AMC12B试题及解答Word文档下载推荐.docx

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AMC12B试题及解答Word文档下载推荐.docx

dragonfly

 

Sincetheharmonicmeanis

Jtimestheirproductdividedbytheirsum,wegettheequation

2x1x2016

1+2016

whichisthen

4032

(A)2

2017

whichisfinallyclosestto

Problem3

LetX-—2016.WhatisthevalueofIM—力I一I刎—兽?

Firstofall,letspluginallofthe©

sintotheequation.

||-2016|一(-2016)1一|-20161-(-2016)

Thenwesimplifytoget

|2016+20161-20161^2016

whichsimplifiesinto

2016+2016

(D)4032

andfinallyweget

Problem4

Theratioofthemeasuresoftwoacuteanglesis5:

1,andthecomplement

ofoneofthesetwoanglesistwiceaslargeasthecomplementoftheother.Whatisthesumofthedegreemeasuresofthetwoangles?

(A)75(B)90(C)135(D)150(E)270

Wesetupequationstofindeachangle.Thelargeranglewillbe

representedasxandthelargeranglewillwerepresentedas/indegrees.

Thisimpliesthat

4x=5y

and

2x(90—j:

)=90—y

(C)135

sincethelargertheoriginalangle,thesmallerthecomplement.

Wethenfindthat「一.£

and彳—沉丄,andtheirsumis

Problem5

TheWarof1S12startedwithadeclarationofwaronThursday,

June1812.Thepeacetreatytoendthewarwassigned019dayslater,

onDecember24,1814.Onwhatdayoftheweekwasthetreatysigned?

Tofindwhatdayoftheweekitisin919days,wehavetodivide919by7toseetheremainder,andthenaddtheremaindertothecurrentday.Weget

919

that7hasaremainderof2,soweincreasethecurrentdayby2to

(B)SatiLrday

get———I

Problem6

AllthreeverticesofAAJ3Clieontheparaboladefinedby9=T,withAattheoriginandBCparalleltothe工-axis.Theareaofthetriangle

is64.WhatisthelengthofDC?

(A)4(B)6(C)8(D)10(E)16

Albert471

Plottingpoints门and:

onthegraphshowsthattheyareat(—上、止)and■,r”),whichisisosceles.Bysettingupthetrianglearea

Makingx=4,andthelength

(c)s

64=—*2t*rr2=G4formulayouget:

2ofDCissotheansweris

Problem7

Joshwritesthenumbers1’2,3,・•・、99,100.Hemarksout1,skipsthenextnumber

(2),marksout3,andcontinuesskippingandmarkingoutthenextnumbertotheendofthelist.Thenhegoesbacktothestartofhislist,

marksoutthefirstremainingnumber⑵,skipsthenextnumber⑴,marks

out6,skips8,marksout10,andsoontotheend.Joshcontinuesinthis

(D)64

manneruntilonlyonenumberremains.Whatisthatnumber?

(A)13(B)32(C)56(D)64

ByAlbert471

Followingthepattern,youarecrossingout...

(E)96

Time1:

Everynon-multipleof

Time2:

4

Time3:

8

Followingthispattern,youareleftwitheverymultipleofG4whichis

only

Problem8

Athinpieceofwoodofuniformdensityintheshapeofanequilateral

trianglewithsidelength3inchesweighs12ounces.Asecondpieceofthesametypeofwood,withthesamethickness,alsointheshapeofanequilateraltriangle,hassidelengthof5inches.Whichofthefollowingis

closesttotheweight,inounces,ofthesecondpiece?

(A)14,0(B)1G.0(C)20.0(D)33.3(E)55.6

Wecansolvethisproblembyusingsimilartriangles,sincetwoequilateral

trianglesarealwayssimilar.Wecanthenuse

100

whichisclosest

Anotherapproachtothisproblem,verysimilartothepreviousonebutperhapsexplainedmorethoroughly,istouseproportions.First,sincethe

thicknessanddensityarethesame,wecansetupaproportionbasedontheprinciplethatV,thusdV=m.

However,sincedensityandthicknessarethesame

25

"

and^4ocb3(recognizingthattheareaofanequilateraltriangleiswecansaythatm<

x涉.

5

Then,byincreasingsbyafactorof3,s2isincreasedbyafactorof

(D)333

TH—12#■—

thus9or

Problem9

Carldecidedtofenceinhisrectangulargarden.Hebought20fenceposts,

placedoneoneachofthefourcorners,andspacedouttherestevenlyalongtheedgesofthegarden,leavingexactly4yardsbetween

neighboringposts.Thelongersideofhisgarden,includingthecorners,hastwiceasmanypostsastheshorterside,includingthecorners.Whatisthearea,insquareyards,ofCarl'

sgarden?

(A)256(B)336(C)384(D)448(E)512

Tostart,usealgebratodeterminethenumberofpostsoneachside.Youhave(thelongsidescountfor2becausetherearetwiceasmany)Gx=20+4(eachcornerisdoublecountedsoyoumustadd4)

Makingtheshorterendhave1,andthelongerend

have8.((8一1)7"

((4-1)木1)=28.12=336.Therefore,the

(B)336

answeris

Problem10

AquadrilateralhasverticesP(a、b),and人一"

),

whereaandbareintegerswithd>

b>

0.TheareaofPQRSis16.What

is«

+b?

