b;}
friendclassDistance;
};
classDistance
{floats,l,n;
public:
Distance(pointa,pointb)
{l=a.x-b.x;n=a.y-b.y;
s=sqrt(l*l+n*n);}
display()
{cout<
};
voidmain()
{floata,b,c,d;
cout<<"pleaseputintwopoint"<cout<<"x=";cin>>a;
cout<<"y=";cin>>b;
cout<<"nextpoint"<cout<<"x=";cin>>c;
cout<<"y=";cin>>d;
pointn(c,d),m(a,b);
Distancer(m,n);
cout<<"thedistanceof("<r.display();
}//经验设为友元方可直接访问,但是不太好,别的一定要通过函数