三年级数学第一学期复习提纲docx.docx

三年级数学第一学期复习提纲docx.docx

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三年级数学第一学期复习提纲docx

三年级数学第一学期复习提纲

Syllabusforthefirstsemesterofgradethreemathematics

Unit1

1,recursiveequationisclever

Addbrackets:

thefrontisplussign,followedbyparentheses,constantnumber・

Thefrontisaminussign,followedbybrackets,youwanttochange.

Shiftposition:

thesignmovesalongwiththenumbersbehind.

2,formaximumdifference,minimumdifference

Thebiggestdifference:

（1）tocreateamaximumnumber

（2）tocreateaminimum（3）verticalsubtraction

Theminimumdifference:

（1）tocreateaminimumoftwodigitsontheminuendaftertwo

（2）tocreatemaximumtwodigitsintwoaftermeiosis

（3）therestoftheadjacentselectnumberoflargeputhundredsofsmallminuend,puthundredsofbits（4）verticalsubtraction

3,subtractiontower

（1）tocreatethelargestandsmallestnumberswiththreecardnumber,verticalsubtraction

（2）thedifferencebetweentheobtaineddifferenceandthearithmeticnumberisthesame,andtheendofthesubtractiontowerisnotthesame,thenrepeatthenumber

（1）withthedifferencenumberuntilthesame・

Secondunit

1,theentire100,themultiplicationanddivisiondecamerous

2,Divisionistheinverseoperationofmultiplication

3,theapplicationshouldbeinanumberofconditions,accordingtotheproblemtochooseusefulconditions,andthencolumncalculations

4,asingledigitmultipliedbytwodigits,threedigits

Aandspinoffcalculation

（1）twodigits:

twodigitssplitTENS（ten）andanumber（afew）,andonedigitaremultipliedbytwo

（2）productisthesumofthreedigits:

threedigitssplitintoawholehundred（severalhundred）,ten（ten）andanumberof（afew）,andonedigitaremultipliedbythreeisthesumofproduct

B,verticalcalculation

（1）werewrittenbydigitalalignment

（2）morethanthetopfactor（3）metattheendofzero,adigitalalignmentfactorandzerofront（4）fromadate,followedbyanumbermultipliedbyeachdigitnumber（5）thatcarry

Candestimation

（1）findtwofactoradjacenttotheentireten

（2）areadjacenttotheentiretenmultipliedbyafactor（3）thescopeoftheresultisestimated

5,twodigit,threedigit,exceptbyonedigit

A,dividend,divisor二businessRemainder

Bandspinoffcalculation

Twodigits:

twodigitsaccordingtothedivisor,willbesplitintomultiplesofthewholedivisorandtheresidualnumberten,respectivelydividedbythevalueofthetwo,takingthesumof

Threedigit:

accordingtothedividend,willsplitintothreedigitwholehundreddivisormultiples,thentherestofthedigitalsplitintomultiplesoftheentiredivisorandtheresidualnumberten,respectively,threedividedbythenumberofdivisors,thethreeoperatorstogether

Ifthewholehundredcannotbesplitintodivisormultiples,thendirectlysplitintomultiplesoftheentiredivisorandtheresidualnumberten

C,theverticalcalculation（business,multiplication,subtraction,fall）

（1）fromthehighestpointofthedivisor,dividing

（2）towhichofthedivisorsistobelisted

（3）thequotient1isoccupiedby0（4）,andtheremainderissmallerthanthedivisor

（5）check:

quotient*divisor+remainder二divisor（6）,payattentiontotheendofdivisorandzerointhemiddle

D（estimationofquotientrange）

Tofindthedivisorisclosesttothetwowholeten,andthetwonumbersaremultiplesofthedivisor・

Thendividethetwonumbersbythedivisor,andthetwoquotientistheestimateinthisformula

Or,tofindthanthedivisorissmall,andthewholeisthedivisormultiplesoften,thenumberisdividedbyadivisor,thebusinessscopeissmallandthenumber,thenumberrangeinbigplus10.

Thirdunit

1,thepronunciationofthedecimalpoint

Thepartoftheintegerisreadbytheoriginalnumber・Thedecimalpartafterthedecimalpointistoreadoutthenumbersoneachbitinturn（notethezeropronunciation）andrefertothebook〃p34〃

2yuancents

（1）theintegerpartrepresentsafewdollars,thefirstbitafterthedecimalpointrepresentsseveralangles,andthesecondbitafterthedecimalpointindicatesafraction

（2）showafewdollarsandafewcentsindecimalform（3）,1yuan=10angle,1jiao=10,1yuan二100cents

3.Thedecimalrepresentationofkilogramandgram

（1）1kg=1000grams,theintegerpartrepresentskg,thefirstpartofthedecimalmeanshundredsofgrams,thesecondrepresentsafewgrams,andthethirdrepresentsafewgrams

（2）case

1.584kg二（）Gfirstthinklkg584g,thinklkg=1000g,then1000+584二1584,so1.584kg=1584g

0.070kg二（）gwantsseconddecimalplacesafterthedecimalpoint,andthereisnonumberintheintegerpart,so

0.070kg=70g

3500g二（）kgfirstdivides3500into3000gand500g,andthen3000萨3kgwrites500gontheleftofthedecimalpoint,andlkgwritesthedecimalpointtotheright,so3500萨3・500kg