Bydistaneeformulawehave'

'

■1'

■'

1'

■1■'

I■?

■■

SImplifyingweget—^)(a+b)=8.ThusU+ftanda—bhavetobea

■-andremainintegersis

factorof8.Theonlywayforthemtobefactorsof

if:

I;

:

and:

丄Sotheansweris

Solutionbyl_Dont_Do_Math

Solution2

Solutionbye_power_pi_times_i

BytheShoelaceTheorem,theareaofthequadrilateralis2ti2—2b'

soa2—b2—8.Sineeaand&

areintegers,u=3andb=1,

a+b=(A)4I

so.

Problem11

Howmanysquareswhosesidesareparalleltotheaxesandwhoseverticeshavecoordinatesthatareintegerslieentirelywithintheregionboundedbytheline站=齐工,theline~_0.1andtheline龙=5.1?

(A)30(B)41(C)45(D)50(E)57

(Note:

diagramisneeded)

Ifwedrawapictureshowingthetriangle,weseethatitwouldbeeasiertocountthesquaresverticallyandnothorizontally.Theupperbound

is1Gsquares(卩=5」木汗),andthelimitforthe工-valueis5squares.First

wecountthe1*1squares.Inthebackrow,thereare12squareswithlength1becausey=4床ugeneratessquaresfrom@,0)to(蠶仆),andcontinuingonwehave9,6,and3for©

valuesfor1,2,and3intheequationV—兀卫.Sothereare12+9+6+3=30squareswithlengthIinthefigure.For_一’squares,eachsquaretakesup_unleftand2unup.Squarescanalsooverlap.For2*2squares,thebackrow

stretchesfrom(N°

〉to('

*'

兀),sothereare8squareswithlength2ina2by0box.Repeatingtheprocess,thenextrowstretchesfrom(2,0)

to(2,2打)

sothereare5squares.Continuingandaddingupin

theend,thereare

&

”■:

乞一、:

:

squareswithlength-inthefigure.

Squareswithlength3inthebackrowstartatandendat(2*277),so

thereare4suchsquaresinthebackrow.Asthefrontrowstarts

at(10andendsat(1"

)thereare

I1squareswithlength■■.As

squareswithlengthJwouldnotfitinthetriangle,theanswer

is;

I丨whichis

D)5()

Problem12

Allthenumbers1,N3,4,5,6,7*&

0arewrittenina3x3arrayofsquares,

onenumberineachsquare,insuchawaythatiftwonumbersare

consecutivethentheyoccupysquaresthatshareanedge.Thenumbersinthefourcornersaddupto18.Whatisthenumberinthecenter?

(A)5(B)6(C)7(D)8(E)9

SolutionbyMlux:

Drawa3x3matrix.Noticethatnoadjacentnumbers

couldbeinthecornerssincetwoconsecutivenumbersmustsharean

edge.Nowfind4nonconsecutivenumbersthataddupto18.

Trying1+3+5+9—18works.Placeeachoddnumberinthecornerin

aclockwiseorder.Thenfillinthespaces.Therehastobea2inbetween

the1and3.Thereisa4between3and5.Thefinalgridshouldsimilartothis.

1,2.3

8,7A

9.6,5

(C)7

isinthemiddle.

Ifwecolorthesquarelikeachessboard,sincethenumbersaltrenatebetweenevenandodd,andtherearefiveoddnumbersandfourevennumbers,theoddnumbersmustbeinthecorners/center,whiletheevennumbersmustbeontheedges.Sincetheoddnumbersaddupto25,andthenumbersinthecornersaddupto18,thenumberinthecentermustbe25-18=7

Problem13

AliceandBoblive10milesapart.OnedayAlicelooksduenorthfromherhouseandseesanairplane.AtthesametimeBoblooksduewestfromhishouseandseesthesameairplane.Theangleofelevationoftheairplaneis30nfromAlice'

spositionand60^fromBob'

sposition.Whichofthefollowingisclosesttotheairplane'

saltitude,inmiles?

(A)3.5(B)4(C)4*5(D)5(E)5.5

Let'

ssetthealtitude=z,distaneefromAlicetoairplane'

sgroundposition(pointrightbelowairplane)二yanddistaneefromBobtoairplane'

sground

position=x

FromAlice'

spointofview,

y.cos30品

cos

tan(0)=-GO=S1D男=亞工二㊁

FromBob'

T.CUSGO.So,VO

'

、'

l■'

=about5.5.

Weknowthat*+/=丄°

°

Solvingtheequation(byplugginginxandy),wegetz=

So,answeris

solutionbysudeepnarala

Non-trigsolutionbye_power_pi_times_i

SetthedistaneefromAlice'

sandBob'

spositiontothepointdirectlybelowtheairplanetobexand甘,respectively.FromthePythagorean

3or.Solvingthe

Theorem,◎?

+『=100.Asbothare30—60—90triangles,thealtitudeoftheairplanecanbeexpressedas

eq

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