立体几何三视图练习.docx
《立体几何三视图练习.docx》由会员分享,可在线阅读,更多相关《立体几何三视图练习.docx(18页珍藏版)》请在冰豆网上搜索。
![立体几何三视图练习.docx](https://file1.bdocx.com/fileroot1/2022-10/9/77d9a808-d09e-4d07-a3d0-cf0fe43dbf97/77d9a808-d09e-4d07-a3d0-cf0fe43dbf971.gif)
立体几何三视图练习
立体几何三视图练习
课标文数8.G2[2011?
安徽卷]一个空间几何体的三视图如图1,1所示,则该几何体的表面积为()
图1,1
A(48
B(32,817
C(48,817
D(80
课标文数8.G2[2011?
安徽卷]C【解析】由三视图可知本题所给的是一个底面为等腰梯形的放倒的直四棱柱(如图所示),所以该直四棱柱的表面积为
1S,2××(2,4)×4,4×4,2×4,2×1,16×4,48,817.2
课标理数6.G2[2011?
安徽卷]一个空间几何体的三视图如图1,1所示,则该几何体的表面积为()
图1,1
A(48B(32,817
C(48,817D(80
图1,3
课标理数7.G2[2011?
北京卷]某四面体的三视图如图1,3所示,该四面体四个面的面积中最大的是()
A(8
B(62
C(10
D(82
课标理数7.G2[2011?
北京卷]C【解析】由三视图可知,该四面体可以描述为SA?
平面ABC,?
ABC,90?
,且SA,AB,4,BC,3,所以四面体四个面的面积分别为10,8,6,62,从而面积最大为10,故应选C.
图1,4
课标文数5.G2[2011?
北京卷]某四棱锥的三视图如图1,1所示,该四棱锥的表面积是()
图1,1
A(32B(16,162
C(48D(16,322
课标文数5.G2[2011?
北京卷]B【解析】由题意可知,该四棱锥是一个底面边长为4,
1高为2的正四棱锥,所以其表面积为4×4,4××4×22,16,162,故选B.2
课标理数7.G2[2011?
广东卷]如图1,2,某几何体的正视图(主视图)是平行四边形,侧视图(左视图)和俯视图都是矩形,则该几何体的体积为()
regulations,constructionscaffoldingissafeandreliable,andclimbingladders,liftingCommander1established,full-timesafetyofficer1,responsibleforcheckingthesafetyguaranteemeasures,echoedupanddown,preventaccidents.12)trafficpavementinaccordancewithrequirementsofthetransportsector,andseparatedbyclosedisolationbarrier,constructionandnon-constructionwithbarrierisolation.13)volunteerfireorganizations,employeesconductingfirepreventionpublicityandeducationoftheknowledge,skills,andorganizationalimplementationoffire-fightingandemergencyevacuationplansandwalkthroughs.8.4.5specificconstructionprogramforsafetytechnologyaccordingtotheHebeiprovincialconstructionsafetyinspectionrulesfortheimplementationofrequirementsofthestandard,aseparatespecificconstructionprogramforthefollowing1)scaffolderection,dismantlingprogramme;2)Foundationsupportschemes;3)constructionprojectoftemplateengineering;4)"threetreasures","four"protectionscheme;5)constructionorganizationdesignoftemporarypowersupply;6)installation,demolitionofatowercraneprogramme;7)liftingoperationplan.8.58.5.1environmentalmanagementgoalsofenvironmentalprotection,civilizationconstructionwithoutmajorenvironmentalpollutionaccident,wastegas,wastewater,noise,dust,solid
图1,2
A(63B(93
C(123D(1832课标理数7.G2[2011?
广东卷]B【解析】由三视图知该几何体为棱柱,h,2,1,3,S,3×3,所以V,93.底
课标文数9.G2[2011?
广东卷]如图1,2,某几何体的正视图(主视图),侧视图(左视图)和俯视图分别是等边三角形,等腰三角形和菱形,则该几何体体积为()
A(43B(4
C(23D(2
课标文数9.G2[2011?