4.Thedecimalrepresentationofkilometerandmetre

1km二1000meters（conversionmethodwithkg/gramconversion）

5,tosolvedifferentroutes

Observeseveralroutesfromthebeginningtothepoint,thenobservehowmanyroutesfromthispointtothefinishline,andthengooutofthedifferentroutesinturn・Calculatetheshortestdistance・

Adecimalrepresentationof6metersandcentimeters

（1）lm=100cm

（2）theintegerpartexpressedseveralm,expresseddissatisfactionwiththedecimalnumberlm,name1yumptyumpthcm,decimalpointrightfirstsaiddozensofCM,secondbitdecimalpointrightsaidseveralcm

（3）example:

3.67m=（）cmintegerpart3represents3M,3m=300cm,anddecimalpartrepresents67cm300+67二367cm,so3.67m二367cm

0.8m二（）cmfirstlookattheintegerpartof0,lessthanlm,thedecimalpartof8writtenatthedecimalpointafterthefirst,indicating80cm,secondonthe0omittedtowrite,so0.8m=80cm

5cm二（）mwantsseveralcmtowriteseconddecimalplaces,andotherplaceswrite0placeholder,so5cm二0.05m7unitsoflength

（1）aunitoflengthbetweentheinletratepleasereferencebooksp42greenbox

（2）DM1dm二10cm・

&date

（1）12monthsayear（leftfistmemory）

Thebig7,31days（January,March,May,July,August,October,December）

Ihave430days（April,June,September,November）

Februaryisnotlargenorthemoon,isaspecialmonth,thereare28days,29daysinaleapyear

Thereare365days,366daysinaleapyear

（2）judgmentoftheyearof"PingandJirT;

Fouryearsaleap,ahundredyearsdoesnotrun,fourhundredyearsandintercalated・

Theyeardividedby4,theremainderisnotaleapyearyeardividedby4,theremainderisaleapyear

Whenistheentire100toyear,dividedby400,theremainderisnotaleapyear,thereisaremainder

（1600,2000,2400）isaleapyear

（2）7daysaweekthereare52weeksayearofmorethan1years

52weeksayearmorethan2days

（3）firsthalf,secondhalf,quarter,etc・

Fourthunit

1,triangle

（1）thetriangleisdividedintoequilateraltriangle,isoscelestriangleandequilateraltrianglebytheedge・

（2）atrianglewithtwoequalsidesiscalledisoscelestriangle・

Atrianglewhosethreesidesareequaliscalledanequilateraltriangle,alsocalledaequilateraltriangle・

（3）isoscelestriangleincludingequilateraltriangle・Anequilateraltrianglemustbeanisoscelestriangle・Anisoscelestriangleisnotnecessarilyanequilateraltriangle

（4）isoscelestrianglehasasymmetricalaxis・Anequilateraltrianglehasthreesymmetricalaxes.

2,area

3.Thesizeofaplaneiscalledarea

4.Theareaofarectangularsquare

（1）thelengthofthesquareislcm,theareais1square

centimeters,andthewritingislcm2

（2）rectangulararea二length*width;

Slong二a*B

（3）squarearea二sidelength*sidelength

Sis=3*a

（notethattheareaiscm2,andM2isnotaunitoflength・）

5squaremeters

Thelengthofthesquareislm,theareais1squaremeters,andthewritingis1m2

Inlife,largerobjectsaresquaremeters

Fifthunit

Exercise1,multiplicationanddivisioncalculation

2,accordingtothedivisionformula,comparethesize

（1）thedivisorisequalandthedivisorislarge;thequotientissmall

（2）thedivisorisequalandthequotientislargewhenthedivisorisequal

（3）thedividendanddivisorarenotthesame,calculatethesize

3,afewtimesafewtimesDuojijiproblems（citylightsbeforetwoP60-61）

（1）willbejudgedaccordingtothelinegraph

Note:

whatisonthelinegraph?

Isitasolidlineoradashedline?

（2）firstfindamultiple,thenmultiplyitseveraltimes,plusmore（orless）numbers

（3）ifyouusestep-by-stepcalculation,youcanwritetheanswerdirectly

Ifthecolumnsynthesisalgorithmiswrittenintheformofarecursiveequation

4times,andthebadtimes,theproblem（aftertwop61~62lights）

Distinguishbetween1multiplesormultiples,severaltimesafterthesummation,and1multiplesaddorsubtract

Thetwomethod,thefirstiscalculatedaccordingtothecondition,andthenthetwopartisadded（orsubtracted）

Thesecondfirstcalculatesthesumoftheparts（orthediffereneeinthenumberofcopies）,andthenmultipliesthenumberofeach

（1）takebookp61/3asanexampleandtwomethods

First,askforthenumberoflotusbulbs,andthenaddthenumberoftherabbitlightstogetafew

Makeasyntheticformula25*3+25

Methodtwotakerabbitlampas1parts,lotuslampassuch3,total1+3=4

Multiplyagain,eachoneisthe25light

Makeasyntheticequation（1+3）*25notethatparenthesesdon，tleak

（2）takebookp62/4asanexampleandtwomethods

First,countthenumberofsphericalbulbs,thensubtractthenumberofthelampoftherabbit，slamp,andgetafewmore

Makeasyntheticformulaof25*4-25

Methodtwotaketherabbitlightas1parts,andthesphericallampisconsideredas4ofthese,intotal4-1=3

Multiplyagain,eachone