广东卷]C【解析】由三视图知该几何体为四棱锥,棱锥高h,
122,23,,,3,,3,底面为菱形,对角线长分别为23,2,所以底面积为×23×2,23,2
11所以V,Sh,×23×3,23.33
图1,1
课标理数3.G2[2011?
湖南卷]设图1,1是某几何体的三视图,则该几何体的体积为()
9A.π,122
9B.π,182
C(9π,42
D(36π,18
课标理数3.G2[2011?
湖南卷]B【解析】由三视图可得这个几何体是由上面是一个直径为3的球,下面是一个长、宽都为3、高为2的长方体所构成的几何体,则其体积为:
V
3493,,,V,V,×π×,3×3×2,π,18,12,,322
故选B.
课标文数4.G2[2011?
湖南卷]设图1,1是某几何体的三视图,则该几何体的体积为()
图1,1
A(9π,42B(36π,18
99C.π,12D.π,1822
课标文数4.G2[2011?
湖南卷]D【解析】由三视图可得这个几何体是由上面是一个直径为3的球,下面是一个长、宽都为3高为2的长方体所构成的几何体,则其体积为:
V
4393,,,V,V,×π×,3×3×2,π,18,故选D.12,,322
课标理数6.G2[2011?
课标全国卷]在一个几何体的三视图中,正视图和俯视图如图1,2所示,则相应的侧视图可以为()
图1,2图1,3
课标理数6.G2[2011?
课标全国卷]D【解析】由正视图和俯视图知几何体的直观图是由一个半圆锥和一个三棱锥组合而成的,如下图,故侧视图选D.
regulations,constructionscaffoldingissafeandreliable,andclimbingladders,liftingCommander1established,full-timesafetyofficer1,responsibleforcheckingthesafetyguaranteemeasures,echoedupanddown,preventaccidents.12)trafficpavementinaccordancewithrequirementsofthetransportsector,andseparatedbyclosedisolationbarrier,constructionandnon-constructionwithbarrierisolation.13)volunteerfireorganizations,employeesconductingfirepreventionpublicityandeducationoftheknowledge,skills,andorganizationalimplementationoffire-fightingandemergencyevacuationplansandwalkthroughs.8.4.5specificconstructionprogramforsafetytechnologyaccordingtotheHebeiprovincialconstructionsafetyinspectionrulesfortheimplementationofrequirementsofthestandard,aseparatespecificconstructionprogramforthefollowing1)scaffolderection,dismantlingprogramme;2)Foundationsupportschemes;3)constructionprojectoftemplateengineering;4)"threetreasures","four"protectionscheme;5)constructionorganizationdesignoftemporarypowersupply;6)installation,demolitionofatowercraneprogramme;7)liftingoperationplan.8.58.5.1environmentalmanagementgoalsofenvironmentalprotection,civilizationconstructionwithoutmajorenvironmentalpollutionaccident,wastegas,wastewater,noise,dust,solid
图1,5
课标理数15.G2[2011?
辽宁卷]一个正三棱柱的侧棱长和底面边长相等,体积为23,
5所示,左视图是一个矩形,则这个矩形的面积是________(它的三视图中的俯视图如图1
课标理数15.G2[2011?
辽宁卷]23【解析】由俯视图知该正三棱柱的直观图为图1,6,其中M,N是中点,矩形MNCC为左视图(1
12由于体积为23,所以设棱长为a,则×a×sin60?
×a,23,解得a,2.所以CM,3,2
故矩形MNCC面积为23.1
图1,6
图1,3
课标文数8.G2[2011?
辽宁卷]一个正三棱柱的侧棱长和底面边长相等,体积为23,它的三视图中的俯视图如图1,3所示,左视图是一个矩形,则这个矩形的面积是()
A(4B(23C(2D.3
课标文数8.G2[2011?
辽宁卷]B【解析】由俯视图知该正三棱柱的直观图为下图,其中M,N是中点,矩形MNCC为左视图(1
图1,4
12由于体积为23,所以设棱长为a,则×a×sin6